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Structure of Atom

Structure of AtomNEET Chemistry · Class 11 · NCERT Chapter 2

Introduction

Every substance you study in chemistry is made of atoms. Understanding the inside of an atom, its electrons, protons, neutrons, and the rules governing their arrangement, is the key to explaining chemical reactivity, bonding, and the entire periodic table. Structure of Atom is one of the highest-weightage chapters in NEET Chemistry, delivering 3 to 4 questions most years.

The most tested areas are: electronic configurations (including exceptions for Cr and Cu), quantum numbers, Bohr model energy calculations, and de Broglie wavelength problems. This chapter is mathematical as well as conceptual, so you need to practise both.

Sub-atomic Particles

Three experiments revealed that atoms are made of smaller particles.

Discovery of Electron: Cathode Ray Experiment (J.J. Thomson, 1897)

When high voltage is applied across gas-filled tubes at low pressure, rays travel from the cathode to the anode. These cathode rays have these key properties:

  • They travel in straight lines and cast shadows.
  • They are deflected by electric and magnetic fields toward the positive plate, showing they are negatively charged.
  • The charge-to-mass ratio (e/m) is constant regardless of the cathode material or gas used.
  • This proved electrons are fundamental particles present in all matter.

Thomson measured e/m = 1.758820 × 10¹¹ C kg⁻¹. Millikan later determined e = 1.602 × 10⁻¹⁹ C, from which mass of electron = 9.11 × 10⁻³¹ kg.

Discovery of Proton: Canal Rays (Goldstein, 1886)

When a perforated cathode is used, rays also travel in the opposite direction (from anode toward cathode). These canal rays (or anode rays) are positively charged. The lightest canal ray particles had charge equal and opposite to the electron and much greater mass. These were protons. Mass of proton = 1.673 × 10⁻²⁷ kg = 1836 × mass of electron.

Discovery of Neutron (Chadwick, 1932)

When beryllium was bombarded with alpha particles, a highly penetrating radiation was produced that was not deflected by electric or magnetic fields. Chadwick showed these were neutral particles with mass approximately equal to the proton. These are neutrons. Mass of neutron = 1.675 × 10⁻²⁷ kg.

Properties of Sub-atomic Particles

ParticleSymbolChargeMass (kg)Mass (u)Location
Electrone⁻−1.602 × 10⁻¹⁹ C (−1 unit)9.11 × 10⁻³¹0.000549Outside nucleus (orbitals)
Protonp⁺+1.602 × 10⁻¹⁹ C (+1 unit)1.673 × 10⁻²⁷1.00728Inside nucleus
Neutronn01.675 × 10⁻²⁷1.00866Inside nucleus

Atomic Number, Mass Number, Isotopes, and Isobars

The atomic number (Z) = number of protons in the nucleus. It determines the identity of the element. The mass number (A) = number of protons + number of neutrons. Number of neutrons = A − Z.

Isotopes are atoms of the same element (same Z) but different mass number (different number of neutrons). Example: ¹H (protium), ²H (deuterium), ³H (tritium) are isotopes of hydrogen.

Isobars are atoms of different elements (different Z) but the same mass number (A). Example: ¹⁴₆C and ¹⁴₇N are isobars (both have A = 14).

Isotones are atoms with the same number of neutrons. Example: ¹⁴₆C and ¹⁵₇N both have 8 neutrons.

Early Atomic Models

Thomson's Plum-Pudding Model (1904)

Thomson proposed that an atom is a sphere of uniform positive charge (like pudding) with electrons embedded in it (like plums). The positive and negative charges balance, making the atom neutral. This model was abandoned when Rutherford's experiment showed the positive charge is concentrated in a tiny nucleus.

Rutherford's Nuclear Model (1911)

Geiger and Marsden, working under Rutherford, bombarded a thin gold foil with a beam of alpha particles (helium nuclei, charge +2, mass 4u) from a radioactive source. A circular fluorescent screen detected where the particles went.

Key Observations and Conclusions

ObservationConclusion
Most alpha particles passed straight throughMost of an atom is empty space
Some deflected at small anglesThere is a region of positive charge inside the atom
Very few (about 1 in 20,000) bounced straight backThe positive charge is concentrated in an extremely small, dense region: the nucleus

Rutherford's Model of the Atom

  • The atom has a tiny, dense, positively charged nucleus at the centre.
  • Almost all the mass of the atom is in the nucleus.
  • The electrons revolve around the nucleus in circular orbits (like planets around the sun).
  • The size of the nucleus is about 10⁻¹⁵ m; the atom is about 10⁻¹⁰ m. So the nucleus is about 10⁵ times smaller than the atom.

Drawbacks of Rutherford's Model

  • An electron moving in a circular orbit is accelerating. According to classical electromagnetic theory, an accelerating charged particle must continuously emit radiation and lose energy. So the electron should spiral inward and the atom should collapse in about 10⁻⁸ s. Atoms clearly do not collapse, so the model was incomplete.
  • It could not explain the line spectrum of hydrogen. Classical theory predicts a continuous spectrum, but hydrogen emits only specific wavelengths of light.

Bohr's Model of Hydrogen (1913)

Niels Bohr solved Rutherford's problems by incorporating quantum ideas. He proposed four postulates for the hydrogen atom:

  1. Electrons revolve around the nucleus in fixed circular paths called stationary states or orbits. These are allowed orbits.
  2. An electron in an allowed orbit does not radiate energy and does not spiral inward.
  3. Only orbits where the angular momentum of the electron is a whole-number multiple of are allowed:
    where n = 1, 2, 3, ... is the principal quantum number, h is Planck's constant.
  4. Energy is absorbed or emitted only when an electron jumps between allowed orbits. The energy of the photon equals the energy difference between the two states:
    where is the frequency of the emitted or absorbed photon.

Energy of Bohr's Orbits (for Hydrogen-like atoms)

The negative sign means the electron is bound to the nucleus (energy is negative for bound states). The ground state is n = 1 with E₁ = −13.6 eV. As n increases, the energy becomes less negative (higher, i.e., less stable). At n = ∞, E = 0 (electron is free).

Radius of Bohr's Orbits

For hydrogen: r₁ = 52.9 pm (= 0.529 Å, the Bohr radius, a₀). r₂ = 4 × 52.9 = 211.6 pm.

Velocity of Electron in Bohr's Orbits

Hydrogen Spectrum and Spectral Series

When hydrogen is excited (given energy), electrons jump to higher levels. When they fall back to lower levels, they emit photons of specific energy. Different series are named for the level they fall to:

SeriesElectron falls to shell (n₂)Spectral region
Lymann = 1Ultraviolet
Balmern = 2Visible
Paschenn = 3Infrared
Brackettn = 4Infrared
Pfundn = 5Far infrared

The wavenumber ( = 1/λ) of a line in any series is given by Rydberg's formula:

where RH= 1.097 × 10⁷ m⁻¹ (Rydberg constant), n₁ = lower level, n₂ = upper level (n₂ > n₁).

Energy levels

Energy (eV)n=1-13.60 eVn=2-3.40 eVn=3-1.51 eVn=4-0.85 eVn=5-0.54 eVn=6-0.38 eVn=7-0.28 eVemissionn=∞0 eV

Select transition

From n =

1
2
3
4
5
6
7

To n =

1
2
3
4
5
6
7

Type

Emission (photon released)

n=3 → n=2 (higher to lower)

Energy

ΔE = 1.889 eV

3.026e-19 J

Limitations of Bohr's Model

  • Works only for hydrogen and hydrogen-like ions (one electron). Fails for multi-electron atoms.
  • Cannot explain the fine structure of spectral lines (Zeeman and Stark effects).
  • Does not account for the wave nature of the electron (de Broglie).
  • Violates the Heisenberg uncertainty principle by specifying exact orbits.

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Dual Nature of Matter and Radiation

Planck's Quantum Theory (1900)

Energy is not emitted or absorbed continuously. It is emitted in discrete packets called quanta (plural) or a quantum (singular). The energy of one quantum is:

where h = 6.626 × 10⁻³⁴ J·s (Planck's constant) and ν is the frequency of radiation. Since c = νλ, we can write E = hc/λ.

Photoelectric Effect (Einstein, 1905)

When light of a certain minimum frequency (threshold frequency, ν₀) falls on a metal, electrons are ejected. Key observations:

  • Electrons are ejected only if the frequency of light exceeds ν₀, regardless of intensity.
  • The kinetic energy of emitted electrons increases with frequency, not intensity.
  • Above ν₀, the number of electrons ejected increases with intensity.

Einstein explained this by treating light as particles (photons). Each photon carries energy hν. If hν ≥ hν₀ (the work function), the electron is ejected:

Cesium
Potassium
Sodium
Zinc
Copper
Platinum

Sodium (Na)

Work function (Φ) = 2.75 eV · Threshold frequency ν₀ = 6.65 × 10¹⁴ Hz (451 nm, Visible)

Incident light frequency

ν = 10.0 × 10¹⁴ Hz

λ = 300.0 nm (UV)

Electron ejected

ν = 10.0 × 10¹⁴ Hz ν₀ = 6.65 × 10¹⁴ Hz

Einstein's equation: KE = hν − Φ

E(photon) = hν = 6.626e-34 × 10.0 × 10¹⁴ = 6.626e-19 J = 4.136 eV

Φ = 2.75 eV

KE = 4.1362.75 = 1.386 eV = 2.220e-19 J

Kinetic energy of ejected electron

1.386 eV

2.220e-19 J

de Broglie's Wave-Particle Duality (1924)

If radiation (light) can behave as particles (photons), then matter (particles like electrons) can also behave as waves. de Broglie's wavelength for a particle of mass m moving with velocity v:

where p = mv is the momentum. The wave nature of electrons was confirmed by Davisson and Germer's electron diffraction experiment (1927).

For a particle accelerated through potential V, the kinetic energy is eV = ½mv², so:

Heisenberg's Uncertainty Principle (1927)

It is fundamentally impossible to simultaneously determine the exact position and exact momentum of a moving particle. The more precisely you know the position, the less precisely you can know the momentum, and vice versa.

Or in terms of energy and time:

This principle destroys the concept of definite orbits. An electron cannot have a known path. Instead, we can only speak of the probability of finding an electron in a given region of space.

Note: The uncertainty principle is not due to instrument limitations. It is a fundamental property of quantum systems.

Quantum Mechanical Model of the Atom

Erwin Schrödinger (1926) derived a wave equation for the electron in an atom. Solutions to the Schrödinger equation are called wave functions (ψ, psi). Each wave function describes a specific state of the electron.

Key idea: ψ² gives the probability density of finding an electron at a given point in space. The 3D region where ψ² is significant is called an orbital. An orbital is not a definite path; it is a probability cloud.

Radial probability distribution tells you the probability of finding the electron at various distances from the nucleus. For 1s, there is a maximum at r = 52.9 pm (the Bohr radius is the most probable distance for the 1s electron in hydrogen).

Quantum Numbers

Four quantum numbers completely describe the state of an electron in an atom. They arise naturally from the solution to the Schrödinger equation.

1. Principal Quantum Number (n)

Indicates the main energy level (shell) and the average distance of the electron from the nucleus.

  • Allowed values: n = 1, 2, 3, 4, ... (positive integers)
  • Shell designations: n = 1 (K), n = 2 (L), n = 3 (M), n = 4 (N)
  • Maximum electrons in a shell: 2n²

2. Azimuthal (Angular Momentum) Quantum Number (l)

Indicates the subshell (shape of orbital) within a shell.

  • Allowed values: l = 0, 1, 2, ..., (n−1)
  • Subshell designations: l = 0 (s), l = 1 (p), l = 2 (d), l = 3 (f)
  • Number of orbitals in a subshell: 2l + 1
  • Maximum electrons in a subshell: 2(2l + 1)
l valueSubshellNumber of orbitals (2l+1)Max electrons
0s12
1p36
2d510
3f714

3. Magnetic Quantum Number (ml or m)

Indicates the orientation of the orbital in space.

  • Allowed values: ml = −l, ..., −1, 0, +1, ..., +l (total 2l + 1 values)
  • For l = 1 (p): ml = −1, 0, +1 (three p orbitals: px, py, pz)
  • For l = 2 (d): ml = −2, −1, 0, +1, +2 (five d orbitals)

4. Spin Quantum Number (ms or s)

Indicates the spin of the electron: either spin-up (+½) or spin-down (−½). Each orbital can hold at most 2 electrons with opposite spins.

  • Allowed values: ms = +½ or −½

Quick Summary Table

Quantum numberSymbolWhat it describesAllowed values
PrincipalnShell, energy, size1, 2, 3, ...
AzimuthallSubshell, shape0 to n−1
MagneticmlOrbital, orientation−l to +l
SpinmsElectron spin+½ or −½
1s electron (↑)
2p electron (mₗ=+1, ↓)
3d electron (mₗ=-2, ↑)
Invalid: l > n-1
Invalid: mₗ out of range

1, 2, 3, …

0 to n−1

−l to +l

mₛ (spin)

Valid set

3d

Electron in orbital 3d, mₗ = -2, spin ↑ (+½)

Subshell

3d

Orbitals in subshell

5 (mₗ = -2, -1, 0, 1, 2)

Max electrons

10 (subshell)

Orbital capacity

2 electrons

Shapes of Orbitals

s Orbitals (l = 0)

s orbitals are spherically symmetric: the probability of finding the electron is the same in all directions at a given distance from the nucleus. The size increases with n: 3s > 2s > 1s. The 2s orbital has one radial node (a spherical surface where ψ² = 0); 3s has two.

p Orbitals (l = 1)

There are three p orbitals (px, py, pz), each shaped like a dumbbell (two lobes) along one axis. They have a nodal plane (a plane where ψ² = 0) passing through the nucleus. For example, px has its lobes along the x-axis and a nodal plane in the yz plane. The three p orbitals are degenerate (have the same energy) in a free atom.

d Orbitals (l = 2)

There are five d orbitals. Four of them (dxy, dxz, dyz, and dx²-y²) have four lobes arranged between or along the axes. The fifth (d) has two lobes along the z-axis and a doughnut-shaped ring in the xy plane. All five are degenerate in a free atom.

Number of Nodes

Total nodes in any orbital = n − 1. These are split into angular nodes (l) and radial nodes (n − l − 1).

OrbitalTotal nodes (n−1)Angular nodes (l)Radial nodes (n−l−1)
1s000
2s101
2p110
3s202
3p211
3d220

Rules for Filling Orbitals

1. Aufbau Principle

Electrons fill orbitals in order of increasing energy. The (n + l) rule: the orbital with lower (n + l) has lower energy. If two orbitals have the same (n + l), the one with lower n has lower energy.

Filling order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, ...

2. Pauli Exclusion Principle

No two electrons in an atom can have the same set of all four quantum numbers. This means each orbital can hold at most two electrons, and they must have opposite spins (+½ and −½).

3. Hund's Rule of Maximum Multiplicity

When filling orbitals of equal energy (degenerate orbitals, e.g., three p orbitals or five d orbitals), electrons fill each orbital singly before any orbital is doubly occupied. All singly-occupied orbitals have parallel spins.

Example for carbon (Z = 6): configuration is 1s² 2s² 2p². The two 2p electrons go into two different 2p orbitals with parallel spins, not both into the same orbital.

Electronic Configurations

Use the Aufbau principle, Pauli exclusion principle, and Hund's rule together to write electronic configurations.

Key Configurations to Memorise

Element (Z)Electronic ConfigurationNote
H (1)1s¹
He (2)1s²Noble gas; 1s full
Li (3)[He] 2s¹
Be (4)[He] 2s²
B (5)[He] 2s² 2p¹
C (6)[He] 2s² 2p²Hund's rule: two separate p orbitals
N (7)[He] 2s² 2p³Half-filled 2p; extra stability
O (8)[He] 2s² 2p⁴
F (9)[He] 2s² 2p⁵
Ne (10)[He] 2s² 2p⁶Noble gas
Na (11)[Ne] 3s¹
Ar (18)[Ne] 3s² 3p⁶Noble gas
K (19)[Ar] 4s¹4s fills before 3d
Ca (20)[Ar] 4s²
Sc (21)[Ar] 3d¹ 4s²First transition metal
Cr (24)[Ar] 3d⁵ 4s¹Exception: half-filled 3d stability
Cu (29)[Ar] 3d¹⁰ 4s¹Exception: fully-filled 3d stability
Zn (30)[Ar] 3d¹⁰ 4s²
Kr (36)[Ar] 3d¹⁰ 4s² 4p⁶Noble gas

Stability of Half-filled and Fully-filled Subshells

Certain electron configurations have extra stability because of two factors:

  • Symmetry: Half-filled (d⁵, f⁷) and fully-filled (d¹⁰, f¹⁴) subshells have spherically symmetric electron distributions, which lowers the energy.
  • Exchange energy: Electrons with parallel spins can exchange positions. More parallel spins means higher exchange energy, which stabilises the configuration.

This is why chromium (Cr, Z = 24) has [Ar] 3d⁵ 4s¹ instead of the expected [Ar] 3d⁴ 4s². One electron moves from 4s to 3d to give the half-filled 3d⁵ configuration. Copper (Cu, Z = 29) has [Ar] 3d¹⁰ 4s¹ instead of [Ar] 3d⁹ 4s² for similar reasons.

These two exceptions (Cr and Cu) are the most tested in NEET. Memorise them.

Fe

Z = 26

Full configuration

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶

Noble gas shorthand

[Ar] 4s² 3d⁶

Subshell filling (Aufbau order)

1s

2/2

2s

2/2

2p

6/6

3s

2/2

3p

6/6

4s

2/2

3d

6/10

Unpaired electrons (Hund's rule)

4

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NEET-style mock questions on quantum numbers, orbital filling, and Cr/Cu exceptions. Track your progress chapter by chapter.

Worked NEET Problems

1

NEET-style problem · Bohr Model

Question

Calculate the energy of the electron in the second orbit of hydrogen. (RH = 2.18 × 10⁻¹⁸ J)

Solution

Using J.

E₂ = −2.18 × 10⁻¹⁸ / (2²) = −2.18 × 10⁻¹⁸ / 4 = −5.45 × 10⁻¹⁹ J.

2

NEET-style problem · de Broglie Wavelength

Question

What is the de Broglie wavelength of an electron moving with a velocity of 2.0 × 10⁶ m/s? (h = 6.626 × 10⁻³⁴ J·s, mass of electron = 9.11 × 10⁻³¹ kg)

Solution

= 6.626 × 10⁻³⁴ / (1.822 × 10⁻²⁴) = 3.64 × 10⁻¹⁰ m = 3.64 Å.

3

NEET-style problem · Quantum Numbers

Question

How many orbitals are present in n = 3 shell? How many electrons can it hold?

Solution

For n = 3, l can be 0, 1, or 2 (i.e., 3s, 3p, and 3d subshells).

Number of orbitals: 3s has 1, 3p has 3, 3d has 5. Total = 1 + 3 + 5 = 9 orbitals.

Maximum electrons = 2 × (number of orbitals) = 2 × 9 = 18. OR use the formula: 2n² = 2(9) = 18.

4

NEET-style problem · Electronic Configuration

Question

Write the electronic configuration of Fe (Z = 26) and Fe³⁺.

Solution

Fe (Z = 26): 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶ 4s² or [Ar] 3d⁶ 4s².

Fe³⁺ loses 3 electrons. In transition metals, electrons are removed from the outermost s subshell first, then from d. So 4s² electrons go first (losing 2), then one 3d electron (losing 1 more).

Fe³⁺: [Ar] 3d⁵. This is a half-filled 3d subshell (extra stability), which is why Fe³⁺ is more stable than Fe²⁺.

Summary Cheat Sheet

ConceptKey Formula / Fact
Bohr orbit energyEn = −13.6/n² eV = −2.18 × 10⁻¹⁸/n² J
Bohr orbit radiusrn = 0.529 × n² Å
Rydberg formulaν̄ = RH(1/n₁² − 1/n₂²); RH = 1.097 × 10⁷ m⁻¹
de Broglie wavelengthλ = h/mv = h/p
Photoelectric equation½mv² = hν − hν₀
Heisenberg uncertaintyΔx · Δp ≥ h/4π
Quantum numbersn: shell; l: 0 to n−1; ml: −l to +l; ms: ±½
Orbitals in a shelln² orbitals; 2n² electrons maximum
Angular nodes= l
Radial nodes= n − l − 1
Cr exception[Ar] 3d⁵ 4s¹ (not 3d⁴ 4s²)
Cu exception[Ar] 3d¹⁰ 4s¹ (not 3d⁹ 4s²)
Spectral series: LymanFalls to n = 1; UV region
Spectral series: BalmerFalls to n = 2; Visible region

Frequently asked questions

Why do Cr and Cu have exceptional electronic configurations?

Chromium (Z=24) has [Ar] 3d⁵ 4s¹ instead of the expected [Ar] 3d⁴ 4s². Copper (Z=29) has [Ar] 3d¹⁰ 4s¹ instead of [Ar] 3d⁹ 4s². In both cases, one electron shifts from 4s to 3d to achieve the extra stability of a half-filled (3d⁵) or fully-filled (3d¹⁰) d subshell. This stability comes from spherical symmetry of the electron cloud and maximum exchange energy.

What is the difference between a shell, subshell, and orbital?

A shell is a main energy level described by the principal quantum number n (K=1, L=2, M=3, ...). Each shell contains one or more subshells described by the azimuthal quantum number l (s, p, d, f). Each subshell contains one or more orbitals described by the magnetic quantum number ml. An orbital is the smallest unit: a region of space that can hold at most 2 electrons with opposite spins.

How do you identify which spectral series a transition belongs to?

The series is determined by the lower energy level (n₁) to which the electron falls. Lyman: n₁=1 (UV). Balmer: n₁=2 (visible). Paschen: n₁=3 (IR). Brackett: n₁=4 (IR). Pfund: n₁=5 (far IR). The first line of each series corresponds to the transition from n₂=(n₁+1) to n₁.

What does Heisenberg's uncertainty principle really mean?

It means you cannot simultaneously know both the exact position and exact momentum of an electron. This is not a limitation of instruments. It is a fundamental quantum property: the more precisely you measure the position, the more the momentum becomes uncertain, and vice versa. For large objects like a cricket ball, the uncertainties are negligibly small. For electrons, they are significant enough to make the concept of a definite orbit meaningless.

How many radial nodes does a 3p orbital have?

Radial nodes = n − l − 1. For 3p: n=3, l=1. Radial nodes = 3−1−1 = 1. Angular nodes = l = 1. Total nodes = n−1 = 2. So a 3p orbital has 1 radial node and 1 angular node (a nodal plane).

What is the maximum number of electrons in the n=4 shell?

Maximum electrons = 2n² = 2(4²) = 32. The n=4 shell contains the 4s (2 electrons), 4p (6 electrons), 4d (10 electrons), and 4f (14 electrons) subshells, totalling 32 electrons.

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