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General Principles of Isolation of Elements

General Principles of Isolation of ElementsNEET Chemistry · Class 12 · NCERT Chapter 15

Ores and Minerals

The Earth's crust contains many elements, but almost all of them occur as compounds (oxides, sulphides, carbonates, silicates, halides) rather than as free metals. Only a few metals like gold and platinum are found in the free (native) state.

Mineral vs Ore

A mineral is any naturally occurring compound of a metal in the Earth's crust. An ore is a mineral from which a metal can be extracted economically and profitably. The key word is "economically."

Example: Aluminium has two common minerals, bauxite (Al₂O₃.2H₂O) and corundum (Al₂O₃). Bauxite is the ore because it has a high enough Al content and is easy enough to process to be profitable. Corundum is too hard and dense to be processed economically. So bauxite is an ore; corundum is just a mineral.

All ores are minerals, but not all minerals are ores.

Gangue (Matrix)

The unwanted rocky material mixed with an ore in the Earth is called gangue (or matrix). Before extracting the metal, you must first remove the gangue from the ore. This step is called concentration (or beneficiation or dressing of ore).

Important Ores Table

MetalOre NameFormulaOre Type
Iron (Fe)HaematiteFe₂O₃Oxide
Iron (Fe)MagnetiteFe₃O₄Oxide
Iron (Fe)LimoniteFe₂O₃.3H₂OHydrated oxide
Iron (Fe)SideriteFeCO₃Carbonate
Aluminium (Al)BauxiteAl₂O₃.2H₂OHydrated oxide
Aluminium (Al)CorundumAl₂O₃Oxide
Copper (Cu)Copper pyritesCuFeS₂Sulphide
Copper (Cu)CupriteCu₂OOxide
Copper (Cu)MalachiteCuCO₃.Cu(OH)₂Carbonate
Zinc (Zn)Zinc blende / SphaleriteZnSSulphide
Zinc (Zn)ZinciteZnOOxide
Zinc (Zn)CalamineZnCO₃Carbonate
Lead (Pb)GalenaPbSSulphide
Silver (Ag)ArgentiteAg₂SSulphide
Sodium (Na)Rock saltNaClHalide
Sodium (Na)Chile saltpetreNaNO₃Nitrate
Tin (Sn)Cassiterite (Tinstone)SnO₂Oxide
Mercury (Hg)CinnabarHgSSulphide

NEET tip: NEET frequently asks you to identify the ore of a metal or to match an ore with its type. Commit this table to memory. The sulphide ores and oxide ores are most commonly tested.

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Concentration of Ores

Before you can extract the metal, you must increase the proportion of ore mineral and remove the gangue. This is called concentration (also called beneficiation or ore dressing). There are four main methods.

1. Gravity Separation (Hydraulic Washing)

This method works when the ore particles are denser than the gangue. A stream of water washes over the crushed ore on a vibrating platform. The lighter gangue particles are carried away by the water; the heavier ore particles remain behind. Used for cassiterite (SnO₂, tinstone), which is denser than its silicate gangue.

2. Magnetic Separation

Used when the ore or the gangue is magnetic. The crushed ore mixture is fed onto a belt running over an electromagnetic drum. Magnetic particles are attracted and held; non-magnetic particles fall off.

  • Magnetic ore, non-magnetic gangue: e.g. magnetite (Fe₃O₄) and chromite (FeCr₂O₄) are separated from silicate gangue.
  • Non-magnetic ore, magnetic gangue: e.g. cassiterite (SnO₂, non-magnetic) is separated from wolframite (FeWO₄, magnetic). The wolframite sticks to the drum; the cassiterite falls off.

3. Froth Flotation

Used for sulphide ores (e.g. PbS, ZnS, CuFeS₂). The method exploits the difference in the ability of ore and gangue particles to be wetted by water (hydrophobicity vs hydrophilicity).

How it works:

  1. Finely crushed ore is added to water in a large flotation tank. Pine oil (or cresol) is added as the frother to create stable froth.
  2. Collectors like sodium ethyl xanthate (NaC₂H₅OCS₂) are added. These preferentially coat the sulphide ore particles and make them hydrophobic (water-repelling).
  3. Air is blown through the mixture. The hydrophobic ore particles attach to the air bubbles and rise to the surface with the froth.
  4. The silica/silicate gangue is hydrophilic (water-loving) and remains in the water (sinks).
  5. The froth carrying the ore is skimmed off and the ore is recovered.

Depressants in Froth Flotation

When two sulphide ores are mixed (e.g. ZnS and PbS together), you can separate them selectively by adding a depressant:

  • NaCN (sodium cyanide) acts as a depressant for ZnS. CN⁻ ions form a complex with Zn²⁺ on the ZnS surface ([Zn(CN)₄]²⁻), making ZnS hydrophilic so it sinks. PbS remains hydrophobic and floats, allowing separation.

4. Leaching (Chemical Method)

The ore is dissolved in a suitable chemical solvent, leaving the gangue behind. The metal is then recovered from the solution.

  • Aluminium (Bayer process): Bauxite (Al₂O₃.2H₂O) is dissolved in hot concentrated NaOH solution. Al₂O₃ dissolves as sodium aluminate: Al₂O₃ + 2NaOH → 2NaAlO₂ + H₂O. The impurities (Fe₂O₃, SiO₂) do not dissolve. The solution is then diluted and Al(OH)₃ precipitates, which is calcined to give pure Al₂O₃.
  • Silver and Gold: The ore is treated with dilute NaCN solution in the presence of air (O₂). Ag and Au dissolve as complex anions: 4Ag + 8NaCN + 2H₂O + O₂ → 4Na[Ag(CN)₂] + 4NaOH. The metal is then recovered by displacement with a more reactive metal: 2Na[Ag(CN)₂] + Zn → Na₂[Zn(CN)₄] + 2Ag.
Ore Concentration

Metallurgy Flow Builder

Select a metal to see its complete extraction pathway from ore to pure metal. Click any step to read a detailed explanation.

Ore

Starting Ore

Copper pyrites (CuFeS₂)

Concentration

Concentration

Froth Flotation

Pre-treatment

Pre-treatment (Partial Roasting)

Matte Formation: Cu₂S + FeS

Reduction

Smelting + Flux

Remove FeS as slag (FeSiO₃)

Reduction

Reduction (Auto-reduction)

Blister Copper (98–99% Cu)

Refining

Refining

Electrolytic Refining

Product

Pure Product

Copper 99.99% (Cu)

Ore

Concentration

Pre-treatment

Reduction

Refining

Product

Tap any step to expand its explanation.

Thermodynamic Principles of Metallurgy

Once the ore is concentrated, you need to extract the metal from the metal compound (oxide, sulphide, or carbonate). The key question is: which reductant should you use and at what temperature?

Thermodynamics gives the answer through the concept of Gibbs free energy (ΔG). A reaction is spontaneous if ΔG is negative. The Ellingham diagram is a visual tool that makes this easy.

The Ellingham Diagram

The Ellingham diagram plots the standard Gibbs free energy of formation (ΔfG°) of metal oxides against temperature. Each metal oxide has its own line.

Key rules for reading the Ellingham diagram

  1. Lower line = more stable oxide. A metal oxide with a more negative ΔfG° (lower on the diagram) is more thermodynamically stable. The metal has a stronger affinity for oxygen.
  2. Slope of lines: Most metal oxide lines go upward (positive slope) with increasing temperature. This is because the reaction M + O₂ → MO₂ involves a decrease in entropy (solid + gas → solid), so ΔS is negative. As T increases, −TΔS becomes more positive, making ΔG less negative (less stable).
  3. Changes in slope: At the melting point or boiling point of the metal, the slope changes because the entropy of the metal changes. This appears as a kink in the line.
  4. Using the diagram for reduction: If you want to reduce metal oxide B using metal A, the reaction A + BOₓ → AOₓ + B is spontaneous when the line for A (i.e. for A + O₂ → AOₓ) lies below the line for B at that temperature.

Carbon as a Reductant (Why Coke is So Useful)

Carbon has two oxidation reactions with oxygen:

  • C + O₂ → CO₂: The line is nearly horizontal (ΔS ≈ 0 because equal moles of gas on both sides).
  • 2C + O₂ → 2CO: The line has a steep negative slope (ΔG becomes more negative with increasing temperature). This is because 1 mol of gas (O₂) produces 2 mol of gas (CO), so ΔS is large and positive. At high temperature, −TΔS dominates and ΔG becomes very negative.

Because the C→CO line has a negative slope, it crosses below the lines of many metal oxides at high temperatures. Above the crossover temperature, carbon can reduce that metal oxide. This is why coke is used in blast furnaces and retort furnaces.

Important Crossover Temperatures

Metal OxideCrossover Temperature (approx.)Can Carbon Reduce It?
Fe₂O₃~700°CYes: carbon reduction used in blast furnace
ZnO~950°CYes: coke used in retort furnace, then distillation
SnO₂~700°CYes
Al₂O₃Never (C line never crosses)No: use electrolysis (Hall-Heroult)
MgONever at practical temperatureNo: use electrolysis of MgCl₂
CaONever at practical temperatureNo

Key NEET point: The most common Ellingham question asks why coke cannot reduce Al₂O₃ or MgO. The answer is that the Al₂O₃ and MgO lines lie below the C→CO line at all practical temperatures, meaning those oxides are more stable than CO. There is no temperature at which the reduction would be spontaneous.

Thermit Reaction (Aluminothermy)

Aluminium can reduce certain metal oxides because the Al₂O₃ line lies below those metal oxide lines in the Ellingham diagram. The reaction with Fe₂O₃ is called the thermit reaction:

2Al + Fe₂O₃ → Al₂O₃ + 2Fe (ΔH ≈ −848 kJ/mol)

This is highly exothermic and produces temperatures around 2500°C, melting the iron produced. It is used in thermit welding for rail tracks and pipelines (no electricity needed, compact, portable).

Thermodynamics of Metallurgy

Ellingham Diagram Explorer

Click any line to see which metals carbon can reduce, at what temperature, and why. Lower = more stable oxide = harder to extract.

Y-axis: ΔfG° (kJ/mol O₂), lower means more stable oxide

|

X-axis: Temperature (0 → 2000°C, left → right)

0°C

500°C

1000°C

1500°C

2000°C

Less stable

More stable

CO₂
CO
CuO
ZnO
Fe₂O₃
Al₂O₃
MgO

CO₂

CO

CuO

ZnO

Fe₂O₃

Al₂O₃

MgO

2C + O₂ → 2CO

Can carbon reduce this oxide?

No

Carbon crosses at

N/A: this IS the key carbon line

Extraction method

This line determines what carbon can reduce

NEET explanation

Strong negative slope because 1 mol gas → 2 mol gas, so ΔS is large and positive. At high T, this line crosses below metal oxide lines, enabling carbon reduction.

Key line for assessing carbon reduction feasibility

Key rules for NEET

  • Lower line in diagram = more stable oxide = harder to extract the metal
  • C→CO line has a negative slope (entropy increases: 1 mol gas → 2 mol gas)
  • C→CO₂ line is nearly horizontal (ΔS ≈ 0: 1 mol gas → 1 mol gas)
  • Where C→CO crosses below a metal oxide line = carbon can reduce that oxide at that T
  • Al₂O₃ and MgO lines are always BELOW C→CO: must use electrolysis
  • Al₂O₃ line is below Fe₂O₃ line: Al reduces Fe₂O₃ (thermit reaction)

Extraction by Reduction

After concentration and conversion to the oxide (by roasting or calcination), the next step is to reduce the metal oxide to the free metal. There are three main routes.

Pre-Treatment: Roasting vs Calcination

MethodOre TypeConditionsWhat HappensExample
RoastingSulphideHigh temp, excess air (O₂)Sulphide → Oxide + SO₂2ZnS + 3O₂ → 2ZnO + 2SO₂
CalcinationCarbonate / HydroxideHigh temp, limited airCarbonate decomposes → Oxide + CO₂ZnCO₃ → ZnO + CO₂

1. Pyrometallurgy (Smelting)

The oxide ore is heated with a reducing agent (coke, CO, or H₂) at high temperature. The reducing agent removes oxygen from the metal oxide, leaving the free metal.

Carbon (coke) reduction: Most common. Used for Fe, Zn, Sn, Pb.

  • ZnO + C → Zn + CO (above 950°C)
  • Fe₂O₃ + 3CO → 2Fe + 3CO₂ (in blast furnace, CO is the actual reductant)

Flux and Slag: A flux is a substance added to the furnace to remove gangue as a liquid slag. The flux reacts with the acidic or basic gangue to form a fusible slag, which floats on the molten metal and can be tapped off separately.

  • Acidic gangue (SiO₂) requires a basic flux (CaO, limestone): CaO + SiO₂ → CaSiO₃ (slag)
  • Basic gangue requires an acidic flux (SiO₂)

2. Hydrometallurgy (Leaching + Displacement)

The ore is leached with a chemical solvent to form a solution of the metal ion. The metal is then recovered by displacement with a more reactive metal or by electrolysis.

Silver recovery from NaCN leach solution: 2Na[Ag(CN)₂] + Zn → Na₂[Zn(CN)₄] + 2Ag

This route avoids high temperatures and is used for noble metals (Ag, Au) and some oxide ores. It is also more environmentally compatible for some ores.

3. Auto-Reduction (Self-Reduction)

Some metals (mainly copper) can be reduced without an external reductant. When the sulphide ore is heated, the sulphide and oxide react with each other to produce the metal:

Cu₂S + 2Cu₂O → 6Cu + SO₂

This happens in the converter during copper smelting. No coke is added; the matte itself acts as the reductant.

Blast Furnace (Iron Extraction)

The blast furnace is a large steel vessel lined with fire-brick. Layers of haematite ore, coke, and limestone are added from the top. Hot air is blasted in at the bottom.

Zone (Temperature)ReactionWhat forms
Bottom (1500–1600°C)C + O₂ → CO₂; CO₂ + C → 2COCO (the main reductant)
Middle (900–1200°C)3Fe₂O₃ + CO → 2Fe₃O₄ + CO₂; Fe₃O₄ + CO → 3FeO + CO₂; FeO + CO → Fe + CO₂Molten iron (pig iron)
Upper (400–700°C)CaCO₃ → CaO + CO₂; CaO + SiO₂ → CaSiO₃ (slag)Slag (floats over iron)

Pig iron (cast iron) contains about 4% carbon and is brittle. Removing carbon gives wrought iron (pure Fe, very ductile). Controlled carbon gives steel (0.1–1.5% C, strong and workable).

Electrolytic Reduction

Highly reactive metals (those near the top of the electrochemical series: Al, Mg, Na, K, Ca) have very stable oxides. Their Ellingham lines lie far below the C→CO line, so carbon reduction is not thermodynamically feasible. You must use electrolysis to provide the energy needed.

Hall-Heroult Process (Aluminium)

Aluminium is the most abundant metal in Earth's crust, but it cannot be extracted by carbon reduction because Al₂O₃ is too stable.

Step 1: Bayer Process (Concentration by Leaching)

  1. Bauxite (Al₂O₃.2H₂O) + hot concentrated NaOH → sodium aluminate solution: Al₂O₃ + 2NaOH + 3H₂O → 2Na[Al(OH)₄]
  2. Fe₂O₃ and SiO₂ gangue do not dissolve and are filtered off ("red mud").
  3. The sodium aluminate solution is diluted and seeded with Al(OH)₃ crystals. Al(OH)₃ precipitates: Na[Al(OH)₄] → Al(OH)₃ + NaOH
  4. Al(OH)₃ is calcined (heated at 1200°C) to give pure Al₂O₃ (alumina).

Step 2: Hall-Heroult Electrolysis

  • Alumina (Al₂O₃) is dissolved in molten cryolite (Na₃AlF₆) at about 950–1000°C. Cryolite lowers the melting point of alumina from 2045°C to about 950°C.
  • Small amounts of AlF₃ and CaF₂ are added to improve conductivity and lower MP further.
  • Cathode: Carbon lining of the cell. Reaction: Al³⁺ + 3e⁻ → Al (l). Molten aluminium sinks to the bottom and is tapped off.
  • Anode: Carbon (graphite) rods. Reaction: 2O²⁻ → O₂ + 4e⁻. The O₂ produced reacts with the carbon anode at high temperature, forming CO₂. The anode is slowly consumed and must be replaced periodically. This is a distinctive feature of the Hall-Heroult cell.

Down's Process (Sodium)

Sodium is extracted by electrolysis of molten NaCl (not aqueous NaCl, because that would give H₂ at the cathode instead of Na).

  • CaCl₂ is added to lower the melting point of NaCl from 801°C to about 600°C. A steel gauze diaphragm separates the two electrodes to prevent Na and Cl₂ from recombining.
  • Cathode (iron): Na⁺ + e⁻ → Na (molten sodium rises and is collected).
  • Anode (graphite): 2Cl⁻ → Cl₂ + 2e⁻ (chlorine gas collected at top).

Other metals: Magnesium is extracted by electrolysis of molten MgCl₂ (Dow process). Calcium and potassium also need electrolysis of their fused salts.

Refining of Metals

The metal obtained after reduction is usually impure. Refining removes impurities to give a pure metal. The method chosen depends on the properties of the metal and its impurities.

MethodPrincipleMetals RefinedKey Details
DistillationMetal has low b.p.; impurities have higher b.p.Zinc (b.p. 907°C), Mercury (b.p. 357°C)Metal evaporates, condenses separately; impurities stay behind
LiquationMetal has lower m.p. than impuritiesTin (m.p. 232°C), Bismuth (m.p. 271°C)Impure metal on inclined hearth; metal melts and flows away; impurities stay
Electrolytic RefiningPure metal deposited at cathode; impurities dissolve at anode or fall as anode mudCu, Ag, Au, Ni, ZnAnode = impure metal; cathode = pure metal; electrolyte = metal salt solution
Zone RefiningImpurities more soluble in melt than solid; move with molten zoneGe, Si, Ga, In (semiconductors)Molten zone swept along rod; impurities concentrate at one end; that end is cut off
Vapor Phase Refining (Mond)Metal forms volatile compound; decomposed at higher tempNickel (Ni)Ni + 4CO → Ni(CO)₄ (55°C); Ni(CO)₄ → Ni + 4CO (230°C). CO recycled.
Vapor Phase Refining (van Arkel)Metal forms volatile halide; decomposed on hot filamentTitanium (Ti), Zirconium (Zr)Ti + 2I₂ → TiI₄ (500°C); TiI₄ → Ti + 2I₂ (1400°C, on hot wire). I₂ recycled.
Chromatographic PurificationDifferent affinities for stationary phaseRare elements, compoundsUsed when other methods fail; small scale

Electrolytic Refining (Detailed)

This is the most important refining method for NEET. Let us take copper as the example.

  • Anode: Impure copper (blister copper, 98–99% Cu)
  • Cathode: Thin sheet of pure copper
  • Electrolyte: Acidic CuSO₄ solution (copper sulphate + H₂SO₄)

What happens at each electrode:

  • Anode reaction: Cu → Cu²⁺ + 2e⁻. The impure copper dissolves. Impurities more active than Cu (Fe, Zn, Ni) also dissolve into the solution as Fe²⁺, Zn²⁺, Ni²⁺.
  • Cathode reaction: Cu²⁺ + 2e⁻ → Cu. Only Cu²⁺ is preferentially deposited because it has the right reduction potential. The more active metal ions (Fe²⁺, Zn²⁺, Ni²⁺) stay in solution.
  • Anode mud: Metals less active than Cu (gold, silver, platinum) do not dissolve at the anode. They fall below the anode as the "anode mud" or "anode slime." This anode mud is commercially valuable (source of precious metals).

The purity of the cathode copper reaches 99.99% (4 nines purity). This is required for electrical wiring.

Zone Refining (Detailed)

Zone refining (developed by W.G. Pfann, 1952) achieves the highest purities achievable and is essential for the semiconductor industry.

  1. An impure metal rod is placed in a tube under an inert atmosphere.
  2. A narrow circular heater moves slowly from one end of the rod to the other, creating a narrow molten zone.
  3. Impurities have a higher solubility in the liquid phase than in the solid phase (their distribution coefficient k < 1). As the molten zone moves forward, the impurities dissolve into the liquid zone and travel with it.
  4. Pure solid metal crystallises behind the molten zone as it moves forward.
  5. After multiple passes, impurities are concentrated at one end (the end where the heater finished). That end is cut off and discarded.

The remaining rod is extremely pure. Zone refining is used for Ge, Si, Ga, In, Bi, and other elements where ultra-high purity is needed for electronics.

Mond Process for Nickel

Nickel forms a volatile compound, nickel tetracarbonyl Ni(CO)₄, at low temperatures:

Ni (impure) + 4CO → Ni(CO)₄ (gas, at 50–60°C)

The Ni(CO)₄ vapour is then passed to a decomposer at 230°C, where it breaks back down:

Ni(CO)₄ → Ni (pure, deposits) + 4CO

The CO is recycled. This process is very selective: iron impurities form Fe(CO)₅ at a different temperature so can be separated. The pure Ni deposits on a nickel seed. The Mond process gives 99.99% pure nickel.

Van Arkel Method for Titanium and Zirconium

This uses a volatile halide intermediate. For titanium:

Ti (impure) + 2I₂ → TiI₄ (vapour, at 250°C) → heated tungsten filament (1400°C) → Ti (pure) + 2I₂

The iodine is recycled. This method gives extremely pure Ti and Zr, which are needed for aerospace and nuclear applications. The key point is that the metal forms a volatile iodide that can be transported and then thermally decomposed on a hot wire.

Extraction of Specific Metals

NEET questions often focus on specific metals. Know the complete extraction pathway for Cu, Fe, Al, and Zn.

Copper Extraction

Main ore: Copper pyrites, CuFeS₂

  1. Concentration: Froth flotation (sulphide ore; pine oil; collector is sodium ethyl xanthate). Gangue sinks; ore floats.
  2. Roasting (partial, limited air):2CuFeS₂ + O₂ → Cu₂S + 2FeS + SO₂. The ore converts to a molten mixture called matte (Cu₂S + FeS).
  3. Smelting in reverberatory furnace: Matte is heated with SiO₂ (silica flux). FeS is oxidised: 2FeS + 3O₂ → 2FeO + 2SO₂. FeO + SiO₂ → FeSiO₃ (slag, removed). Remaining Cu₂S goes to the converter.
  4. Converter (Bessemerisation): Cu₂S undergoes auto-reduction: 2Cu₂S + 3O₂ → 2Cu₂O + 2SO₂; Cu₂S + 2Cu₂O → 6Cu + SO₂. Product: blister copper (98–99% pure, blistered surface from SO₂ bubbles trapped during solidification).
  5. Refining: Electrolytic refining. Anode: blister Cu. Cathode: pure Cu. Electrolyte: CuSO₄ (aq). Anode mud contains Au, Ag, Pt.

Iron Extraction (Blast Furnace)

Main ore: Haematite, Fe₂O₃

  1. Concentration: Magnetic separation (Fe₂O₃ is magnetic; silicate gangue is not).
  2. No separate roasting needed: Haematite is already an oxide ore. Limestone (CaCO₃) is added as flux. The blast furnace processes ore, coke, and limestone together.
  3. Smelting in blast furnace: (See the blast furnace zone table in Section 4.) CO reduces Fe₂O₃ step by step. Molten pig iron (4% C) and slag (CaSiO₃) form at the bottom.
  4. Steel making: Pig iron is converted to steel by removing excess carbon and impurities using the Basic Oxygen Furnace (BOF) or electric arc furnace.

Aluminium Extraction (Already covered in Section 5)

Ore: Bauxite (Al₂O₃.2H₂O). Steps: Bayer leaching → calcination → Hall-Heroult electrolysis.

Zinc Extraction

Main ore: Zinc blende, ZnS

  1. Concentration: Froth flotation.
  2. Roasting: 2ZnS + 3O₂ → 2ZnO + 2SO₂ (in excess air, 900°C). ZnO is obtained.
  3. Carbon reduction (retort furnace): ZnO + C → Zn + CO (above 1000°C). Zinc is more volatile than the temperature needed; it leaves as zinc vapour. It is condensed in a separate chamber.
  4. Refining by distillation: Zinc (b.p. 907°C) can be separated by distillation from less volatile impurities. Gives 99.99% pure Zn.

Worked NEET Problems

1

NEET-style problem · Froth Flotation

Question

In froth flotation used to separate PbS from ZnS, which chemical acts as a depressant for ZnS?

Solution

NaCN (sodium cyanide) is the depressant for ZnS. The cyanide ion CN⁻ forms a stable complex [Zn(CN)₄]²⁻ on the ZnS particle surface, making ZnS hydrophilic so it sinks. PbS remains hydrophobic and floats with the froth. This allows selective separation of PbS from a mixed sulphide ore.
2

NEET-style problem · Ellingham Diagram

Question

In the Ellingham diagram, the line for 2C + O₂ → 2CO has a negative slope (goes downward with increasing temperature). Why?

Solution

Slope of an Ellingham line = −ΔS. For 2C + O₂ → 2CO: left side has 1 mole of gas (O₂); right side has 2 moles of gas (CO). The number of moles of gas increases, so entropy increases (ΔS is positive). Therefore −ΔS is negative, meaning the slope is negative (line goes downward). As temperature rises, the −TΔS term becomes more and more negative, so ΔG for this reaction keeps decreasing (becomes more negative). This is why at high temperatures, carbon (as C→CO) can reduce almost all metal oxides.
3

NEET-style problem · Vapour Phase Refining

Question

Impure nickel is treated with CO at 50°C to form a gas that is then decomposed at 230°C. What is the name and formula of the intermediate gas, and what is the name of this process?

Solution

The intermediate is nickel tetracarbonyl, Ni(CO)₄, a volatile gas. The process is the Mond process. Step 1: Ni + 4CO → Ni(CO)₄ (at 50–60°C, impure Ni reacts with CO). Step 2: Ni(CO)₄ → Ni + 4CO (at 230°C, pure Ni is deposited; CO is recycled). This gives 99.99% pure nickel. Iron forms Fe(CO)₅ at a different temperature, so it is separated at the first step.
4

NEET-style problem · Electrolytic Refining

Question

In the electrolytic refining of copper, the anode is impure and the cathode is pure. Some impurities dissolve in the electrolyte but are NOT deposited at the cathode. Why? And what happens to less active impurities like gold?

Solution

Active impurities like Fe, Zn, and Ni dissolve from the anode (their oxidation potentials are high enough) but are not deposited at the cathode because their reduction potentials are lower than that of Cu²⁺/Cu. Under the operating voltage, only Cu²⁺ is selectively reduced at the cathode. The Fe²⁺, Zn²⁺, and Ni²⁺ remain in the electrolyte solution and accumulate. Less active impurities like Au, Ag, and Pt have a higher reduction potential than the operating cell voltage; they do not dissolve at the anode at all. They fall as a sludge below the anode called 'anode mud' or 'anode slime.' The anode mud is recovered and processed to extract precious metals, making it an economically valuable by-product.
5

NEET-style problem · Hall-Heroult Process

Question

Why must the carbon anode in the Hall-Heroult process be replaced periodically?

Solution

At the anode in the Hall-Heroult cell, oxide ions (O²⁻) from the dissolved Al₂O₃ are oxidised: 2O²⁻ → O₂ + 4e⁻. The oxygen released is at about 950–1000°C. At this high temperature, the O₂ immediately reacts with the carbon (graphite) anode: C + O₂ → CO₂ (or CO). This slowly burns and consumes the carbon anode. Over time the anode shrinks and must be replaced to maintain electrical contact and proper cell geometry. This is a significant operational cost of the Hall-Heroult process. Modern cells use a continuous anode feed to minimise downtime.

Summary Cheat Sheet

Ore Concentration Methods

MethodUsed ForKey Reagent/FeatureNEET Example
Gravity separationDense oresWater stream; dense ore sinksCassiterite (SnO₂)
Magnetic separationMagnetic ore or gangueElectromagnetic drumRemove FeWO₄ from SnO₂
Froth flotationSulphide oresPine oil (frother), xanthate (collector), NaCN (depressant)PbS, ZnS, CuFeS₂
LeachingOxide/hydroxide ores; noble metalsNaOH for Al; NaCN for Ag/AuBayer process for Al

Ellingham Diagram Quick Reference

  • Line lower in diagram = oxide more stable = metal harder to extract
  • C→CO line has negative slope (ΔS positive, 1 mol gas → 2 mol gas)
  • C→CO₂ line is nearly horizontal (ΔS ≈ 0, equal moles of gas)
  • Where C→CO crosses below metal oxide line = carbon can reduce that oxide at that temperature
  • Al₂O₃, MgO, CaO lines never crossed by C→CO = must use electrolysis
  • Al₂O₃ line below Fe₂O₃ line = Al reduces Fe₂O₃ (thermit reaction)

Refining Method Quick Reference

  • Zone refining: Ge, Si, Ga, In (semiconductors, ultra-high purity)
  • Distillation: Zn, Hg (volatile metals)
  • Liquation: Sn, Bi (low melting point metals)
  • Electrolytic: Cu, Ag, Au, Ni, Zn (anode = impure; cathode = pure; anode mud = precious metals)
  • Mond process: Ni (forms volatile Ni(CO)₄ at 55°C; decomposes at 230°C)
  • Van Arkel: Ti, Zr (forms volatile TiI₄ at 250°C; decomposes on hot wire at 1400°C)

Specific Extraction Summary

MetalMain OreConcentrationPre-treatmentReductionRefining
CuCuFeS₂Froth flotationRoasting (matte)Auto-reduction in converterElectrolytic
FeFe₂O₃Magnetic separationNone (already oxide)CO in blast furnaceSteel making
AlAl₂O₃.2H₂OBayer leaching (NaOH)Calcination → Al₂O₃Hall-Heroult (electrolysis in cryolite melt)No further needed
ZnZnSFroth flotationRoasting → ZnOC reductionDistillation
NaNaClNone neededMelt NaCl + CaCl₂Electrolysis (Down's process)No further needed

NEET Frequency Summary

This chapter contributes about 1–2 questions per year. The most tested topics are:

  1. Froth flotation: depressants (NaCN for ZnS), collectors, frothers
  2. Ellingham diagram: slope interpretation, which metal oxide carbon can/cannot reduce
  3. Zone refining: which metals (Ge, Si), principle (impurities in melt)
  4. Hall-Heroult process: role of cryolite, electrode reactions
  5. Roasting vs calcination: which pre-treatment for which ore type
  6. Electrolytic refining: anode = impure, cathode = pure, anode mud = precious metals
  7. Matte in copper metallurgy: Cu₂S + FeS
  8. Auto-reduction: Cu₂S + Cu₂O → Cu + SO₂

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Frequently asked questions

What is the difference between an ore and a mineral?

A mineral is any naturally occurring compound of a metal found in Earth's crust. An ore is a mineral from which the metal can be extracted profitably (economically). All ores are minerals, but not all minerals are ores. For example, both bauxite (Al₂O₃.2H₂O) and corundum (Al₂O₃) are minerals of aluminium. Bauxite is the ore used commercially because it has a high enough aluminium content and is easy to process. Corundum is too hard and too pure to be processed economically at scale. The key question that makes a mineral an ore is: can you get the metal out at a profit?

How does froth flotation work? Why is pine oil used?

Froth flotation separates sulphide ore particles from gangue (waste rock) by using the difference in the ability of the two surfaces to be wetted by water (hydrophobicity). The ore powder is mixed with water and pine oil, and air is blown through the mixture to create froth. Pine oil (or other frother/collector combination) preferentially wets the sulphide ore particles and makes them hydrophobic (water-repelling). These hydrophobic particles attach to the air bubbles in the froth and float to the surface. The gangue (silicates, etc.) is hydrophilic (water-loving) and sinks to the bottom. The froth carrying the ore is skimmed off. Specific collectors like sodium ethyl xanthate increase the selectivity. Depressants like NaCN can suppress one sulphide (e.g. ZnS) while allowing another (e.g. PbS) to float, enabling selective separation of mixed sulphide ores.

What is the Ellingham diagram? How do you read it?

The Ellingham diagram is a graph of standard Gibbs free energy of formation (ΔfG°) of metal oxides plotted against temperature. Each metal oxide has its own line. A line lower in the diagram means the oxide is more stable (more negative ΔfG°) and the metal is harder to extract. To decide if metal A can reduce the oxide of metal B: if the line for metal A lies below the line for metal B's oxide at a given temperature, then the reaction (A + BOx → AOx + B) is spontaneous (negative ΔG). In simpler terms, a metal whose oxide line is lower can reduce the oxide whose line is higher. Carbon is special: the line for 2C + O₂ → 2CO has a negative slope (goes downward with increasing temperature) because entropy increases sharply. At high enough temperature, the carbon line drops below almost all metal oxide lines, making carbon (coke) a universal reductant at high temperatures. The C + O₂ → CO₂ line is nearly horizontal (ΔS ≈ 0, same moles of gas on both sides).

Why is coke used to reduce iron oxide but not aluminium oxide?

Whether coke (carbon) can reduce a metal oxide depends on the Ellingham diagram: coke reduces the metal oxide only where the C→CO line lies below the metal oxide line (i.e., ΔG for the reduction becomes negative). For Fe₂O₃: the C→CO line crosses below the Fe₂O₃ line at around 700°C. Above this temperature, carbon spontaneously reduces Fe₂O₃ to Fe. For Al₂O₃: the Al₂O₃ line is far below the C→CO line at all practical temperatures (even above 1500°C). This means Al₂O₃ is more stable than any carbon oxide that would form. Carbon cannot reduce Al₂O₃ because the reduction is thermodynamically unfavourable at any achievable temperature. That is why aluminium must be extracted by electrolysis (Hall-Heroult process) instead. Similarly, MgO and CaO have very low Ellingham lines and cannot be reduced by carbon.

What is zone refining? For which metals is it used?

Zone refining is a method of purifying metals (especially semiconductors) to very high purity. A narrow molten zone is moved slowly from one end of an impure metal rod to the other. Impurities are more soluble in the molten phase than in the solid phase, so they concentrate in the molten zone and travel with it to one end of the rod. After several passes, the impurities accumulate at one end (which is cut off and discarded), leaving a very pure metal rod behind. Zone refining is used for semiconductors that need extremely high purity: germanium (Ge), silicon (Si), gallium (Ga), and indium (In). NEET frequently asks "which method is used to purify semiconductors?". The answer is zone refining.

How is aluminium extracted by the Hall-Heroult process?

Aluminium cannot be extracted by carbon reduction because Al₂O₃ is too stable (its Ellingham line is below the C→CO line at all practical temperatures). Instead, electrolytic reduction is used. The Hall-Heroult process works as follows: alumina (Al₂O₃) is dissolved in molten cryolite (Na₃AlF₆) at about 1000°C. Cryolite lowers the melting point of Al₂O₃ from 2045°C to around 950°C, making the process economically feasible. Small amounts of AlF₃ and CaF₂ are added to lower the melting point further and improve conductivity. Carbon (graphite) electrodes are used. At the cathode: Al³⁺ + 3e⁻ → Al (molten aluminium is deposited at the bottom of the cell). At the anode: 2O²⁻ → O₂ + 4e⁻ (oxygen is released, which reacts with the carbon anode and slowly burns it, so the carbon anode must be replaced periodically). The cell operates continuously; pure liquid aluminium is tapped from the bottom.

What is the difference between roasting and calcination?

Both are pre-treatment steps that convert an ore to its oxide before reduction, but they apply to different types of ores. Roasting is heating a sulphide ore strongly in the presence of excess air. The sulphide is converted to an oxide: 2ZnS + 3O₂ → 2ZnO + 2SO₂. Roasting is used for sulphide ores (e.g. ZnS, CuFeS₂). The SO₂ produced is a by-product (used to make H₂SO₄). Calcination is heating a carbonate or hydroxide ore strongly in the absence or limited supply of air. The ore thermally decomposes to give the oxide: ZnCO₃ → ZnO + CO₂, and Al(OH)₃ → Al₂O₃ + H₂O. Calcination is used for carbonate ores (calamine ZnCO₃, siderite FeCO₃, malachite CuCO₃.Cu(OH)₂) and hydroxide ores (gibbsite Al(OH)₃ from bauxite). Memory hook: Roasting uses air (oxygen present), Calcination uses heat alone.

Why is carbon reduction feasible for ZnO but not for MgO?

This is explained directly by the Ellingham diagram. The stability of a metal oxide is shown by how low its ΔfG° line sits on the diagram. MgO has a very low (very negative ΔfG°) line throughout the temperature range, lower than the C→CO line even at 2000°C. This means magnesium has a stronger affinity for oxygen than carbon does, so carbon cannot displace magnesium from MgO at any practical temperature. ZnO has a higher ΔfG° line. The C→2CO line (negative slope) crosses below the ZnO line at around 950°C. Above this temperature, carbon reduction of ZnO becomes spontaneous: ZnO + C → Zn + CO. Zinc is therefore extracted by carbon reduction (in a retort furnace) at about 1200°C followed by distillation to purify the product. For magnesium, electrolysis of molten MgCl₂ is used instead.

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