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Electromagnetic InductionNEET Physics · Class 12 · NCERT Chapter 6

32 NEET previous-year questions on Electromagnetic Induction, each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.

PYQ frequency · topic × year

17
18
19
20
21
22
23
24
Magnetic flux
1
1
1
Faraday
1
2
1
Lenz
1
1
1
1
Motional EMF
1
2
1
Eddy currents
1
1
Self-induction
1
1
1
1
1
1
Mutual induction
1
1
2
Energy in inductor
2
1
1
1

Darker = more questions in our PYQ bank for that topic and year.

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All (32)
Magnetic flux (3)
Faraday (4)
Lenz (4)
Motional EMF (4)
Eddy currents (2)
Self-induction (6)
Mutual induction (4)
Energy in inductor (5)

A

tesla

B

weber

C

henry

D

volt

Solution

Φ in Wb (= T·m²).

A

B

C

D

Solution

. Negative sign comes from Lenz's law.

A

0.04 V

B

0.2 V

C

0.4 V

D

4 V

Solution

.

A

farad

B

henry

C

weber

D

tesla

Solution

Henry (H), defined by .

A

0.5 J

B

1 J

C

2.5 J

D

5 J

Solution

.

A

Conservation of charge

B

Conservation of energy

C

Conservation of momentum

D

Newton's third law

Solution

Lenz's law expresses energy conservation in induction.

A

0.5 V

B

1 V

C

2 V

D

5 V

Solution

.

A

B

C

D

No relation

Solution

Reciprocity: .

A

×1

B

×2

C

×4

D

×8

Solution

. ×4.

A

B

C

D

Solution

.

A

θ = 0° between B and area normal

B

θ = 90°

C

θ = 45°

D

Independent of θ

Solution

is max when normal is parallel to B.

A

Air resistance

B

Eddy currents in tube oppose its motion

C

Friction

D

Gravity decreases inside

Solution

Eddy currents in the copper produce a magnetic force opposing the magnet's motion (Lenz's law).

A

B

C

Zero

D

Solution

When the loop is fully inside, flux is constant. EMF = 0. Only when entering or leaving does flux change.

A

Same

B

×100

C

×1000

D

×0.001

Solution

Putting iron of μ_r in the core multiplies L by μ_r = 1000.

A

8 mJ

B

4 mJ

C

2 mJ

D

16 mJ

Solution

.

A

5 V

B

10 V

C

20 V

D

50 V

Solution

. .

A

Aids the motion

B

Opposes the motion

C

Is zero

D

Tries to rotate the loop

Solution

Lenz's law: induced effects oppose the change. Force opposes the motion that causes the change.

A

Number of turns and shared area

B

Currents only

C

Voltages

D

Resistances

Solution

. Geometry only.

A

B

C

D

Solution

At terminal velocity, gravity provides power that equals power dissipated: .

A

Use a single solid block

B

Use thin laminations insulated from each other

C

Use thicker wire

D

Use copper instead of iron

Solution

Laminations break up the eddy current loops, reducing power loss.

A

0.125 V

B

0.5 V

C

2 V

D

8 V

Solution

.

A

Same

B

×2

C

×0.5

D

×0.25

Solution

. L → 2L, I → I/2: . So U becomes 0.5x.

A

V

B

0.06 V

C

6 V

D

60 V

Solution

.

A

4 V

B

8 V

C

16 V

D

20 V

Solution

.

A

0.4 H

B

2.5 H

C

10 H

D

0.04 H

Solution

.

A

0.2 Wb

B

2 Wb

C

0.02 Wb

D

20 Wb

Solution

Flux linkage = .

A

Clockwise

B

Counter-clockwise

C

Zero

D

Cannot say

Solution

Coil's right face must become S to repel approaching S. Current is clockwise viewed from the right.

A

0.24 V

B

24 V

C

0.024 V

D

2.4 V

Solution

. .

A

Double

B

Quadruple

C

Stay same

D

Increase by sqrt(2)

Solution

. To double U, multiply I by .

A

Solid iron core

B

Laminating the core

C

Using bigger wire

D

Lower frequency

Solution

Laminations and high resistivity reduce eddy currents.

A

5 mH

B

25 mH

C

500 mH

D

1 H

Solution

.

A

5/6

B

5/13

C

1

D

5/sqrt(36)

Solution

.

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