14 NEET previous-year questions on s-Block Elements (Alkali and Alkaline Earth Metals), each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.
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Li
Na
K
Be
Solution
Li forms a normal oxide (Li₂O). Na forms a peroxide (Na₂O₂). K, Rb, and Cs form superoxides (KO₂, RbO₂, CsO₂). The larger the alkali metal, the higher the oxide formed: Li → oxide; Na → peroxide; K, Rb, Cs → superoxide. Be is not an alkali metal (it is Group 2).
Solubility of sulphates increases from Be to Ba
All Group 2 sulphates are insoluble in water
Solubility of sulphates decreases from Mg to Ba (BaSO₄ is almost insoluble)
CaSO₄ is more soluble than MgSO₄
Solution
The solubility of Group 2 sulphates decreases down the group: MgSO₄ is soluble in water, CaSO₄ is sparingly soluble, SrSO₄ is slightly soluble, and BaSO₄ is practically insoluble (Ksp ≈ 1.1 × 10⁻¹⁰). BaSO₄ precipitates as the test for Ba²⁺ and SO₄²⁻.
Na
K
Cs
Li
Solution
Lithium (Li) is the only alkali metal that reacts with N₂ at room temperature to form lithium nitride: 6Li + N₂ → 2Li₃N. This is an anomalous property due to Li's small size and high charge density. Other alkali metals do not react with N₂ directly.
Losing water to form anhydrous CaSO₄
Absorbing water from the environment to form CaSO₄·2H₂O
Reacting with CO₂ to form CaCO₃
Decomposing to form CaO
Solution
Plaster of Paris (CaSO₄·½H₂O) sets by absorbing water (1½ mol per formula unit) to form gypsum (CaSO₄·2H₂O): CaSO₄·½H₂O + 1½H₂O → CaSO₄·2H₂O. This process involves a slight expansion in volume and is slightly exothermic.
NaOH
KOH
LiOH
CsOH
Solution
LiOH decomposes on heating: 2LiOH → Li₂O + H₂O. This is an anomalous property of lithium due to its small size and high charge density. The other alkali metal hydroxides (NaOH, KOH, RbOH, CsOH) are thermally stable and do not decompose on heating.
Ba(OH)₂ is less soluble than Mg(OH)₂
Be(OH)₂ is amphoteric; Ba(OH)₂ is strongly alkaline
All Group 2 hydroxides have equal solubility
Ca(OH)₂ is more soluble than Ba(OH)₂
Solution
Be(OH)₂ is amphoteric (dissolves in both acid and alkali). Solubility of Group 2 hydroxides increases down the group: Mg(OH)₂ ≈ slightly soluble → Ca(OH)₂ slightly soluble → Sr(OH)₂ moderately soluble → Ba(OH)₂ soluble (strongly basic). So Ba(OH)₂ is the most soluble and most strongly basic Group 2 hydroxide.
It dissolves in kerosene to increase stability
Kerosene prevents reaction with air and moisture
Sodium is less dense than kerosene
Sodium reacts with other hydrocarbon liquids but not kerosene
Solution
Sodium reacts vigorously with water (forming NaOH and H₂) and with oxygen (forming Na₂O₂). To protect it from both atmospheric moisture and oxygen, sodium is stored under kerosene oil, which is a non-polar, non-reactive liquid that does not react with sodium.
Beryllium
Aluminium
Magnesium
Silicon
Solution
Li (Group 1, Period 2) has a diagonal relationship with Mg (Group 2, Period 3). Both have similar charge-to-radius ratios (polarising power). Common similarities: both react with N₂ (Li₃N and Mg₃N₂), both form normal oxides on burning, both decompose their carbonates on mild heating.
It burns and absorbs heat
It decomposes on heating to release CO₂, which smothers the fire
It is a strong base that reacts with flames
It produces water vapour to cool the fire
Solution
2NaHCO₃ → Na₂CO₃ + H₂O + CO₂. The CO₂ released is a non-flammable gas heavier than air; it smothers the fire by cutting off the oxygen supply. Dry powder fire extinguishers (for oil and electrical fires) use NaHCO₃ for this reason.
Forms a superoxide with oxygen
Dissolves in alkali as well as in acid (amphoteric)
Forms an ionic chloride BeCl₂
Reacts very vigorously with cold water
Solution
Beryllium is amphoteric — it dissolves in both dilute acids (Be + 2HCl → BeCl₂ + H₂) and strong alkalis (Be + 2NaOH + 2H₂O → Na₂[Be(OH)₄] + H₂). No other Group 2 element shows this behaviour. BeCl₂ is covalent, not ionic. Be does not react with cold water.
Potassium
Barium
Sodium
Calcium
Solution
Sodium imparts a characteristic golden-yellow (sometimes called brilliant yellow) colour to a flame. This is due to the 3s → 3p transition of the sodium D-line doublet at 589 nm. Potassium gives violet/lilac, barium gives apple green, calcium gives brick red.
BaCl₂
NaCl
CaCl₂
MgCl₂
Solution
BaCl₂ is used to test for sulphate ions (SO₄²⁻). Ba²⁺ + SO₄²⁻ → BaSO₄↓ (white precipitate, insoluble in dilute HCl). This is because BaSO₄ has an extremely low Ksp. CaSO₄ is slightly soluble, and Mg/Na sulphates are soluble.
Li⁺ has a larger ionic radius than Cs⁺
Li⁺ has a smaller ionic radius and higher charge density; it attracts water molecules more strongly
Cs⁺ is more electronegative than Li⁺
Li⁺ has more electrons than Cs⁺
Solution
Hydration energy (enthalpy of hydration) depends on the charge density of the ion (charge/radius ratio). Li⁺ is the smallest Group 1 ion (ionic radius ≈ 76 pm), so it has the highest charge density and attracts the dipole of water molecules very strongly. Hydration enthalpy: Li⁺ (−520 kJ/mol) >> Cs⁺ (−264 kJ/mol).
The milky precipitate persists
The milky precipitate dissolves, giving a clear solution
A yellow precipitate forms
No reaction occurs
Solution
When CO₂ is passed into lime water: Ca(OH)₂ + CO₂ → CaCO₃↓ + H₂O (milky, due to insoluble CaCO₃). On passing excess CO₂: CaCO₃ + CO₂ + H₂O → Ca(HCO₃)₂. Calcium bicarbonate is soluble, so the milkiness disappears and the solution becomes clear again.
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