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Alternating Current

Alternating CurrentNEET Physics · Class 12 · NCERT Chapter 7

Introduction

Alternating current (AC) reverses direction many times per second. Indian household mains is 50 Hz: the current changes direction 100 times every second. This chapter covers how V and I behave through R, L and C in AC circuits, what happens when you combine them, and how transformers change voltages.

Expect 1 to 2 NEET questions. Favourites: RMS values, AC across a single inductor or capacitor (phase), impedance and resonance of series LCR, transformer ratios.

AC voltage and current

Standard sinusoidal AC:

V_0 and I_0 are peak values. omega = 2 pi f is angular frequency. Phase phi depends on the type of element.

RMS, peak and average values

Mean of sin(omega t) over a full cycle is zero, but the RMS value (which controls heating) is not:

Mean over a half-cycle (full-wave rectified) is . When NEET says "220 V mains", that means RMS, so the peak is V_0 = 220 sqrt(2) ≈ 311 V.

For a sinusoidal AC, peak V_0 is the maximum value. Mean over a full cycle is zero. RMS = V_0 / sqrt(2). Mean over a half-cycle = 2 V_0 / pi.

Peak V_0: 311 V

Indian household mains: V_rms = 220 V, so V_0 ≈ 311 V.

RMS

219.91 V

Avg (full cycle)

0 V

Avg (half cycle)

197.99 V

AC through a resistor

Voltage and current in phase. For :

Power dissipated: .

AC through a pure resistor: voltage and current are exactly in phase. No phase shift.

Peak V₀: 10 V

R: 5 Ω

Peak I₀ = V₀/R = 2.00 A

Phase: 0 (in phase)

t

● V (solid)

● I (dashed)

AC through an inductor

Voltage leads current by π/2:

X_L is inductive reactance, in ohms. Higher frequency means higher reactance (inductor blocks AC at high f). Average power consumed by an ideal inductor over a cycle is zero.

AC through an inductor: V leads I by π/2 (90°). Reactance X_L = ω L grows with frequency.

L: 50 mH

V₀: 10 V

Frequency f: 50 Hz

X_L = ωL = 15.71 Ω

I₀ = V₀/X_L = 0.637 A

● V (leads)

● I (lags by π/2)

AC through a capacitor

Current leads voltage by π/2:

X_C is capacitive reactance. Higher frequency means LOWER reactance (capacitor passes AC at high f, blocks DC). Average power consumed by an ideal capacitor over a cycle is zero.

AC through a capacitor: I LEADS V by π/2 (90°). Reactance X_C = 1/(ω C) DROPS with frequency.

C: 10.00 µF

V₀: 10 V

Frequency f: 50 Hz

X_C = 1/(ωC) = 318.31 Ω

I₀ = V₀/X_C = 0.031 A

● V (lags)

● I (leads by π/2)

Memory hook: ELI the ICE man

In an inductor (L), E (voltage) leads I. In a capacitor (C), I leads E (voltage). ELI the ICE man.

Series LCR circuit

With R, L and C in series, total opposition (impedance):

Phase angle phi between V and I:

If X_L > X_C: voltage leads current (inductive). If X_C > X_L: voltage lags current (capacitive).

Series LCR: total opposition is the impedance Z. Phase angle phi between V and I depends on which reactance wins.

R: 10 Ω

L: 50 mH

C: 40.00 µF

f: 50 Hz

Impedance Z

64.65 Ω

X_L

15.71

X_C

79.58

cos φ

0.155

Phase φ = -81.1°. Capacitive (I leads V).

Resonance

At a special frequency, X_L = X_C, the reactances cancel, and Z reduces to R alone:

At resonance, current is maximum (V/R), and phase angle is zero. Quality factor Q measures the sharpness:

Used for tuning radios and TVs to a specific station.

At resonance, X_L = X_C. The reactive parts cancel; impedance equals R alone. Current is maximum at the resonance frequency.

L: 10.00 mH

C: 10.00 µF

R: 2 Ω

Resonance frequency

503.29 Hz

Quality factor Q

15.81

Practice these on the timed test

Try a free 10-question NEET mock test on Alternating Current, with instant results and no sign-up needed.

Power in AC circuits

Average power over a full cycle:

cos φ is the power factor. For a pure resistor: cos φ = 1, all power is real. For a pure L or C: cos φ = 0, no real power. Wattless current: I_rms sin φ flows but does no real work; only the in-phase component I_rms cos φ delivers real power.

Transformer

Two coils linked by a common iron core. AC current in the primary creates a changing flux that induces an EMF in the secondary:

For an ideal (lossless) transformer, P_p = P_s, so:

Step-up: more turns on secondary, voltage rises but current falls. Step-down: opposite. Real transformers lose energy to copper resistance, hysteresis and eddy currents (use laminated cores to reduce).

Ideal transformer: turns ratio sets the voltage ratio. Power in = power out (no losses).

Primary V_p: 220 V

Primary turns N_p: 1000

Secondary turns N_s: 50

Primary I_p: 2 A

Secondary V_s

11.0 V

Secondary I_s (ideal)

40.00 A

Power: P_p = 440 W, P_s = 440 W

Step-DOWN transformer

AC generator (brief)

A coil rotated in a magnetic field produces a sinusoidal EMF:

Slip rings carry the AC out to the external circuit. This is how power plants generate electricity at 50 Hz (or 60 Hz in some countries).

Worked NEET problems

1

NEET-style problem · RMS

Question

An AC source has peak voltage 100 V. Find V_rms.

Solution

2

NEET-style problem · Reactance

Question

Find the reactance of a 10 mH inductor at 50 Hz.

Solution

3

NEET-style problem · LCR

Question

R = 6 Ω, X_L = 8 Ω, X_C = 0. Find impedance and phase angle.

Solution

Inductive (X_L > X_C). V leads I by 53°.

4

NEET-style problem · Resonance

Question

Find the resonance frequency of a circuit with L = 4 mH and C = 1 µF.

Solution

5

NEET-style problem · Transformer

Question

Step-down: V_p = 220 V, N_p = 1100 turns, N_s = 100 turns. Find V_s and I_s if I_p = 0.5 A (ideal).

Solution

Power conserved: 220 × 0.5 = 20 × 5.5 = 110 W.

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Summary cheat sheet

  • RMS: .
  • Inductor: V leads I by π/2. .
  • Capacitor: I leads V by π/2. .
  • LCR impedance: .
  • Phase: .
  • Resonance: .
  • Q-factor: .
  • Power: .
  • Transformer: , .

Next: try the interactive widgets for AC through R/L/C, LCR impedance and transformer, or work through the 32 NEET PYQs with full solutions. To time yourself, take the free 10-question mock test.

Frequently asked questions

How many questions come from Alternating Current in NEET 2027?

You can expect 1 to 2 questions in NEET 2027. The chapter has high PYQ frequency. RMS values, AC through inductor or capacitor (phase relations), series LCR impedance and resonance, and transformers are favourites.

What is RMS value of an alternating current?

For a sinusoidal current i(t) equals i_0 sin(omega t), the RMS (root mean square) value is i_rms equals i_0 over square root 2 ≈ 0.707 i_0. The mean over a full cycle is zero, but the heating effect (proportional to i squared) is non-zero. RMS is the equivalent DC current that would dissipate the same power.

How does an inductor behave in an AC circuit?

In an inductor, voltage leads current by pi over 2 (90 degrees). Reactance X_L equals omega L equals 2 pi f L. Higher frequency means higher reactance. At very low f, an inductor acts like a wire; at very high f, like an open circuit.

How does a capacitor behave in an AC circuit?

In a capacitor, current leads voltage by pi over 2. Reactance X_C equals 1 over (omega C) equals 1 over (2 pi f C). Higher frequency means LOWER reactance. At very low f, a capacitor acts like an open circuit; at very high f, like a wire (DC blocks, AC passes).

What is impedance in a series LCR circuit?

Total opposition to AC: Z equals square root of R squared plus (X_L minus X_C) squared. Phase angle phi between voltage and current: tan phi equals (X_L minus X_C) over R. If X_L > X_C, voltage leads current (inductive). If X_C > X_L, voltage lags current (capacitive).

What is resonance in a series LCR circuit?

When omega_0 equals 1 over square root LC (so X_L equals X_C), impedance Z reduces to its minimum value R, and current is maximum equal to V over R. Phase angle phi equals 0; voltage and current are in phase. This is series resonance.

What is the working principle of a transformer?

A transformer uses two coils linked by a common iron core. Changing AC current in the primary coil produces a changing flux which induces an EMF in the secondary. Voltage ratio equals turns ratio: V_p over V_s equals N_p over N_s. For an ideal (lossless) transformer, V_p I_p equals V_s I_s, so I_s over I_p equals N_p over N_s. Step-up: more turns on secondary, voltage rises, current falls.

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