Oscillations NEET Questions with Solutions

Q: How many questions come from Oscillations in NEET 2027?

You can expect 1 to 2 questions from Oscillations in NEET 2027. The chapter has high PYQ frequency. Time period of pendulum and spring-mass, energy in SHM, velocity and acceleration at given displacement, and series / parallel spring problems are the favourites.

Q: What is Simple Harmonic Motion (SHM)?

SHM is a special kind of oscillatory motion in which the restoring force is directly proportional to the displacement from a fixed point and is always directed toward that point. Mathematically, F equals minus k x, which gives a equals minus omega squared x, with the standard solution x of t equals A sin(omega t plus phi).

Q: What is the time period of a simple pendulum?

For small angles, T equals 2 pi times the square root of L over g, where L is the length of the pendulum and g is the acceleration due to gravity. The period does not depend on the mass of the bob or the (small) amplitude. NEET problems often vary L or g (different planets, lifts) and ask how T changes.

Q: What is the time period of a spring-mass system?

T equals 2 pi times the square root of m over k, where m is the mass and k is the spring constant. This is independent of the amplitude. The period is the same on a horizontal frictionless surface and hanging vertically; gravity only shifts the equilibrium position, it does not change T.

Q: What is the velocity and acceleration in SHM?

For x equals A sin(omega t plus phi), v equals A omega cos(omega t plus phi) and a equals minus A omega squared sin(omega t plus phi). At the mean position (x = 0), v is maximum equal to A omega and a is zero. At the extremes (x = plus minus A), v is zero and a is maximum equal to A omega squared. A useful formula: v equals omega times square root of (A squared minus x squared).

Q: How does the total energy in SHM compare with KE and PE?

The total mechanical energy of SHM is constant: E equals half k A squared equals half m omega squared A squared. KE equals half k (A squared minus x squared) and PE equals half k x squared. KE is maximum at x equals 0; PE is maximum at x equals plus minus A. Their sum is always E.

Q: How do springs combine in series and in parallel?

Series: the same force stretches each spring, so they extend in turn. Effective spring constant is given by 1 over k_eff equals 1 over k_1 plus 1 over k_2. The effective k is smaller than the smallest k. Parallel: both springs share the load and extend by the same amount. k_eff equals k_1 plus k_2. The effective k is larger than the largest k.

Question 1

The oscillation of a body on a smooth horizontal surface is represents by the equation X = A cos ( ω t) where X = displacement at time t ω = frequency of oscillation Which one of the following graph s

Accepted Answer

a O T t

Question 2

A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then, its time period of vibration will be:

Accepted Answer

2πβ α

Question 3

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Th

Accepted Answer

4 5 π

Question 4

A spring of force constant k is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is k′. Then they are connected in parallel and force constant is k ′′. Then

Accepted Answer

1 : 11

Question 5

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s 2 at a distanc

Accepted Answer

2 π s

Question 6

Which of the following acts as a circuit protection device?

Accepted Answer

fuse

Question 7

The phase difference between displacement and acceleration of a particle in a simple harmonic motion is :

Accepted Answer

rad 2 π

Question 8

A body is executing simple harmonic motion with frequency ‘n’, the frequency of its potential energy is :

Accepted Answer

2n

Question 9

A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is :

Accepted Answer

0.628 s

Question 10

Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum afte

Accepted Answer

11

Question 11

If 5sin m 3 π⎛⎞= π + ⎜⎟⎝⎠ xt represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are

Accepted Answer

5 m, 2 s

Question 12

If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is 2 x times its original

Accepted Answer

2

Question 13

In an oscillating spring mass system, a spring is connected to a box filled with sand. As the box oscillates, sand leaks slowly out of the box vertically so that the average frequency [math] and avera

Accepted Answer

Graph showing ω(t) increasing with time and A(t) decreasing with time.

Question 14

Two identical point masses [math] and [math], suspended from two separate massless springs of spring constants [math] and [math], respectively, oscillate vertically. If their maximum speeds are the sa

Accepted Answer

[math]

OscillationsNEET Physics · Class 11 · NCERT Chapter 13

More NEET questions, next chapter

Track Your NEET Score Across All 90 Chapters

OscillationsNEET Physics · Class 11 · NCERT Chapter 13

1NEET 2014Medium4 bookletsThe oscillation of a body on a smooth horizontal surface is represents by the equation X = A cos ( ω t) where X = displacement at time t ω = frequency of oscillation Which one of the following graph shows correctly the variation ‘a’ with ‘t’ ?

2NEET 2015Medium4 bookletsA particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then, its time period of vibration will be:

3NEET 2017Medium5 bookletsA particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

4NEET 2017Medium5 bookletsA spring of force constant k is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is k′. Then they are connected in parallel and force constant is k ′′. Then k′ : k′′ is

5NEET 2018Medium20 bookletsA pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s 2 at a distance of 5 m from the mean position. The time period of oscillation is

6NEET 2019Medium5 bookletsWhich of the following acts as a circuit protection device?

7NEET 2020Medium24 bookletsThe phase difference between displacement and acceleration of a particle in a simple harmonic motion is :

8NEET 2021Medium23 bookletsA body is executing simple harmonic motion with frequency ‘n’, the frequency of its potential energy is :

9NEET 2021Medium24 bookletsA spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is :

10NEET 2022Medium24 bookletsTwo pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:

11NEET 2024Medium23 bookletsIf 5sin m 3 π⎛⎞= π + ⎜⎟⎝⎠ xt represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are

12NEET 2024Medium24 bookletsIf the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is 2 x times its original time period. Then the value of x is:

More NEET questions, next chapter

Track Your NEET Score Across All 90 Chapters