Introduction to Coordination Compounds
A coordination compound is a compound in which a central metal atom (or ion) is bonded to a fixed number of ions or neutral molecules called ligands. These bonds are coordinate (dative) bonds — the ligand donates a lone pair of electrons to the metal.
Coordination compounds are widespread: haemoglobin (Fe-porphyrin), chlorophyll (Mg-porphyrin), vitamin B12 (Co complex), cisplatin (Pt anticancer drug), EDTA in food preservation, and cyanide extraction of gold are all coordination chemistry in action.
The study of coordination compounds was systematised by Alfred Werner (1913 Nobel Prize in Chemistry). His key insight was the idea of primary and secondary valence, which is the foundation of modern coordination chemistry.
Terminology and Types of Ligands
Key Terms
- Central metal atom/ion: the metal at the centre of the complex that accepts electron pairs. It is typically a transition metal.
- Ligand: a molecule or ion that donates one or more lone pairs of electrons to the central metal. Ligands must have at least one lone pair available for donation.
- Coordination number (CN): the total number of ligand atoms directly bonded to the central metal. Common coordination numbers: 4 (square planar or tetrahedral) and 6 (octahedral).
- Coordination sphere: the central metal + all directly bonded ligands, written inside square brackets, e.g., [Co(NH3)6]3+.
- Chelate: a complex in which a polydentate ligand forms one or more rings by bonding to the metal through two or more donor atoms.
Types of Ligands
| Type | Donor atoms | Examples |
|---|---|---|
| Monodentate | 1 | NH3 (ammine), H2O (aqua), Cl- (chlorido), CN- (cyanido), CO (carbonyl), OH- (hydroxido) |
| Bidentate | 2 | en (ethylenediamine, two N), oxalate ox2- (two O), 2,2'-bipyridyl (two N) |
| Tridentate | 3 | diethylenetriamine (dien) |
| Tetradentate | 4 | triethylenetetramine (trien) |
| Hexadentate | 6 | EDTA (ethylenediaminetetraacetate: 2 N + 4 O) |
| Ambidentate | 1 (but can choose between 2 atoms) | NO2- (through N or O); SCN- (through S or N); CN- (through C or N) |
Chelate effect: Polydentate ligands form more stable complexes than equivalent monodentate ligands. This extra stability arises because replacing multiple monodentate ligands with one polydentate ligand increases the number of free particles in solution (increases entropy). The more donor atoms a ligand has, the more stable the complex.
IUPAC Nomenclature
Rules for Naming Coordination Compounds
- Name the cation first, then the anion (same as for ionic compounds).
- Within the complex ion, name the ligands first in alphabetical order, then the central metal.
- Alphabetise ligands by their names, ignoring multiplying prefixes (di, tri, tetra, bis, tris).
- Use multiplying prefixes: di, tri, tetra for simple ligands; use bis, tris, tetrakis for ligands whose names already contain a number or for polydentate ligands (to avoid ambiguity).
- Indicate the oxidation state of the central metal in Roman numerals in round brackets immediately after the metal name: e.g., cobalt(III).
- For anionic complexes, add the suffix -ate to the metal name (using Latin-based names for some metals):
- Fe → ferrate; Co → cobaltate; Cr → chromate; Cu → cuprate; Au → aurate; Ag → argentate; Pt → platinate
- Most others use English names + -ate: nickelate, manganate, etc.
Common Ligand Names
| Ligand | Formula | IUPAC name |
|---|---|---|
| Ammonia | NH3 | ammine |
| Water | H2O | aqua |
| Carbonyl | CO | carbonyl |
| Nitrosyl | NO | nitrosyl |
| Fluoride | F- | fluoro |
| Chloride | Cl- | chlorido |
| Bromide | Br- | bromido |
| Cyanide | CN- | cyanido |
| Hydroxide | OH- | hydroxido |
| Nitrite (N-bonded) | NO2- | nitro |
| Nitrite (O-bonded) | NO2- | nitrito-O |
| Ethylenediamine | H2N-CH2-CH2-NH2 | ethylenediamine (en) |
| Oxalate | C2O42- | oxalato |
Worked Examples
- [Co(NH3)6]3+ = hexaamminecobalt(III) ion
- [CoCl2(NH3)4]+ = tetraamminedichloridocobalt(III) ion (ammine before chlorido alphabetically: a before c; note tetra + ammine, di + chlorido)
- K3[Fe(CN)6] = potassium hexacyanidoferrate(III)
- K2[PtCl4] = potassium tetrachloridoplatinate(II)
- [Cu(en)2]2+ = bis(ethylenediamine)copper(II) ion (bis because en already has a number)
- [Fe(CO)5] = pentacarbonyliron(0)
Card 1 of 10
Formula
[Co(NH₃)₆]³⁺
What is the IUPAC name of this coordination compound?
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Isomerism in Coordination Compounds
Structural Isomers (same molecular formula, different bonding)
1. Ionisation Isomerism
The ligand inside the coordination sphere and the counter ion outside are swapped. They give different ions in solution. Test with AgNO3 (precipitates Cl-) or BaCl2 (precipitates SO42-).
- [Co(NH3)5Cl]SO4 (gives SO42- in solution) vs [Co(NH3)5(SO4)]Cl (gives Cl- in solution)
2. Hydrate (Solvate) Isomerism
Water molecules can be inside the coordination sphere (bonded as aqua ligands) or outside (as water of crystallisation). The three hydrate isomers of CrCl3·6H2O:
- [Cr(H2O)6]Cl3 — violet; all 3 Cl- are free in solution
- [Cr(H2O)5Cl]Cl2·H2O — blue-green; 2 Cl- free
- [Cr(H2O)4Cl2]Cl·2H2O — dark green; 1 Cl- free
3. Linkage Isomerism
Ambidentate ligands can bond through different atoms. NO2- can bond through N (nitro) or O (nitrito).
- [Co(NH3)5(NO2)]Cl2 (nitro, M-N) vs [Co(NH3)5(ONO)]Cl2 (nitrito, M-O)
4. Coordination Isomerism
When both the cation and anion are complex ions, the distribution of ligands between the two complexes can vary.
- [Co(NH3)6][Cr(CN)6] vs [Cr(NH3)6][Co(CN)6]
Stereoisomers (same bonding, different spatial arrangement)
5. Geometric (Cis-Trans) Isomerism
Geometric isomers differ in the relative positions of identical ligands. Not possible for regular tetrahedral complexes (all positions are equivalent).
Square planar MA2B2 type (like [PtCl2(NH3)2]):
- Cis: two identical ligands at 90° (adjacent corners)
- Trans: two identical ligands at 180° (opposite corners)
Octahedral MA4B2 type (like [Co(NH3)4Cl2]+):
- Cis: two Cl are adjacent (90° apart)
- Trans: two Cl are opposite (180° apart)
Octahedral MA3B3 type (like [Co(NH3)3Cl3]):
- Fac (facial): three identical ligands on one triangular face. All A-M-A angles = 90°.
- Mer (meridional): three identical ligands span a meridian. One A-M-A angle = 180°.
6. Optical Isomerism
Optical isomers are non-superimposable mirror images (enantiomers). They rotate plane-polarised light in opposite directions (one is +/dextro, the other is -/laevo). An equal mixture of both is called a racemic mixture (optically inactive).
Conditions for optical isomerism in octahedral complexes:
- [M(en)3]n+ type (e.g., [Co(en)3]3+) — always optically active, no plane of symmetry
- cis-[M(en)2A2]n+ (e.g., cis-[Co(en)2Cl2]+) — optically active (cis isomer)
- trans-[M(en)2A2]n+ — optically inactive (has a plane of symmetry)
Bonding Theories: Werner, VBT, and CFT
Werner's Theory (1893)
Werner proposed that metals have two types of valence:
- Primary valence (ionisable valence): the oxidation state of the metal. Satisfied by negative ions (counter ions outside the coordination sphere).
- Secondary valence (non-ionisable valence): the coordination number. Satisfied by ligands directly bonded to the metal (inside the coordination sphere).
For CoCl3·6NH3 = [Co(NH3)6]Cl3: Co has primary valence 3 (oxidation state, satisfied by 3 Cl-) and secondary valence 6 (coordination number, satisfied by 6 NH3). Werner's theory was confirmed by conductivity measurements (number of ions in solution) and by precipitation of Cl- with AgNO3.
Valence Bond Theory (VBT)
VBT describes the bonding in terms of hybridisation of the metal's orbitals to accept lone pairs from ligands.
| Geometry | CN | Inner orbital hybrid | Outer orbital hybrid |
|---|---|---|---|
| Square planar | 4 | dsp2 (uses inner d) | |
| Tetrahedral | 4 | sp3 | |
| Octahedral | 6 | d2sp3 (uses inner 3d) | sp3d2 (uses outer 4d) |
Inner orbital complex (d2sp3): strong field ligands (CN-, CO, en, NH3) force electron pairing in lower d-orbitals, freeing inner d-orbitals for hybridisation. Result: fewer unpaired electrons, lower (or zero) paramagnetism. Also called low-spin complex.
Outer orbital complex (sp3d2): weak field ligands (F-, Cl-, H2O, OH-) do not force pairing — electrons spread out, using outer d-orbitals for hybridisation. Result: more unpaired electrons, higher paramagnetism. Also called high-spin complex.
Example: [Co(NH3)6]3+ vs [CoF6]3-
- Co3+ = [Ar] 3d6. With NH3 (strong field): electrons pair up in 3d (3d6 → t2g6 eg0), freeing 3d3 and 4s, 4p for d2sp3. Result: diamagnetic (0 unpaired).
- Co3+ with F- (weak field): electrons spread across 3d5 and 4s, 4p, 4d for sp3d2. Result: 4 unpaired electrons, paramagnetic.
Crystal Field Theory (CFT)
CFT treats the metal-ligand interaction as an electrostatic interaction between the metal d-electrons and the negative charges (or dipoles) of the ligands. The key result is the splitting of the five degenerate d-orbitals into two sets:
Octahedral field:
- eg (higher energy, +0.6 Δo): dx2-y2 and dz2 — point along the x, y, z axes directly toward the ligands (maximum repulsion)
- t2g (lower energy, -0.4 Δo): dxy, dxz, dyz — point between the axes (less repulsion)
Octahedral field: 5 d-orbitals split into t₂g (×3) and eɡ (×2)
Higher energy (destabilised)
eɡ (+0.6Δo each)
Lower energy (stabilised)
t₂g (-0.4Δo each)
Unpaired electrons
1
Magnetic moment
1.73 BM (paramagnetic)
CFSE
-0.4Δo
Spin type
High spin
High Spin vs Low Spin
When filling d-electrons in an octahedral field, there is a competition between:
- Δo (crystal field splitting energy) — the energy cost of promoting an electron to eg
- P (pairing energy) — the energy cost of pairing two electrons in the same orbital
If Δo > P (strong field ligands): electrons pair up in t2g before going to eg. Low spin complex (fewer unpaired electrons).
If Δo < P (weak field ligands): electrons go to eg before pairing in t2g. High spin complex (more unpaired electrons).
Spectrochemical Series (weak field to strong field):
I- < Br- < Cl- < F- < OH- < H2O < NH3 < en < CN- < CO
CFSE Calculation
CFSE = (number of t2g electrons × -0.4 Δo) + (number of eg electrons × +0.6 Δo)
Example: High spin d6 in octahedral field (t2g4 eg2): CFSE = 4(-0.4) + 2(+0.6) = -1.6 + 1.2 = -0.4 Δo
Example: Low spin d6 in octahedral field (t2g6 eg0): CFSE = 6(-0.4) + 0 = -2.4 Δo
Tetrahedral Crystal Field
In a tetrahedral field, the splitting is inverted: the e-set (dx2-y2, dz2) is now lower in energy and the t2-set (dxy, dxz, dyz) is higher. Also, Δt = (4/9) Δo. Because Δt is so small, almost all tetrahedral complexes are high spin.
Applications and Stability of Coordination Compounds
Biological Importance
- Haemoglobin: Fe2+ coordinated to a porphyrin ring (haem group) and a protein chain. Carries O2 in the blood. CO binds to the same site 200× more strongly than O2, causing CO poisoning.
- Chlorophyll: Mg2+ at the centre of a porphyrin ring. Absorbs red and blue light; reflects green. Essential for photosynthesis.
- Vitamin B12 (Cobalamin): Co3+ in a corrin ring. Essential cofactor for DNA synthesis and nerve function.
Industrial Applications
- Gold and silver extraction (cyanide process):
- Nickel refining (Mond process): Ni reacts with CO at 50-60°C to form [Ni(CO)4], a volatile liquid. It decomposes at 230°C to give pure Ni.
- Electroplating: metals are plated from coordination compound solutions (e.g., gold plating from [Au(CN)2]-).
Medicinal Uses
- Cisplatin (cis-[PtCl2(NH3)2]): anticancer drug. Crosslinks guanine bases on the same DNA strand, blocking replication.
- EDTA as antidote: Ca-EDTA chelates heavy metals (Pb, Hg) and removes them from the body.
Stability of Complexes
Stability is measured by the stability constant (formation constant, Kf). The larger Kf, the more stable the complex. Key factors:
- Chelate effect: polydentate ligands give higher stability due to entropy increase.
- Nature of metal: higher charge density on metal = stronger bonds. Small, highly charged metal ions form more stable complexes.
- Nature of ligand: strong field ligands (CN-, CO) form very stable complexes (large Δo, more CFSE).
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Worked NEET Problems
NEET-style problem · IUPAC Naming
Question
Give the IUPAC name of K3[Cr(C2O4)3].
Solution
Step 1: The complex ion is [Cr(C2O4)3]3- (anionic, so Cr becomes chromate).
Step 2: C2O42- is the oxalate ion (IUPAC name: oxalato). Three oxalato ligands = tris(oxalato) — use tris because oxalato contains a multiplier (tridentate-like naming).
Step 3: Oxidation state of Cr: 3(-2) + x = -3; x = +3. Chromate(III).
Full name: Potassium tris(oxalato)chromate(III).
NEET-style problem · Identifying Isomerism Type
Question
[Co(NH3)5Br]SO4 and [Co(NH3)5(SO4)]Br — what type of isomerism is this?
Solution
Answer: Ionisation isomerism. Both have the same molecular formula but different ions in solution. The first gives SO42- as the free anion in water (detected by BaCl2 — white precipitate); the second gives Br- as the free anion (detected by AgNO3 — pale yellow precipitate). Inside the coordination sphere, Br and SO4 have swapped positions with their respective counter ions.
NEET-style problem · VBT Hybridisation
Question
Determine the hybridisation and geometry of [Ni(CN)4]2-.
Solution
Step 1: Ni2+ (Z=28): [Ar] 3d8. Two electrons lost from 4s: [Ar] 3d8.
Step 2: CN- is a strong field ligand. It forces electron pairing in 3d. In Ni2+ (3d8), two electrons pair up in one 3d orbital, leaving one inner 3d orbital empty.
Step 3: Hybridisation: the empty 3d + 4s + 4p2 = dsp2 (square planar).
Result: [Ni(CN)4]2- is dsp2 hybridised, square planar geometry, diamagnetic (0 unpaired electrons). Note: [Ni(Cl)4]2- uses weak field Cl- and is sp3 (tetrahedral, paramagnetic).
NEET-style problem · Crystal Field Theory
Question
[Fe(H2O)6]2+ is pale green while [Fe(CN)6]4- is yellow. Using CFT, explain why these two complexes absorb different wavelengths of light.
Solution
Both complexes have Fe2+ (3d6). The difference is the ligand field strength. H2O is a weak field ligand (small Δo), so [Fe(H2O)6]2+ is a high spin d6 complex with a small energy gap between t2g and eg. Electrons absorb in the red-orange region (~500 nm) and the complex appears green (complementary colour). CN- is a strong field ligand (large Δo), so [Fe(CN)6]4- is a low spin d6 complex with a large t2g-eg gap. The larger Δo means higher-energy photons are absorbed (blue-violet region), and the complex appears yellow (complementary to violet). Strong field ligands shift the absorbed wavelength to shorter (higher energy), while weak field ligands lead to longer-wavelength absorption.
NEET-style problem · EAN Rule
Question
Calculate the EAN of Fe in [Fe(CO)5]. Does it satisfy the noble gas rule?
Solution
Fe in [Fe(CO)5]: Fe is in the 0 oxidation state (Fe0). Atomic number of Fe = 26. Electrons lost = 0. Each CO donates 2 electrons; 5 CO donate 5 × 2 = 10 electrons. EAN = 26 - 0 + 10 = 36. Krypton (Kr) has Z = 36. So [Fe(CO)5] satisfies the EAN rule (reaches Kr configuration). This makes [Fe(CO)5] a stable, diamagnetic compound. The EAN rule (18-electron rule) is most reliable for metal carbonyls.
Summary Cheat Sheet
Key Terms Quick Reference
| Term | Definition / Example |
|---|---|
| Coordination number | Total donor atoms bonded to metal. en counts as 2, NH3 as 1. |
| Chelate effect | Polydentate ligands form more stable complexes (entropy driven) |
| Ambidentate ligand | NO2- (N or O), SCN- (S or N) — leads to linkage isomerism |
| IUPAC naming order | Cation first, then ligands alphabetically, then metal + ox. state |
| Anionic complex | Metal gets -ate suffix: Fe→ferrate, Co→cobaltate, Pt→platinate |
| Ionisation isomers | Ligand inside / counter ion outside are swapped |
| Linkage isomers | Different donor atom of ambidentate ligand bonded to metal |
| Geometric isomers | Cis-trans in square planar MA2B2; fac-mer in octahedral MA3B3 |
| Optical isomers | Non-superimposable mirror images; [M(en)3]n+ and cis-[M(en)2A2]n+ |
| d2sp3 vs sp3d2 | Strong field = d2sp3 (inner, low spin); weak field = sp3d2 (outer, high spin) |
| CFT octahedral | t2g (lower, -0.4 Δo) and eg (higher, +0.6 Δo) |
| Spectrochemical series | I- < Cl- < F- < H2O < NH3 < en < CN- < CO (weak to strong) |
| Δt vs Δo | Δt = (4/9) Δo; tetrahedral = always high spin |
| EAN rule | EAN = Z - ox. state + 2 × (no. of ligands) — noble gas count |
| Cisplatin | cis-[PtCl2(NH3)2]; anticancer drug; crosslinks DNA guanines |
| Cyanide process | [Au(CN)2]- extracts gold from ore |
Frequently asked questions
How many questions from Coordination Compounds appear in NEET each year?
You can expect 3 to 5 questions from this chapter in NEET every year, making it one of the highest-weightage chapters in Class 12 Chemistry. The topics tested most are IUPAC naming (especially getting the ligand names and order right), identifying types of isomerism, determining hybridisation (d2sp3 or sp3d2), and crystal field theory (high spin vs low spin, colour). Practise IUPAC naming with real examples until it becomes automatic.
What is a chelate and why are chelating ligands more stable?
A chelate is a complex formed when a polydentate ligand (one with two or more donor atoms) binds to a single metal ion through multiple points simultaneously, forming a ring structure. For example, ethylenediamine (en) has two NH2 groups that can both bond to the metal, forming a 5-membered ring. Chelating complexes are more stable than those with an equivalent number of monodentate ligands — this extra stability is called the chelate effect. The reason is entropy: replacing two monodentate ligands (e.g., 2NH3) with one bidentate ligand (en) increases the number of free particles in solution, which increases entropy (ΔS > 0) and makes the reaction more spontaneous (more negative ΔG).
How do you name a coordination compound using IUPAC rules?
Follow these steps in order: (1) Name the cation before the anion (just like for ionic compounds). (2) Within the complex ion, name the ligands first in alphabetical order (ignore multiplying prefixes like di, tri when alphabetising). (3) Then name the central metal atom, followed by its oxidation state in Roman numerals in brackets — for example, chromium(III). (4) For anionic complexes, add the suffix -ate to the metal name, e.g., cobaltate, ferrate, platinate. (5) Common ligand name changes: F- = fluoro, Cl- = chlorido, CN- = cyanido, NH3 = ammine, H2O = aqua, CO = carbonyl, NO = nitrosyl, OH- = hydroxido, en = ethylenediamine. Example: [Co(NH3)4Cl2]+ is tetraamminedichloridocobalt(III) ion.
What is the difference between geometric isomerism and optical isomerism?
Geometric isomers (cis-trans isomers) differ in the spatial arrangement of ligands around the metal. In a square planar complex like [PtCl2(NH3)2], cis has two Cl on the same side, trans has them on opposite sides. In octahedral complexes, cis/trans isomerism occurs for MA4B2 type. Geometric isomers are not mirror images of each other and cannot be interconverted without breaking bonds. Optical isomers (enantiomers) are non-superimposable mirror images of each other. They rotate plane-polarised light in opposite directions. Octahedral complexes with 3 bidentate ligands like [Co(en)3]3+ or cis-[Co(en)2Cl2]+ show optical isomerism. A mixture of equal amounts of both optical isomers is called a racemic mixture.
How does Crystal Field Theory explain the colour of coordination compounds?
In an isolated transition metal ion, all five d-orbitals are degenerate (same energy). When ligands approach the metal in an octahedral arrangement, they repel the d-electrons. The d-orbitals split into two sets: a lower-energy set t2g (dxy, dxz, dyz, pointing between the axes) and a higher-energy set eg (dx2-y2, dz2, pointing along the axes directly at the ligands). The energy gap between these sets is called crystal field splitting energy, Δo. When white light hits the complex, electrons absorb photons with exactly the energy Δo and jump from t2g to eg. The colour you see is the complementary colour. For example, if violet light is absorbed, the complex appears yellow-green.
What is the difference between high spin and low spin complexes?
In octahedral complexes, the d-electrons can be arranged in two ways depending on the balance between Δo (the crystal field splitting energy) and P (the pairing energy, the energy cost of putting two electrons in the same orbital). If Δo is small (weak field ligands like F-, Cl-, H2O), it is easier for electrons to go to eg than to pair up. This gives a high-spin complex (more unpaired electrons, more paramagnetic). If Δo is large (strong field ligands like CN-, CO, en, NH3), it is cheaper to pair up in t2g than to promote to eg. This gives a low-spin complex (fewer unpaired electrons, less paramagnetic or diamagnetic). The spectrochemical series orders ligands from weak to strong field: I- < Br- < Cl- < F- < OH- < H2O < NH3 < en < CN- < CO.
How do you calculate the oxidation state of the central metal in a complex?
The sum of the charges on the central metal and all ligands must equal the overall charge of the complex. Steps: (1) Note the total charge of the complex (positive, negative, or neutral). (2) Assign known charges to all ligands (e.g., Cl- = -1, CN- = -1, NH3 = 0, H2O = 0, en = 0, NO2- = -1, ox2- = -2). (3) Let the metal oxidation state = x, and solve: x + sum of ligand charges = complex charge. Example: [Fe(CN)6]4- — total charge = -4; six CN- each = -1, total ligand charge = -6; so x + (-6) = -4; x = +2. Fe is +2.
What is the EAN (Effective Atomic Number) rule?
The EAN rule (proposed by Sidgwick) states that stable metal complexes tend to have the metal surrounded by enough electrons from ligands to reach the electron count of the nearest noble gas. EAN = atomic number of metal - electrons lost (oxidation state) + electrons donated by all ligands. Each ligand donates 2 electrons (one lone pair). Example: [Fe(CO)5] — Fe is Z=26, no charge lost (Fe0), five CO each donate 2 electrons = 10. EAN = 26 - 0 + 10 = 36 (same as Kr). For [Ni(CO)4] — Ni Z=28, Ni0, four CO donate 8 electrons: EAN = 28 + 8 = 36 (Kr). The EAN rule works well for metal carbonyls but has exceptions for other complexes.
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