32 NEET previous-year questions on Ray Optics and Optical Instruments, each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.
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-15 cm
-7.5 cm
-30 cm
+15 cm
Solution
. cm.
Real, inverted
Real, erect
Virtual, inverted
Virtual, erect, diminished
Solution
Convex mirror always gives a virtual, erect, diminished image.
15°
19.5°
22.5°
45°
Solution
.
30°
42°
49°
60°
Solution
.
4 cm
6 cm
8 cm
10.6 cm
Solution
cm.
+12 cm
+60 cm
-60 cm
-12 cm
Solution
. cm (real, beyond F).
+10 cm
+20 cm
-20 cm
+40 cm
Solution
cm.
2°
3°
6°
9°
Solution
.
5×
20×
105×
500×
Solution
.
+10 cm
+20 cm
Infinity
-10 cm
Solution
Object at F: rays parallel after lens, image at infinity.
At F, diminished
At C, same size, inverted, real
Beyond C, magnified
Behind mirror, virtual
Solution
u = 2f gives v = 2f, m = -1: same size, inverted, real, at C.
41.8°
49°
62.5°
79°
Solution
.
+12 cm
-60 cm
+60 cm
-12 cm
Solution
. cm.
√2
1.5
√3
2
Solution
.
16×
50×
96×
120×
Solution
.
+15 cm
-15 cm
-20 cm
+20 cm
Solution
u = -30, v = -60. . f = -20 cm.
0.75
1.33
1.5
4/3
Solution
.
+0.25 D
+4 D
+25 D
+100 D
Solution
D.
Refraction
TIR
Reflection at flat surface
Diffraction
Solution
Repeated TIR at the core-cladding boundary keeps the light trapped.
Speed
Wavelength
Frequency
Refractive index of the medium relative to first
Solution
Speed and λ both decrease. f stays. n_2/n_1 > 1 means light goes into a denser medium.
Decreases
Stays
Becomes 4f
Becomes f/2
Solution
. In water . Ratio .
Real, inverted
Real, erect
Virtual, erect, magnified 2×
Virtual, inverted
Solution
m positive → erect (so virtual). |m| = 2 → magnified.
Solution
.
f_o - f_e
f_o + f_e
f_o
f_e
Solution
Both image and final image at infinity, so length = f_o + f_e.
24.4°
42°
49°
90°
Solution
. Hence diamond's brilliance.
D/f
1 + D/f
f/D
D - f
Solution
.
+8 D
-2 D
+2 D
-15 D
Solution
D.
m/s
m/s
m/s
m/s
Solution
m/s.
2 cm
3 cm
4 cm
6 cm
Solution
Shift cm.
+6 cm
+15 cm
-30 cm
-6 cm
Solution
. v = +6 cm (virtual, behind mirror).
+20 cm
+30 cm
Infinity
-20 cm
Solution
P = +5 D → f = 20 cm. u = -f → image at infinity.
Increase λ
Decrease λ
Use long-focal-length objective
Use a concave eyepiece
Solution
Resolving power . Shorter λ (e.g., UV microscopes) gives higher resolution.
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