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The p-Block Elements

The p-Block ElementsNEET Chemistry · Class 12 · NCERT Chapter 13

Group 15: Nitrogen Family

Group 15 elements are nitrogen (N), phosphorus (P), arsenic (As), antimony (Sb), and bismuth (Bi). The general valence shell configuration is ns² np³, with three half-filled p orbitals. This half-filled configuration gives these elements extra stability, which is why they have higher ionization energies than their neighbours (Group 14 and Group 16).

Key Physical Properties

ElementSymbolAtomic numberState at 25°CCharacter
NitrogenN7Gas (N2)Non-metal
PhosphorusP15Solid (P4 or polymeric)Non-metal
ArsenicAs33Solid (sublimes)Metalloid
AntimonySb51Solid (metal-like)Metalloid
BismuthBi83Solid (metal)Metal

Oxidation States

All Group 15 elements show oxidation states of -3, +3, and +5. The -3 state is found in ionic hydrides and covalent hydrides (NH3, PH3). The +3 and +5 states are found in halides and oxoacids.

Important trend: inert pair effect. Going down the group, the +5 oxidation state becomes less stable and +3 becomes more stable. This is because the ns² electrons become increasingly reluctant to participate in bonding as you go down the group (due to poor shielding by the intervening d and f electrons). Bismuth shows +3 almost exclusively in its stable compounds.

Why Nitrogen is Anomalous

Nitrogen differs from the rest of Group 15 in several ways:

  • No pentavalent halides: N cannot form NF5 or NCl5 because nitrogen is in period 2 and has no d orbitals. It cannot expand its octet. Phosphorus can form PCl5 because P has available 3d orbitals (sp3d hybridization).
  • Forms p-p pi bonds: N forms strong multiple bonds (N≡N, C=N, N=O) using 2p orbitals that overlap effectively. Heavier elements (P, As) prefer single bonds and show catenation differently.
  • No d orbitals: N cannot act as a Lewis acid in certain reactions where P can (e.g., P forms adducts by using d orbitals).
  • High ionization energy: The half-filled 2p³ configuration of N is extra-stable, giving N a higher first ionization energy than even O.

Trends in Hydrides: NH3 to BiH3

HydrideBond angleBoiling pointStabilityBasicity
NH3107.8°-33°C (high, H-bonding)Most stableMost basic
PH393.6°-87.7°CStableWeak base
AsH391.8°-55°CModerately stableVery weak
SbH391.3°-17°CUnstableNegligible
BiH390.5°17°CLeast stableNegligible

NH3 has the highest boiling point because it forms hydrogen bonds (N-H...N). Bond angle decreases down the group as the lone pair is in a larger, more diffuse orbital and pushes less. Stability decreases down because the M-H bond strength decreases. Basicity decreases because the lone pair is less available (larger, more diffuse orbitals in heavier elements).

Nitrogen: Compounds and Reactions

Dinitrogen (N2)

Nitrogen exists as N2, held together by a very strong triple bond (N≡N, bond enthalpy = 945 kJ/mol). This makes N2 extremely unreactive at room temperature. To "fix" nitrogen (convert it to useful compounds), you need very high energy or special catalysts.

Haber Process (Synthesis of Ammonia)

The Haber process converts atmospheric nitrogen to ammonia, which is essential for fertilisers:

N2(g) + 3H2(g) ⇌ 2NH3(g) ΔH = -92 kJ/mol (exothermic)

ConditionValueReason
Temperature450-500°C (optimum)High T speeds the reaction (kinetics). Too high T shifts equilibrium left (Le Chatelier).
Pressure200-400 atmHigh P favours 2 mol product side. Increases yield (Le Chatelier: fewer moles of gas on right).
CatalystIron (Fe) with K2O and Al2O3 as promotersFe catalyst lowers activation energy. Promoters improve catalyst activity.

Properties of Ammonia (NH3)

Ammonia is a colourless, pungent gas with a characteristic smell. It is highly soluble in water: NH3 + H2O ⇌ NH4+ + OH- (alkaline solution). This makes litmus paper turn blue in the presence of NH3 vapour.

Reducing property: 4NH3 + 5O2 → 4NO + 6H2O (catalytic oxidation with Pt catalyst, used in Ostwald process for HNO3 manufacture).

Complexing property: NH3 acts as a Lewis base (electron pair donor) and forms complexes: Cu2+ + 4NH3 → [Cu(NH3)4]2+ (deep blue colour, Schweitzer's reagent).

Oxides of Nitrogen

OxideOS of NCommon NameNatureKey Facts
N2O+1Nitrous oxide (laughing gas)NeutralAnaesthetic; supports combustion
NO+2Nitric oxideNeutralFree radical (odd electron); brown in NO2 mixture
N2O3+3Dinitrogen trioxideAcidicAnhydride of HNO2; unstable
NO2+4Nitrogen dioxide (brown gas)AcidicParamagnetic; dimerises to N2O4
N2O5+5Dinitrogen pentoxideAcidicIonic solid [NO2+][NO3-]; anhydride of HNO3

Nitric Acid (HNO3): Ostwald Process

HNO3 is made industrially by the Ostwald process:

  1. Step 1: 4NH3 + 5O2 → 4NO + 6H2O (Pt catalyst, 850°C)
  2. Step 2: 2NO + O2 → 2NO2
  3. Step 3: 4NO2 + O2 + 2H2O → 4HNO3

Concentrated HNO3 is a powerful oxidising agent. It reacts with most metals (except platinum and gold). With copper: 3Cu + 8HNO3(dil.) → 3Cu(NO3)2 + 2NO + 4H2O. With concentrated HNO3: Cu + 4HNO3(conc.) → Cu(NO3)2 + 2NO2 + 2H2O. Zinc dissolves in very dilute HNO3 to give N2O or NH4NO3. Aqua regia (3 parts HCl + 1 part HNO3 conc.) dissolves gold and platinum.

Oxoacids of Nitrogen

AcidFormulaOS of NProperties
Hyponitrous acidH2N2O2+1Weak, unstable
Nitrous acidHNO2+3Weak acid, unstable. Oxidiser and reducer.
Nitric acidHNO3+5Strong acid, powerful oxidiser

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Phosphorus: Allotropes and Compounds

Allotropes of Phosphorus

Phosphorus has several allotropes. The three main ones tested in NEET are:

White Phosphorus (P4)

White phosphorus consists of discrete P4 molecules with a tetrahedral structure. Each P atom is bonded to the other three, with bond angles of only 60°. This causes severe ring strain (normal sp3 bond angle is 109.5°), making white P highly reactive.

  • Waxy, white/yellow solid. Translucent.
  • Soft. Melting point 44°C.
  • Extremely toxic. Causes severe burns.
  • Ignites spontaneously in air above 30°C (pyrophoric).
  • Glows in the dark (chemiluminescence) due to slow oxidation.
  • Stored under water to prevent contact with air.
  • Soluble in CS2 (carbon disulfide).

Red Phosphorus

Red phosphorus is formed by heating white P at 250°C in the absence of air. It is a polymeric form where P4 units are linked into long chains by covalent bonds. There are no discrete small molecules.

  • Red, amorphous powder. Denser than white P.
  • Stable in air up to 260°C. Does not ignite spontaneously.
  • Non-toxic. Used on the striking surface of safety match boxes.
  • Insoluble in CS2 (unlike white P).
  • Melting point: decomposes at about 400°C (converts back to white P then vaporises).

Black Phosphorus

Black phosphorus is the most stable and least reactive allotrope. It is formed by heating white phosphorus under very high pressure. It has a layered structure similar to graphite, with each P atom bonded to three neighbours in corrugated layers.

  • Black solid, resembles graphite in appearance.
  • Semiconductor. Layers held by van der Waals forces.
  • Thermodynamically most stable. Least reactive.
  • A 2D layer called phosphorene (analogous to graphene) is obtained from black P.
PropertyWhite PRed PBlack P
StructureP4 tetrahedral moleculePolymeric chainsLayered (graphite-like)
ColourWhite/yellowRedBlack
ReactivityVery high (ignites in air)ModerateLeast reactive
StabilityLeast stableMore stableMost stable (thermodynamically)
Solubility in CS2SolubleInsolubleInsoluble
ToxicityHighly toxicNon-toxicNon-toxic
UsesUsed in synthesis (historically in matches)Safety matches, flame retardantsResearch in 2D materials

Halides of Phosphorus

Phosphorus forms two important chlorides: PCl3 and PCl5.

PCl3 (Phosphorus trichloride)

P is sp3 hybridized in PCl3. It has 3 bond pairs and 1 lone pair. Geometry is trigonal pyramidal, similar to NH3. Bond angle is about 100°.

PCl3 + 3H2O → H3PO3 + 3HCl (hydrolysis gives phosphorous acid).

PCl5 (Phosphorus pentachloride)

P is sp3d hybridized in PCl5. It has 5 bond pairs and 0 lone pairs. Geometry is trigonal bipyramidal. There are two types of bonds:

  • 3 equatorial P-Cl bonds: bond angle 120°. Shorter and stronger.
  • 2 axial P-Cl bonds: bond angle 90° with equatorial, 180° with each other. Longer and weaker (more repulsion from equatorial bonds).

PCl5 + H2O → POCl3 + 2HCl (partial hydrolysis). PCl5 + 4H2O → H3PO4 + 5HCl (complete hydrolysis gives phosphoric acid).

In the solid state, PCl5 exists as [PCl4]+ [PCl6]- (ionic), not as covalent PCl5.

Oxoacids of Phosphorus

AcidFormulaOS of PBasicityStructure highlight
Hypophosphorous acidH3PO2+1Monobasic2 P-H bonds (non-ionizable), 1 P-OH bond (acidic), 1 P=O
Phosphorous acidH3PO3+3Dibasic1 P-H bond (non-ionizable), 2 P-OH bonds (both acidic), 1 P=O
Orthophosphoric acidH3PO4+5TribasicNo P-H bond, 3 P-OH bonds (all acidic), 1 P=O
Pyrophosphoric acidH4P2O7+5TetrabasicTwo PO4 units joined by P-O-P linkage. 4 P-OH groups.
Metaphosphoric acid(HPO3)n+5Monobasic (per unit)Cyclic or chain structure

Key rule for basicity of P oxoacids: only the OH groups directly bonded to P are acidic. Any P-H bond is NOT acidic (the hydrogen is not ionizable). So count the P-OH groups to find basicity.

Group 16: Oxygen Family

Group 16 elements are oxygen (O), sulphur (S), selenium (Se), tellurium (Te), and polonium (Po). The general valence shell configuration is ns² np⁴. They commonly show -2 oxidation state (in binary compounds). Heavier elements can expand their octets and show +4 and +6 oxidation states.

Why Oxygen is Anomalous

  • No d orbitals: Oxygen (period 2) cannot expand its octet. It shows only -2 and exceptionally +2 (in OF2) oxidation states.
  • High electronegativity: O is the second most electronegative element (after F). This is why water has such a high boiling point (H-bonding).
  • Small size: O forms strong double bonds (O=O in O2, C=O, S=O) using 2p orbitals. Heavier S, Se, Te prefer single bonds with lone pairs.
  • Allotropy: Oxygen has two allotropes: O2 (dioxygen, the common form) and O3 (ozone).

Ozone (O3)

Ozone is an allotrope of oxygen. Its structure has resonance: O-O=O (with a lone pair on the central O). The O-O-O bond angle is 116.8°. The central O is sp2 hybridized. It is a bent molecule.

Preparation: O2 + electrical discharge → O3 (by electrolytic method: in the ozoniser). O3 is formed in the upper atmosphere when UV radiation breaks O2: O2 + UV → 2O; O + O2 → O3.

Properties: Ozone is a powerful oxidising agent. It decomposes to give nascent oxygen: O3 → O2 + [O]. It bleaches by oxidation. It liberates iodine from KI: O3 + 2KI + H2O → 2KOH + I2 + O2 (test for ozone). It also bleaches indigo dye.

Ozone layer: The ozone layer (15-40 km altitude, stratosphere) absorbs harmful UV-B and UV-C radiation. CFCs (chlorofluorocarbons) and nitrogen oxides destroy ozone through catalytic cycles. One Cl atom can destroy over 100,000 ozone molecules.

Hydrogen Peroxide (H2O2)

H2O2 is a pale blue liquid in pure form. Structure: non-planar with O-O bond. The dihedral angle between the two O-H groups is about 111.5° in the liquid.

Preparation (industrial): autoxidation of 2-ethylanthraquinol.

Oxidising property: H2O2 + 2I- + 2H+ → I2 + 2H2O (oxidizes iodide in acidic medium). It acts as an oxidiser in acidic and basic media.

Reducing property: 2MnO4- + 5H2O2 + 6H+ → 2Mn2+ + 5O2 + 8H2O (H2O2 reduces permanganate in acidic medium). So H2O2 is amphoteric with respect to redox (acts as both oxidiser and reducer).

Bleaching: H2O2 bleaches hair and fabrics by oxidation (nascent O from decomposition).

Disproportionation: 2H2O2 → 2H2O + O2 (catalysed by MnO2, dust, or base). Store in dark bottles to prevent catalytic decomposition.

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Sulphur: Allotropes and Oxoacids

Allotropes of Sulphur

Sulphur has two important crystalline allotropes:

Rhombic Sulphur (alpha-S)

  • Stable form at room temperature (below 96°C).
  • Yellow crystals with rhombic (orthorhombic) unit cell.
  • Consists of crown-shaped S8 rings, puckered, with S-S-S angle 108°.
  • Melting point: 114°C. Density: 2.06 g/cm3.
  • Insoluble in water. Soluble in CS2.

Monoclinic Sulphur (beta-S)

  • Stable above 96°C (transition temperature) up to 119°C.
  • Needle-like monoclinic crystals, pale yellow.
  • Also consists of S8 rings but different crystal packing.
  • Melting point: 119°C. Density: 1.98 g/cm3.
  • Converts back to rhombic S below 96°C.

Plastic Sulphur

  • Formed by pouring boiling S into cold water.
  • Amorphous, elastic (rubbery) solid. Long chains of S atoms.
  • Metastable: slowly reverts to rhombic S on standing.

Sulphur Dioxide (SO2)

SO2 is produced when S burns in air: S + O2 → SO2. It is also produced in the roasting of sulfide ores: 2ZnS + 3O2 → 2ZnO + 2SO2.

Structure: SO2 is bent (angular), bond angle 119°. S is sp2 hybridized. There is a resonance structure with both S=O and S-O bonds.

Properties: Pungent smell. Acidic oxide (anhydride of H2SO3). A reducing agent: bleaches by reducing colored compounds, unlike Cl2 which bleaches by oxidation. The bleaching by SO2 is temporary (the colorless reduced compound can be re-oxidized).

Sulphuric Acid (H2SO4): Contact Process

H2SO4 is made industrially by the contact process:

  1. S + O2 → SO2 (burning sulphur or roasting pyrite)
  2. 2SO2 + O2 ⇌ 2SO3 (catalyst: V2O5, 450-500°C, 1-2 atm)
  3. SO3 + H2SO4 → H2S2O7 (SO3 absorbed in 98% H2SO4, forms oleum)
  4. H2S2O7 + H2O → 2H2SO4 (oleum diluted with water)

Note: SO3 cannot be dissolved directly in water because the reaction is too vigorous and produces a fine acidic mist. It is first absorbed in concentrated H2SO4 to form oleum.

Properties of Concentrated H2SO4

Concentrated H2SO4 (98%, density 1.84 g/mL) is a colourless, oily, dense liquid.

  • Strong acid: In water it fully ionises. First dissociation is complete; second is partial (Ka2 = 0.012).
  • Dehydrating agent: Removes water from organic compounds. Charcoal forms from sugar: C12H22O11 → 12C + 11H2O (conc. H2SO4 removes H2O from sucrose). Absorbs water of crystallization from CuSO4.5H2O to give white anhydrous CuSO4.
  • Oxidising agent: Hot concentrated H2SO4 oxidises metals and non-metals. Cu + 2H2SO4(hot, conc.) → CuSO4 + SO2 + 2H2O. S + 2H2SO4(hot, conc.) → 3SO2 + 2H2O.
  • Mixing with water is exothermic: Always add acid to water (not water to acid) to prevent localised boiling and splashing.

Oxoacids of Sulphur

AcidFormulaOS of SStructure notes
Sulphurous acidH2SO3+4Pyramidal SO3 unit; weak acid
Sulphuric acidH2SO4+6Tetrahedral SO4; strong, diprotic
Oleum (pyrosulphuric acid)H2S2O7+6Two SO4 units joined by S-O-S; stronger than H2SO4
Peroxodisulphuric acidH2S2O8+6Contains O-O peroxy linkage (-O-O-); very strong oxidiser
Thiosulphuric acidH2S2O3+2 (average)One S replaces an O in sulphate; used in photography (hypo)
Dithionic acidH2S2O6+5 (average)S-S direct bond

Group 17: Halogens

Group 17 elements are fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At). The general valence configuration is ns² np⁵. They need one electron to complete their octet, which is why they are excellent oxidising agents and form -1 ions readily. All halogens are non-metals; astatine is radioactive.

Trends in Physical Properties

PropertyFClBrI
Physical state at 25°CPale yellow gasGreenish-yellow gasReddish-brown liquidViolet-black solid
Melting point (°C)-220-101-7.3114
Boiling point (°C)-188-3459184
Bond length (X-X, pm)143199228267
Bond energy (kJ/mol)159243192151
Electronegativity4.03.02.82.5

Bond Dissociation Energy Anomaly of F2

You might expect bond energy to decrease smoothly from F2 to I2 (as bond length increases). However, F2 (159 kJ/mol) has a LOWER bond dissociation energy than Cl2 (243 kJ/mol). This is a major NEET anomaly.

Reason: Fluorine atoms are very small. In the F2 molecule, the two F atoms are so close that their lone pairs (all three of them on each F) are also very close together. These lone pairs repel each other strongly, weakening the F-F bond. In Cl2, Br2, and I2, the atoms are larger so the lone pairs are further apart and the repulsion is less. This extra lone pair repulsion in F2 is why the F-F bond is weaker than expected.

Boiling Point Order of Hydrogen Halides

The boiling points are: HF (19.5°C) >> HI (-35.4°C) > HBr (-66.8°C) > HCl (-85.1°C).

Why HF is anomalous: Fluorine is the most electronegative element. The H-F bond is very polar, and HF molecules form strong intermolecular hydrogen bonds (F-H...F). These H-bonds require a lot of energy to break, giving HF a very high boiling point. HCl, HBr, and HI cannot form significant H-bonds. Their boiling points follow molecular mass order: HCl (lowest MW) to HI (highest MW) due to increasing van der Waals forces.

Acid Strength of HX

In water, the acid strength order is: HF << HCl < HBr < HI.

HF is a weak acid in water (pKa = 3.2), while HCl, HBr, and HI are strong acids. The H-F bond is so strong that it does not dissociate completely in water. Going from HCl to HI, the H-X bond gets weaker and the acid gets stronger.

Reducing power of HX: The reducing power order is HF < HCl <HBr < HI. HI is the strongest reducing agent because it has the weakest H-I bond. HF cannot reduce even MnO4- or MnO2, but HI can.

Reactions of Halogens

Displacement reactions: A more reactive halogen displaces a less reactive one. F2 displaces Cl-, Br-, I-. Cl2 displaces Br- and I-. Br2 displaces only I-.

Cl2 + 2KBr → 2KCl + Br2 Cl2 + 2KI → 2KCl + I2 Br2 + 2KI → 2KBr + I2

Important Compounds of Halogens

Bleaching Powder (Ca(OCl)Cl)

Prepared by passing Cl2 over dry slaked lime at 40°C: 2Ca(OH)2 + 2Cl2 → Ca(OCl)Cl + CaCl2 + 2H2O. Bleaching powder is actually Ca(OCl)Cl, not pure Ca(OCl)2. The active bleaching component is the hypochlorite ion (OCl-), which releases nascent O in acid medium.

Chlorine Water

Cl2 + H2O ⇌ HCl + HOCl. Chlorine water is acidic and a weak bleach due to hypochlorous acid (HOCl). HOCl releases [O] on exposure to light, which oxidises and bleaches coloured materials.

Sodium Hypochlorite (NaOCl)

NaOH + Cl2(cold) → NaCl + NaOCl + H2O. Used in household bleach (Javelle water). Also used for disinfecting swimming pools.

Iodine Extraction from Seaweed

Seaweed is burnt, and the ash (containing NaI and KI) is treated with Cl2: Cl2 + 2NaI → 2NaCl + I2. Iodine can be purified by sublimation.

Oxoacids of Halogens (Chlorine series)

AcidFormulaOS of ClStabilityAcid strengthOxidising power
Hypochlorous acidHOCl+1Weakest (unstable)WeakestStrongest oxidiser
Chlorous acidHClO2+3UnstableWeakStrong
Chloric acidHClO3+5Moderately stableStrongModerate
Perchloric acidHClO4+7Most stableStrongest (strongest acid)Weakest oxidiser

Key point for NEET: As the number of oxygen atoms increases, acid strength increases (more electron withdrawal makes the O-H bond more polar, easier to donate H+). But oxidising power decreases as the OS of Cl increases (Cl is already in a high oxidation state, less tendency to be reduced further).

p-Block elements

Oxide Nature Predictor

Select a p-block element to see all its oxides, their nature (acidic, basic, amphoteric, neutral), reaction with water, and NEET notes. Covers N, P, S, Cl, As, Sb, and Bi oxides.

acidic

basic

amphoteric

neutral

N

Group 15

P

Group 15

S

Group 16

Cl

Group 17

As

Group 15

Sb

Group 15

Bi

Group 15

N2O
NO
N2O3
NO2
N2O5

N2O

Nitrous oxide (laughing gas)

Neutral oxide

Oxidation state

N: +1

Nature

neutral

Reaction with water

Does not react with water. Neither acidic nor basic.

NEET note

Used as anaesthetic. "Laughing gas." Only neutral oxide of N in NCERT.

All oxides of Nitrogen

N2O

neutral

N: +1

NO

neutral

N: +2

N2O3

acidic

N: +3

NO2

acidic

N: +4

N2O5

acidic

N: +5

Interhalogen Compounds

Interhalogen compounds are formed between two different halogen atoms. The general formula is XYn where X is the larger (heavier, less electronegative) halogen, Y is the smaller (lighter, more electronegative) halogen, and n = 1, 3, 5, or 7.

Why They Form

Interhalogens are more reactive than the parent halogens because the X-Y bond is weaker than X-X or Y-Y bonds (it is a polar bond with less effective overlap). The heavier halogen has available d orbitals, allowing it to accommodate more than 4 bonds.

Types and Structures

TypeExamplesHybridization of XShapeLone pairs on X
XY (1 bond)ClF, BrF, BrCl, ICl, IBrsp3 (each atom)Linear (diatomic)3 LP
XY3 (3 bonds)ClF3, BrF3, IF3sp3dT-shaped (2 LP equatorial)2 LP
XY5 (5 bonds)ClF5, BrF5, IF5sp3d2Square pyramidal (1 LP)1 LP
XY7 (7 bonds)IF7 (only)sp3d3Pentagonal bipyramidal0 LP

Notable Points on Interhalogen Structures

  • ClF3 and BrF3 (XY3): T-shaped. sp3d hybridization gives a trigonal bipyramidal electron geometry. The 2 lone pairs occupy the equatorial positions (less repulsion with bonds at 90°). The 3 F atoms go axial (1) and equatorial (2). Result: T-shape with bond angles close to 90° and 180°.
  • BrF5 and ClF5 (XY5): Square pyramidal. sp3d2 hybridization gives an octahedral electron geometry. 1 lone pair occupies one position. The other 5 positions are bonded to F. Result: square pyramidal shape.
  • IF7 (XY7): Pentagonal bipyramidal. sp3d3 hybridization. Only IF7 exists in this type because only iodine is large enough to accommodate 7 bonds with the small F atoms.

Properties of Interhalogen Compounds

  • They are all reactive oxidising agents and halogenating agents.
  • They react with water to give halide and oxyhalide acids.
  • ICl (iodine monochloride) is used for the Wij's test (detecting C=C bonds in fats, Wij's solution).
  • Many are used as fluorinating agents in industrial processes (e.g., ClF3 for uranium hexafluoride preparation in nuclear industry).

Group 18: Noble Gases

Group 18 elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). They have completely filled valence shells: He is 1s², all others have ns² np⁶. This gives them exceptional stability and very low chemical reactivity, hence the older name "inert gases."

Occurrence and Discovery

Noble gases were discovered in the late 19th and early 20th century:

  • Argon (Ar): Discovered by Rayleigh and Ramsay (1894). Most abundant noble gas (0.93% of air).
  • Helium (He): First detected spectroscopically in the sun by Lockyer (1868) before being found on Earth.
  • Neon, Krypton, Xenon: Found by Ramsay and Travers (1898).
  • Radon: Discovered as a radioactive decay product.

Physical Properties

ElementSymbolBoiling point (°C)Uses
HeliumHe-269 (lowest of all)Filling airships and balloons (non-flammable), cryogenics (liquid He for MRI), diving mixtures (heliox)
NeonNe-246Neon signs and advertising lights (red-orange glow), TV tubes
ArgonAr-186Filling light bulbs and fluorescent tubes (prevents filament oxidation), inert atmosphere for welding and metallurgy
KryptonKr-153High-intensity lamps (krypton-arc lamps), lasers, double-pane windows insulation
XenonXe-108Xenon flash lamps, high-intensity discharge lamps (car headlights), general anaesthetic (expensive), nuclear research
RadonRn-62Radioactive. Used in cancer radiotherapy (historically). Now mostly considered a health hazard in buildings.

Noble Gas Compounds (Xenon Fluorides)

For a long time, noble gases were considered completely unreactive. In 1962, Neil Bartlett synthesised the first noble gas compound: Xe[PtF6]. This was followed by the synthesis of xenon fluorides. Among the noble gases, only xenon and krypton form well-characterised compounds (radon too, but it is radioactive).

Xenon Fluorides

CompoundPreparationHybridization of XeShapeLone pairs on Xe
XeF2Xe + F2 (Xe excess, 400°C, 1 atm)sp3dLinear (3 LP equatorial)3 LP
XeF4Xe + F2 (1:5 ratio, 400°C, 6 atm)sp3d2Square planar (2 LP axial)2 LP
XeF6Xe + F2 (1:20 ratio, 300°C, 60 atm)sp3d3Distorted octahedral (1 LP)1 LP

Hydrolysis of Xenon Fluorides

XeF2 + H2O: 2XeF2 + 2H2O → 2Xe + 4HF + O2 (complete hydrolysis in excess water).

XeF4 + H2O (partial hydrolysis): 6XeF4 + 12H2O → 4Xe + 2XeO3 + 24HF + 3O2.

XeF6 + H2O: XeF6 + 3H2O → XeO3 + 6HF. Xenon trioxide XeO3 is formed. With excess NaOH: XeO3 + 2NaOH → Na2XeO4 + H2O (sodium perxenate).

Other Xenon Compounds

CompoundShapeHybridizationNotes
XeO3Pyramidalsp3Strongly oxidising; forms xenate salts with base
XeOF4Square pyramidalsp3d21 O and 4 F around Xe; explosive
XeO2F2See-sawsp3d2 O and 2 F; volatile liquid
XeO4Tetrahedralsp3Xe in +8 state; unstable

Why Are Noble Gas Compounds Rare?

Noble gases have fully filled valence shells (ns2 np6 for Ne through Rn), so they have no tendency to gain or lose electrons. They do not form ionic bonds easily. Their ionization energies are the highest in each period. However, the heavier noble gases (Kr, Xe) have larger atomic radii and their electrons are farther from the nucleus, making it easier to distort the electron cloud. Combined with very electronegative atoms like F and O (which can accept the electron density), Xe can form compounds. He and Ne have no known stable compounds because their IEs are too high.

Worked NEET Problems

1

NEET-style problem · Noble Gases

Question

Determine the hybridization, number of lone pairs on Xe, and shape of (a) XeF2, (b) XeF4, (c) XeF6.

Solution

(a) XeF2: Xe has 8 valence electrons. 2 bonds to F use 2 electrons. Remaining 6 electrons = 3 lone pairs. Total electron pairs = 2 + 3 = 5. Hybridization = sp3d. Electron geometry: trigonal bipyramidal. Lone pairs go to equatorial positions (3 lone pairs equatorial). 2 F atoms go to axial positions. Molecular shape: linear. Bond angle: 180°.

(b) XeF4: 4 bonds to F use 4 electrons. Remaining 4 electrons = 2 lone pairs. Total = 4 + 2 = 6. Hybridization = sp3d2. Electron geometry: octahedral. 2 lone pairs go to opposite axial positions (most stable arrangement). 4 F atoms are in the equatorial plane. Molecular shape: square planar.

(c) XeF6: 6 bonds to F use 6 electrons. Remaining 2 electrons = 1 lone pair. Total = 6 + 1 = 7. Hybridization = sp3d3. Electron geometry: pentagonal bipyramidal (distorted). 1 lone pair creates a distortion. Molecular shape: distorted octahedral (or capped octahedron).

2

NEET-style problem · Oxoacids of Phosphorus

Question

Identify the number of acidic hydrogen atoms in each: (a) H3PO2, (b) H3PO3, (c) H3PO4. Explain with their structural features.

Solution

Rule: Only P-OH hydrogen atoms are acidic. P-H hydrogen atoms are NOT acidic (they cannot ionise).

(a) H3PO2 (hypophosphorous acid): Structure has 1 P=O, 1 P-OH, and 2 P-H bonds. Acidic H = 1 (monobasic). Even though formula shows 3 H atoms, only 1 is OH-bonded to P.

(b) H3PO3 (phosphorous acid): Structure has 1 P=O, 2 P-OH, and 1 P-H bond. Acidic H = 2 (dibasic). The 1 P-H is non-ionisable.

(c) H3PO4 (phosphoric acid): Structure has 1 P=O and 3 P-OH bonds. No P-H bond. Acidic H = 3 (tribasic). All 3 OH groups ionise (Ka1 >> Ka2 >> Ka3).

3

NEET-style problem · Halogens

Question

Arrange HF, HCl, HBr, and HI in increasing order of (a) acid strength in water, (b) reducing power, (c) boiling point.

Solution

(a) Acid strength in water: HF << HCl < HBr < HI. HF is a weak acid (H-F bond very strong). HCl, HBr, HI are all strong acids. Among the strong acids: HI is strongest (weakest H-I bond, most easily dissociated).

(b) Reducing power: HF < HCl < HBr < HI. The reducing power depends on the ease of breaking the H-X bond. Bond strength order is HF > HCl > HBr > HI. So HI, having the weakest bond, is the best reducing agent. HF cannot reduce oxidising agents under ordinary conditions.

(c) Boiling point: HCl < HBr < HI << HF. Note HF is anomalously high due to strong H-bonding. HCl, HBr, HI follow molecular mass order.

4

NEET-style problem · Contact Process

Question

In the contact process for manufacturing H2SO4, SO3 is NOT dissolved directly in water. Instead, it is first dissolved in concentrated H2SO4 to form oleum, which is then diluted. Explain why.

Solution

If SO3 is dissolved directly in water, the reaction SO3 + H2O → H2SO4 is highly exothermic and very rapid. This releases so much heat that it causes the water to boil and produces a fine mist of tiny H2SO4 droplets suspended in air. This mist is very difficult to condense and handle, and it is highly corrosive and dangerous to workers and equipment.

Instead, SO3 is dissolved in concentrated (98%) H2SO4: SO3 + H2SO4 → H2S2O7 (oleum). This is then carefully diluted with water: H2S2O7 + H2O → 2H2SO4. This two-step process avoids the mist problem, is safer to operate, and gives a controlled, concentrated H2SO4 product.

5

NEET-style problem · Interhalogen Compounds

Question

Predict the shape of ClF3 using VSEPR theory.

Solution

ClF3: Central atom is Cl. Cl has 7 valence electrons. 3 bonds to F use 3 electrons (3 bond pairs). Remaining = 7 - 3 = 4 electrons = 2 lone pairs. Total electron pairs on Cl = 3 (bond pairs) + 2 (lone pairs) = 5. Hybridization = sp3d.

Electron geometry: trigonal bipyramidal. To minimize repulsion, the 2 lone pairs go to the equatorial positions (180° from each other). The 3 F atoms go to: 1 equatorial position and 2 axial positions.

Molecular shape: T-shaped (the 3 F atoms form a "T" arrangement). The axial F-Cl-F angle is close to 180°, and each axial F makes an angle less than 90° with the equatorial F (due to lone pair repulsion pushing the axial bonds slightly inward). NEET answer: T-shaped.

Summary Cheat Sheet

Group 15: Key Points

TopicKey Fact
Valence configns2 np3 (half-filled p orbitals)
Oxidation states-3, +3, +5. N mainly -3 and +3/+5. Bi mainly +3 (inert pair effect)
N vs P pentahalidesN CANNOT form NF5 (no d orbitals). P forms PCl5 (3d available, sp3d)
N2 triple bondN≡N bond energy = 945 kJ/mol (very stable). Makes N2 unreactive.
Haber processN2 + 3H2 → 2NH3. Fe catalyst, 450°C, 200 atm.
Ostwald process4NH3 + 5O2 → 4NO + 6H2O (Pt, 850°C). Then NO → NO2 → HNO3.
White P structureP4 tetrahedral, 60° bond angle, very reactive, stored under water.
H3PO3 basicityDibasic (2 P-OH bonds; 1 P-H is non-ionizable).

Group 16: Key Points

TopicKey Fact
Valence configns2 np4. Common state -2. S, Se also +4, +6.
O anomalyNo d orbitals; only -2 and +2 (OF2). Cannot form +6 compounds.
Ozone structureBent molecule, bond angle 116.8°. Central O is sp2 hybridized.
SO2 vs SO3SO2: bent, sp2, anhydride of H2SO3. SO3: trigonal planar, sp2, anhydride of H2SO4.
Contact process catalystV2O5 (vanadium pentoxide), 450-500°C, for 2SO2 + O2 → 2SO3.
OleumH2S2O7 = SO3 dissolved in H2SO4. More reactive than H2SO4.
S allotropesRhombic (stable below 96°C) and monoclinic (stable 96-119°C). Both S8 rings.

Group 17 (Halogens): Key Points

TopicKey Fact
Valence configns2 np5. One electron needed for octet. Common state: -1.
ElectronegativityF (4.0) is HIGHEST of all elements. Decreases down: F > Cl > Br > I.
F2 bond energy anomalyF-F (159) LESS than Cl-Cl (243). Reason: lone pair repulsion in tiny F2 molecule.
HF boiling point anomalyHF (19.5°C) is highest due to H-bonding. Otherwise: HI > HBr > HCl.
HX reducing powerHI > HBr > HCl > HF. HI strongest reducer.
HX acid strengthHI > HBr > HCl >> HF. HF is weak acid.
Electron gain enthalpyCl > F (anomaly: F is too small, lone pair repulsion for incoming e-).
Bleaching powderCa(OCl)Cl. Made: 2Ca(OH)2 + 2Cl2 → Ca(OCl)Cl + CaCl2 + 2H2O.
Oxoacid strength orderHClO4 > HClO3 > HClO2 > HClO (more O = stronger acid).
Oxoacid oxidising powerHClO > HClO2 > HClO3 > HClO4 (more O = weaker oxidiser).

Group 18 (Noble Gases): Key Points

TopicKey Fact
Valence configns2 np6 (He: 1s2). Completely filled shells.
First noble gas compoundXe[PtF6], synthesised by Neil Bartlett in 1962.
XeF2sp3d, linear, 3 LP on Xe.
XeF4sp3d2, square planar, 2 LP on Xe.
XeF6sp3d3, distorted octahedral, 1 LP on Xe.
He usesAirships (non-flammable), MRI cryogenics, deep-sea diving.
Ar usesLight bulbs, welding (inert atmosphere).
Ne usesNeon signs (red-orange glow).

Interhalogen Compounds: Quick Reference

Formula typeHybridizationShapeLP on XExample
XYsp3Linear (diatomic)3ClF, ICl, IBr
XY3sp3dT-shaped2ClF3, BrF3
XY5sp3d2Square pyramidal1BrF5, IF5
XY7sp3d3Pentagonal bipyramidal0IF7 (only)

Must-Know Reactions for NEET

ReactionType / Significance
N2 + 3H2 → 2NH3Haber process (Fe catalyst, 450°C, 200 atm)
4NH3 + 5O2 → 4NO + 6H2OOstwald process Step 1 (Pt, 850°C)
2SO2 + O2 → 2SO3Contact process Step 2 (V2O5, 450°C)
PCl3 + H2O → H3PO3 + 3HClPCl3 hydrolysis gives phosphorous acid
PCl5 + 4H2O → H3PO4 + 5HClPCl5 hydrolysis gives phosphoric acid
2Ca(OH)2 + 2Cl2 → Ca(OCl)Cl + CaCl2 + 2H2OBleaching powder preparation
Cl2 + 2KI → 2KCl + I2Cl2 displaces I2 from KI (halogen displacement)
XeF4 + 2H2O → Xe + 4HF + O2 (not balanced)Partial hydrolysis of XeF4

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Frequently asked questions

What is the inert pair effect and why does it increase down Group 15?

The inert pair effect is the tendency of the outermost s-electrons (the ns² pair) to remain non-bonding in heavier elements. In Group 15, the common oxidation states are +5 and +3. As you go down the group from N to Bi, the +3 state becomes increasingly stable while the +5 state becomes less common. This happens because the 6s² electrons in Bi (and 5s² in Sb) are held tightly by poor shielding from d and f electrons below them, making them harder to use for bonding. So bismuth mainly shows +3, and nitrogen mainly shows +5 (or -3). The trend: N (+5 most common) > P > As > Sb > Bi (+3 most stable).

Why does nitrogen not form pentahalides but phosphorus does?

Nitrogen cannot form pentahalides (such as NF5 or NCl5) because it does not have d orbitals available in its valence shell. Nitrogen is in period 2 and uses only s and p orbitals (maximum 4 bonds, octet rule). Phosphorus is in period 3 and has vacant 3d orbitals. These 3d orbitals can be used to expand the octet, allowing P to form five bonds. PCl5 and PF5 exist with sp3d hybridization of phosphorus. Similarly, N cannot form more than 4 bonds, but P can form up to 5. This is one of the key anomalous behaviors of nitrogen compared to the rest of Group 15.

What are the allotropes of phosphorus? Compare white, red, and black phosphorus.

White phosphorus: discrete P4 molecules with a tetrahedral structure. The bond angle is only 60°, which causes ring strain, making it highly reactive. It catches fire spontaneously in air above 30°C. It is waxy, soft, white/yellow, and extremely toxic. It glows in the dark (chemiluminescence). Red phosphorus: a polymeric form where P4 units are linked by covalent bonds into chains. No discrete small molecules. Much more stable than white P. Does not ignite spontaneously. Used in safety match boxes. Non-toxic. Black phosphorus: the most stable allotrope, made at high pressure. Has a layered structure like graphite. Least reactive. A semiconductor.

Explain the structures of PCl5 and SF6.

PCl5 structure: phosphorus is sp3d hybridized (5 bond pairs, 0 lone pairs). The geometry is trigonal bipyramidal. There are two types of bonds: three equatorial P-Cl bonds (bond angle 120°) and two axial P-Cl bonds (bond angle 90° with equatorial). The axial bonds are longer and weaker than equatorial bonds because axial bonding involves p orbitals with more repulsion. In the gas phase, PCl5 dissociates partly into PCl3 and Cl2. SF6 structure: sulfur is sp3d2 hybridized (6 bond pairs, 0 lone pairs). The geometry is perfectly octahedral (bond angle 90°). All six S-F bonds are equivalent. SF6 is chemically very inert because the large SF6 molecule prevents any reagent from approaching the central S atom (steric protection).

Why does HF have the highest boiling point among hydrogen halides, even though it has the lowest molecular mass?

The boiling point order among hydrogen halides is: HF (19.5°C) >> HI (-35.4°C) > HBr (-66.8°C) > HCl (-85.1°C). HF has an anomalously high boiling point because fluorine is the most electronegative element. The H-F bond is highly polar, and HF molecules form strong intermolecular hydrogen bonds (F-H...F). These hydrogen bonds require more energy to break, giving HF a much higher boiling point. HCl, HBr, and HI cannot form significant hydrogen bonds (Cl, Br, I are not electronegative enough to form strong H-bonds). Among HCl, HBr, and HI, the boiling point increases with molecular mass due to increasing van der Waals forces.

What are the key oxoacids of sulphur? Compare H2SO3, H2SO4, and oleum (H2S2O7).

H2SO3 (sulphurous acid): S is in +4 oxidation state. It is a weak diprotic acid formed when SO2 dissolves in water. It is a good reducing agent. H2SO4 (sulphuric acid): S is in +6 oxidation state. Strong diprotic acid. Made industrially by the contact process. Acts as an acid, dehydrating agent, and oxidising agent (concentrated). It reacts with water vigorously (exothermic). H2S2O7 (oleum or pyrosulphuric acid/disulphuric acid): formed when SO3 is dissolved in concentrated H2SO4. S is in +6. It is more strongly acidic and oxidising than H2SO4. Used industrially when making H2SO4 via the contact process. On adding water: H2S2O7 + H2O → 2H2SO4. Other oxoacids include H2S2O8 (peroxodisulphuric acid, S in +6 with peroxy linkage).

How does the ozone layer protect us and how is it destroyed?

The ozone layer (stratosphere, 15-40 km altitude) absorbs harmful UV-B and UV-C radiation from the sun before it reaches Earth. Without this shield, UV radiation would cause skin cancer, cataracts, and damage to ecosystems. Ozone absorbs UV: O3 + UV → O2 + O. The O atom recombines: O + O2 → O3. This cycle continuously absorbs energy. Destruction by CFCs: chlorofluorocarbons (Freons) release Cl atoms in the stratosphere: CF2Cl2 + UV → CF2Cl + Cl. The Cl atom acts as a catalyst: Cl + O3 → ClO + O2, then ClO + O → Cl + O2. Net: O3 + O → 2O2. One Cl atom can destroy thousands of O3 molecules. Nitrogen oxides (NOx from supersonic jets) also destroy ozone by a similar catalytic mechanism.

What are interhalogen compounds? Give examples and their structures.

Interhalogen compounds are compounds formed between two different halogens. The general formula is XYn where X is the heavier halogen and n = 1, 3, 5, or 7. They are more reactive than individual halogens (the X-Y bond is weaker than X-X or Y-Y because it is polar). Types: XY (ClF, BrF, BrCl, ICl, IBr) - linear. XY3 (ClF3 T-shaped sp3d hybridization 2 lone pairs, BrF3 T-shaped) - T-shaped geometry. XY5 (ClF5, BrF5 - square pyramidal sp3d2 hybridization with 1 lone pair, IF5) - square pyramidal. XY7 (IF7 only - pentagonal bipyramidal sp3d3 hybridization with 0 lone pairs). All interhalogen compounds are reactive oxidizing agents. ICl (iodine monochloride) can be used as a source of I+ ions in electrophilic iodination reactions.

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