Introduction
Two strands meet here. First, light, which we have so far treated as a wave, also behaves like a stream of particles called photons in the photoelectric effect. Second, particles such as electrons, which we have so far treated as little balls, also have a wave nature. Wave-particle duality is a hard idea, but the chapter runs on a small set of formulas you can drill.
Expect 1 to 2 NEET questions every year. Common asks: stopping potential vs frequency line, KE_max from Einstein's equation, de Broglie wavelength of an electron through a potential V, and photon momentum from wavelength.
Hertz and Lenard observations
Hertz (1887) noticed that UV light made a spark gap conduct more easily. Lenard (1902) refined the experiment. The findings:
- Above a certain threshold frequency f_0, light ejects electrons from a metal (photoelectric effect).
- Below f_0, no electrons come out, no matter how bright the light.
- Number of photoelectrons rises with intensity. Maximum kinetic energy depends on frequency, not intensity.
- Emission is essentially instantaneous (less than 10⁻⁹ s).
Classical wave theory could not explain any of these. Einstein (1905) did, by proposing that light comes in discrete packets called photons.
Work function and threshold
The minimum energy needed to free an electron from a metal's surface is the work function W_0. The corresponding photon frequency is the threshold:
Caesium W_0 ≈ 2.14 eV (visible light is enough); platinum W_0 ≈ 6.35 eV (only deep UV works).
Einstein's photoelectric equation
A photon of energy h f hits an electron in the metal. If h f > W_0, the electron escapes with maximum kinetic energy:
The same photon can never "split" between two electrons. One photon, one electron. KE_max depends only on the frequency and the metal, not on intensity.
Pick a metal and a light wavelength. If photon energy exceeds the work function, electrons are ejected with KE = h f - W_0. The stopping potential V_0 directly gives KE_max in volts.
Metal:
Light λ: 300 nm (E_photon = 4.13 eV)
Photoelectric outcome
Electrons ejected
KE_max = 1.77 eV (2.84e-19 J)
Stopping potential V_0 = 1.77 V
Threshold for Sodium
f_0 = 5.71 × 10¹⁴ Hz
λ_0 = 525 nm
Stopping potential
Apply a reverse voltage V to push photoelectrons back. The smallest V that just stops the most energetic ones is the stopping potential:
So V_0 in volts equals KE_max in electronvolts. Above f_0, V_0 grows linearly with f.
Stopping potential rises linearly with frequency. Slope is h/e (universal). x-intercept is the threshold frequency f_0 = W_0 / h (depends on the metal).
Work function W_0: 2.50 eV
Slope (h/e)
4.136e-15 V·s
Threshold f₀
6.04 × 10¹⁴ Hz
Slope is universal: same h/e for every metal. Different metals share the same slope but cut the f-axis at different f_0.
Photoelectric graphs
NEET tests three graphs. Recognise each:
- Photo-current vs applied voltage: rises and saturates. Three curves for three intensities (same f) saturate at different I_sat but cross V-axis at the same -V_0.
- Saturation current vs intensity: straight line through origin (I_sat ∝ Intensity).
- KE_max (or V_0) vs frequency: parallel lines for different metals. Slope = h. x-intercept = f_0.
Toggle between the three NEET-favourite photoelectric graphs.
Photoelectric I vs V: at high positive V, current saturates; bigger intensity → bigger saturation. All curves intersect the V-axis at the same -V_0 (V_0 depends on frequency, not intensity).
Photons: energy and momentum
A photon is the quantum of EM radiation. Its energy and momentum:
Quick handle: E (in eV) × λ (in nm) ≈ 1240. So 620 nm light has photons of 2 eV; 124 nm UV has 10 eV photons.
Each photon carries energy E = h f and momentum p = h / λ. Quick mental check: E (in eV) × λ (in nm) ≈ 1240.
Wavelength λ: 550 nm
Frequency f
5.45e+14 Hz
Energy E
2.255 eV
3.61e-19 J
Momentum p = h/λ
1.20e-27 kg·m/s
Practice these on the timed test
Try a free 10-question NEET mock test on Dual Nature with instant results and no sign-up needed.
de Broglie wavelength of matter waves
Louis de Broglie (1924) proposed that matter, like light, has a wave nature. The wavelength is:
For everyday objects, λ is far too small to detect. For an electron at 100 eV, λ ≈ 0.123 nm, comparable to the spacing of atoms in a crystal, so it can show diffraction.
Every moving particle has a wave nature with λ = h / p. For everyday objects, λ is too small to detect; for electrons it is comparable to atomic spacings.
Particle:
Kinetic energy: 100 eV
(slider is log10 scale; use it for any energy from 0.01 eV to 1 MeV)
de Broglie λ
1.23e+2 pm
Momentum p
5.40e-24 kg·m/s
Speed v
5.93e+6 m/s
Electron accelerated through V volts
An electron starting at rest accelerated through V volts gains KE = eV. Its de Broglie wavelength:
At V = 100 V, λ = 1.23 Å. At V = 10 kV (electron microscope), λ = 0.123 Å. The shorter the wavelength, the finer the detail you can image. That is why electron microscopes outperform light microscopes.
An electron starting at rest accelerated through V volts gains KE = eV. Its de Broglie wavelength is: λ = 12.27 / √V Å.
Accelerating potential V: 100 V
de Broglie λ
1.227 Å
0.1227 nm
Kinetic energy gained
100 eV
Speed v (non-relativistic)
5.93e+6 m/s
= 1.98% of c
Davisson-Germer used 54 V → λ ≈ 1.67 Å. Bragg diffraction off nickel confirmed it; matter waves are real.
Davisson-Germer experiment
Davisson and Germer (1927) accelerated electrons through 54 V and scattered them off a nickel crystal. They found a sharp diffraction peak at scattering angle 50°. Using Bragg's law for nickel (d = 0.91 Å), the peak corresponds to wavelength 1.65 Å. de Broglie's formula gave 12.27 / √54 = 1.67 Å. Match. Matter waves are real.
This is the first direct experimental proof of the wave nature of electrons.
Wave-particle duality and a comparison
Both light and matter show wave behaviour (interference, diffraction) and particle behaviour (photons, point impacts). For a fixed energy, a photon is much "wider" than an electron because c is huge. For a fixed momentum, both have the same λ.
For the same energy, a photon and an electron have very different wavelengths. The photon is much "wider" because it travels at c, while the electron moves much more slowly.
Common energy E: 100 eV
Photon
λ = 1.24e+1 nm
Electron (KE = E)
λ = 1.23e+2 pm
Ratio λ_photon / λ_electron = 101× (electron always shorter for same E)
Worked NEET problems
NEET-style problem · Einstein equation
Question
Solution
NEET-style problem · Photon
Question
Solution
NEET-style problem · de Broglie
Question
Solution
NEET-style problem · Electron through V
Question
Solution
NEET-style problem · Threshold
Question
Solution
So green or shorter wavelengths cause photoemission from sodium; orange and red do not.
Track your accuracy on every chapter
Sign up free to see your chapter mastery, weak areas and predicted NEET score across all 90 NEET chapters.
Summary cheat sheet
- Einstein: .
- Stopping potential: .
- Threshold: , .
- Quick: E (eV) × λ (nm) ≈ 1240.
- Photon: E = hν, p = h/λ = E/c.
- de Broglie: .
- Electron through V: .
- I_sat: ∝ intensity. V_0: ∝ frequency (above f_0).
- V_0 vs f slope: h/e (universal).
Next: try the interactive widgets for the photoelectric equation, V_0-f line and de Broglie wavelength, or work through the 30 NEET PYQs with full solutions. To time yourself, take the free 10-question mock test.
Frequently asked questions
How many questions come from Dual Nature in NEET 2027?
You can expect 1 to 2 questions in NEET 2027. The chapter is small but reliable. Common asks: stopping potential vs frequency graph, KE_max calculation from Einstein's equation, de Broglie wavelength of an electron through a potential V, and photon momentum.
What is the photoelectric effect?
When light of high enough frequency strikes a metal surface, electrons are ejected. The ejected electrons are called photoelectrons. Below a threshold frequency f_0, no electrons are ejected no matter how intense the light. Above f_0, even very weak light ejects them instantly. Classical wave theory could not explain this; Einstein's photon idea did.
What is the work function of a metal?
Work function W_0 is the minimum energy needed to free an electron from a metal's surface. Different metals have different W_0. Caesium has a low W_0 (about 2 eV); platinum is much higher (about 6.4 eV). W_0 = h f_0, where f_0 is the threshold frequency.
State Einstein's photoelectric equation
h f = W_0 + KE_max. The photon's energy h f goes to overcoming the work function W_0 and giving the electron kinetic energy KE_max. Below f = f_0, h f is less than W_0 and no electrons come out.
What is the stopping potential?
V_0 is the smallest reverse voltage that stops the most energetic photoelectrons from reaching the collector. e V_0 = KE_max = h f - W_0. V_0 vs f is a straight line: slope = h / e (universal), x-intercept = f_0 (depends on metal).
How do photo-current vs intensity and vs frequency look?
Saturation photo-current rises linearly with intensity (more photons → more electrons). It is independent of frequency once above f_0. Stopping potential rises linearly with frequency and is independent of intensity.
What is the de Broglie wavelength?
lambda = h / p = h / (m v). Every moving particle has a wave nature, with wavelength inversely proportional to momentum. For a tennis ball, λ is far too small to detect. For an electron, it is comparable to atomic spacings, so it can show diffraction.
What is the de Broglie wavelength of an electron accelerated through V volts?
lambda = h over root (2 m e V) = 12.27 over root V angstroms (when V is in volts). For 100 V: lambda ≈ 1.23 angstrom. This was confirmed by Davisson and Germer's electron diffraction experiment.
What did Davisson and Germer find?
Electrons accelerated through 54 V were scattered by a nickel crystal and showed a clear diffraction peak at 50°, exactly as predicted by Bragg's law for wavelength 1.67 angstrom. This matched the de Broglie prediction and proved electrons behave as waves.
Why do we need the photon idea?
Classical waves cannot explain three things: existence of a threshold frequency, KE_max independent of intensity, and the instantaneous ejection of electrons. Einstein resolved all three by treating light as discrete photons of energy h f, each interacting one-on-one with one electron.
Continue with the next chapter notes
Stay in NCERT order — the next chapter's notes are one click away.
Track Your NEET Score Across All 90 Chapters
Free 14-day trial. AI tutor, full mock tests and chapter analytics — built for NEET 2027.
Free 14-day trial · No credit card required