32 NEET previous-year questions on Electromagnetic Induction, each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.
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tesla
weber
henry
volt
Solution
Φ in Wb (= T·m²).
Solution
. Negative sign comes from Lenz's law.
0.04 V
0.2 V
0.4 V
4 V
Solution
.
farad
henry
weber
tesla
Solution
Henry (H), defined by .
0.5 J
1 J
2.5 J
5 J
Solution
.
Conservation of charge
Conservation of energy
Conservation of momentum
Newton's third law
Solution
Lenz's law expresses energy conservation in induction.
0.5 V
1 V
2 V
5 V
Solution
.
No relation
Solution
Reciprocity: .
×1
×2
×4
×8
Solution
. ×4.
Solution
.
θ = 0° between B and area normal
θ = 90°
θ = 45°
Independent of θ
Solution
is max when normal is parallel to B.
Air resistance
Eddy currents in tube oppose its motion
Friction
Gravity decreases inside
Solution
Eddy currents in the copper produce a magnetic force opposing the magnet's motion (Lenz's law).
Zero
Solution
When the loop is fully inside, flux is constant. EMF = 0. Only when entering or leaving does flux change.
Same
×100
×1000
×0.001
Solution
Putting iron of μ_r in the core multiplies L by μ_r = 1000.
8 mJ
4 mJ
2 mJ
16 mJ
Solution
.
5 V
10 V
20 V
50 V
Solution
. .
Aids the motion
Opposes the motion
Is zero
Tries to rotate the loop
Solution
Lenz's law: induced effects oppose the change. Force opposes the motion that causes the change.
Number of turns and shared area
Currents only
Voltages
Resistances
Solution
. Geometry only.
Solution
At terminal velocity, gravity provides power that equals power dissipated: .
Use a single solid block
Use thin laminations insulated from each other
Use thicker wire
Use copper instead of iron
Solution
Laminations break up the eddy current loops, reducing power loss.
0.125 V
0.5 V
2 V
8 V
Solution
.
Same
×2
×0.5
×0.25
Solution
. L → 2L, I → I/2: . So U becomes 0.5x.
V
0.06 V
6 V
60 V
Solution
.
4 V
8 V
16 V
20 V
Solution
.
0.4 H
2.5 H
10 H
0.04 H
Solution
.
0.2 Wb
2 Wb
0.02 Wb
20 Wb
Solution
Flux linkage = .
Clockwise
Counter-clockwise
Zero
Cannot say
Solution
Coil's right face must become S to repel approaching S. Current is clockwise viewed from the right.
0.24 V
24 V
0.024 V
2.4 V
Solution
. .
Double
Quadruple
Stay same
Increase by sqrt(2)
Solution
. To double U, multiply I by .
Solid iron core
Laminating the core
Using bigger wire
Lower frequency
Solution
Laminations and high resistivity reduce eddy currents.
5 mH
25 mH
500 mH
1 H
Solution
.
5/6
5/13
1
5/sqrt(36)
Solution
.
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