Laws of MotionNEET Physics · Class 11 · NCERT Chapter 4

A force of $10\text{N}$ acts on a body of mass $2\text{kg}$ at rest. The acceleration produced is:

A constant force of $20\text{N}$ acts on a body of mass $4\text{kg}$, initially at rest, for $5\text{s}$. The kinetic energy gained is:

A bullet of mass $20\text{g}$ is fired with velocity $200\text{m/s}$ from a gun of mass $5\text{kg}$. The recoil velocity of the gun is:

A ball of mass $0.5\text{kg}$ moving with velocity $10\text{m/s}$ strikes a wall and bounces back with the same speed. The impulse experienced by the ball is:

A body of mass $4\text{kg}$ moving at $5\text{m/s}$ collides with a stationary body of mass $1\text{kg}$ and they stick together. Their common velocity after collision is:

Two bodies of equal mass collide elastically in one dimension. One was at rest. After collision:

A block of mass $10\text{kg}$ rests on a horizontal surface with ${\mu }_s=0.3$. Take $g=10{\text{m/s}}^2$. The minimum horizontal force to start the block moving is:

A block on an inclined plane is on the verge of sliding when $\theta =30°$. The coefficient of static friction between the block and incline is:

A block slides down a $45°$ incline with coefficient of kinetic friction $0.5$. Take $g=10{\text{m/s}}^2$. The acceleration is:

A block of mass $m$ rests on an inclined plane making an angle $\theta$ with the horizontal. The coefficient of friction is $\mu$. The minimum force needed (parallel to the incline) to push the block up is:

Two masses $m_1=5\text{kg}$ and $m_2=3\text{kg}$ hang on a frictionless pulley. Take $g=10{\text{m/s}}^2$. The acceleration of the system is:

In an Atwood machine with masses $m_1=4\text{kg}$ and $m_2=2\text{kg}$, the tension in the string (take $g=10{\text{m/s}}^2$) is:

A car takes a circular turn of radius $200\text{m}$ on a road banked at $\tan \theta =0.5$. Take $g=10{\text{m/s}}^2$. The maximum speed for no slipping (no friction) is:

On a flat circular road of radius $r$, the centripetal force required for a car of mass $m$ moving with speed $v$ is provided by:

Newton's third law states that for every action there is an equal and opposite reaction. Action and reaction:

A force $F$ acts on a body for time $t$, increasing its momentum from $p_1$ to $p_2$. Then $F$ equals:

In a perfectly elastic 1D collision, the body $m_1$ moving with velocity $u$ strikes a stationary body $m_2$. After collision the velocity of $m_1$ is:

A block of mass $2\text{kg}$ slides on a horizontal surface with ${\mu }_k=0.4$. Take $g=10{\text{m/s}}^2$. The deceleration is:

The variation of momentum with time of a body is shown by a straight line of slope $5{\text{kg⋅m/s}}^2$. The force on the body is:

Two masses $m$ and $2m$ are connected by a light string over a frictionless pulley. The acceleration of the system is:

A man of mass $60\text{kg}$ stands in a lift accelerating upward at $2{\text{m/s}}^2$. Take $g=10{\text{m/s}}^2$. The force exerted by the floor on the man is:

A man of mass $80\text{kg}$ stands in a lift descending at constant velocity. Take $g=10{\text{m/s}}^2$. The reading of the spring balance under his feet is:

A force $F=10\text{N}$ acts on a body for $5\text{s}$. The change in momentum is:

A block is pushed against a wall with a horizontal force $F$. The minimum value of $F$ to keep the block from sliding down (mass $m$, friction coefficient $\mu$) is:

A bullet of mass $0.05\text{kg}$ moving with velocity $400\text{m/s}$ embeds itself in a wooden block of mass $9.95\text{kg}$. The velocity of the combined system is:

On a level circular road of radius $r$, the maximum speed for a car (mass $m$, friction coefficient $\mu$) without skidding is:

Three blocks of masses $1,2,3\text{kg}$ are placed in contact in a line on a frictionless surface. A horizontal force of $12\text{N}$ is applied to the $1\text{kg}$ block from the side. The acceleration of the system is:

A horizontal force $P$ is applied to a block of mass $m$ on a horizontal floor with friction coefficient $\mu$. The block just starts to slide. The value of $P$ is:

A light string over a frictionless pulley supports masses $m$ on one side and $2m$ on the other. The tension in the string is (take $g$ as standard gravity):

A body of mass $5\text{kg}$ has initial velocity $4\text{m/s}$ in the x-direction. A constant force of $10\text{N}$ acts on it in the y-direction for $4\text{s}$. The final speed of the body is:

A vehicle on a banked road takes a turn of radius $r$. If the angle of banking is $\theta$, the speed at which it can take the turn safely (no friction) is: