30 NEET previous-year questions on Atoms, each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.
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-13.6/n eV
-13.6/n² eV
-13.6 n eV
13.6/n² eV
Solution
eV.
n h
n h/2π
h/n
2πn h
Solution
.
0.529 Å
5.29 Å
52.9 Å
0.0529 Å
Solution
a_0 = 0.529 Å.
UV
Visible
IR
Microwave
Solution
Balmer series: visible region of H spectrum.
13.6 eV
10.2 eV
3.4 eV
27.2 eV
Solution
Ionisation energy = -E_1 = 13.6 eV.
486 nm
656 nm
434 nm
410 nm
Solution
H-alpha: 656.3 nm (red).
-13.6 eV
-3.4 eV
-1.51 eV
-0.85 eV
Solution
eV.
Atom is mostly empty space with a dense nucleus
Electrons revolve in shells
Energy is quantised
Wave nature of light
Solution
Most alphas pass through, few backscatter. Atom is mostly empty; positive charge in tiny nucleus.
n × a_0
n² × a_0
a_0/n
a_0/n²
Solution
.
-13.6 eV
-27.2 eV
-54.4 eV
-108.8 eV
Solution
eV.
n_1 = 1
n_1 = 2
n_1 = 3
n_1 = 4
Solution
Lyman series: transitions ending at n_1 = 1 (UV).
91.2 nm
102.6 nm
121.6 nm
364 nm
Solution
Series limit n_2 = ∞: nm.
13.6 eV
3.4 eV
10.2 eV
17.0 eV
Solution
eV.
1
n
2n
2π
Solution
wavelengths.
3
4
6
10
Solution
.
|E_n|
2 |E_n|
|E_n|/2
0
Solution
In Bohr orbit: KE = -E_n = +13.6/n² eV. PE = 2 E_n.
a_0
2 a_0
4 a_0
a_0/2
Solution
.
Lyman
Balmer
Paschen
Brackett
Solution
Hα (3→2), Hβ (4→2): Balmer series.
Charge of alpha
Z of target
KE of alpha
Mass of alpha
Solution
. No mass of alpha appears.
K = E
K = -E
K = 2E
K = E/2
Solution
KE = -E (PE = 2E, so total = E).
13.6 eV
27.2 eV
54.4 eV
108.8 eV
Solution
eV.
91.2 nm
121.6 nm
486 nm
656 nm
Solution
Longest = first transition: 2→1 → 121.6 nm.
Random
Quantised in angular momentum
Spiral
Elliptical
Solution
L = nℏ. Only certain orbits allowed.
4
5
10
20
Solution
.
-13.6 eV
-3.4 eV
-1.51 eV
-0.85 eV
Solution
eV.
Lyman
Balmer
Paschen
Brackett
Solution
To n_1 = 3: Paschen series (IR).
c/137
c/(137 n)
cn/137
137 c/n
Solution
for hydrogen.
Independent of Z
∝ 1/Z
∝ Z
∝ Z²
Solution
(and 1/E_k).
1:2
2:1
1:1
4:1
Solution
. v_1 : v_2 = 2 : 1.
Same
In UV
In visible
In IR
Solution
Lyman series → UV.
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