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Haloalkanes and Haloarenes

Haloalkanes and HaloarenesNEET Chemistry · Class 12 · NCERT Chapter 6

Introduction and Classification

Haloalkanes (alkyl halides) are compounds formed by replacing one or more hydrogen atoms of an alkane with a halogen atom (F, Cl, Br, or I). They have the general formula R-X, where R is an alkyl group and X is a halogen.

Haloarenes (aryl halides) are compounds where the halogen is directly attached to an aromatic ring. The most common example is chlorobenzene (C6H5Cl).

Classification of Haloalkanes

Based on the number of halogen atoms, haloalkanes are classified as mono, di, tri, or polyhalogen compounds. Based on the carbon bearing the halogen:

TypeCarbon attached to XExampleReactivity (SN)
Primary (1°)C bonded to 1 other C (or CH3-X)CH3CH2Cl (chloroethane)Fast SN2, slow SN1
Secondary (2°)C bonded to 2 other C atoms(CH3)2CHBr (2-bromopropane)Both SN1 and SN2 possible
Tertiary (3°)C bonded to 3 other C atoms(CH3)3CCl (2-chloro-2-methylpropane)Fast SN1, poor SN2

Classification of Haloarenes

  • Aryl halide: halogen directly on benzene ring — C6H5Cl (chlorobenzene), C6H5Br (bromobenzene)
  • Aralkyl halide: halogen on the side chain — C6H5CH2Cl (benzyl chloride). This behaves more like a haloalkane than a haloarene.

IUPAC Nomenclature

Rules for Haloalkanes

  1. Choose the longest carbon chain containing the halogen-bearing carbon as the parent chain.
  2. Number the chain from the end that gives the halogen the lowest possible locant.
  3. Halogens are named as prefixes: fluoro-, chloro-, bromo-, iodo- in alphabetical order if more than one.
  4. If there is a functional group of higher priority (e.g., -OH, -COOH), number from that end instead.
StructureIUPAC NameCommon Name
CH3ClChloromethaneMethyl chloride
CH3CH2BrBromoethaneEthyl bromide
CH3CHClCH32-ChloropropaneIsopropyl chloride
CH2ClCH2Cl1,2-DichloroethaneEthylene dichloride
CHCl3TrichloromethaneChloroform
CCl4TetrachloromethaneCarbon tetrachloride

Rules for Haloarenes

For monosubstituted benzene, simply prefix the halogen to benzene: chlorobenzene, bromobenzene. For disubstituted, use ortho (1,2-), meta (1,3-), para (1,4-) prefixes or IUPAC locants. When other substituents are present, the ring is numbered to give the lowest set of locants.

  • C6H5Cl: chlorobenzene (or 1-chlorobenzene)
  • 1,2-C6H4Cl2: 1,2-dichlorobenzene (o-dichlorobenzene)
  • 4-ClC6H4CH3: 1-chloro-4-methylbenzene (p-chlorotoluene)
  • C6H5CH2Cl: (chloromethyl)benzene (benzyl chloride)

Nature of the C-X Bond

The carbon-halogen bond is polar covalent. Because halogens are more electronegative than carbon, the bonding electrons are pulled towards the halogen, giving carbon a partial positive charge () and halogen a partial negative charge (). This polarity makes carbon electrophilic and susceptible to nucleophilic attack.

BondBond Length (pm)Bond Enthalpy (kJ/mol)Electronegativity of X
C-F1384854.0 (highest)
C-Cl1773273.0
C-Br1942722.8
C-I2142382.5 (lowest)

Key trends: Bond length increases C-F to C-I (as atomic radius of halogen increases). Bond strength (enthalpy) decreases C-F to C-I. Therefore, C-I is the weakest and most reactive bond; C-F is the strongest and least reactive.

Dipole moment order: C-F > C-Cl > C-Br > C-I (because both electronegativity difference and bond length matter; electronegativity dominates here). However, CHF3 has lower dipole moment than CHCl3 because F is small and bond length is short.

Preparation of Haloalkanes

1. From Alcohols

  • With HX (Lucas reagent): R-OH + HX → R-X + H2O. Reactivity: HI > HBr > HCl. Lucas test: ZnCl2/HCl. 3° alcohol reacts immediately (turbidity); 2° reacts in 5 min; 1° does not react at room temperature.
  • With SOCl2 (thionyl chloride): R-OH + SOCl2 → R-Cl + SO2 + HCl. Best method for making alkyl chlorides because SO2 and HCl are gaseous byproducts, giving pure product. Reaction proceeds with retention of configuration in pyridine (SNi mechanism).
  • With PCl5: R-OH + PCl5 → R-Cl + POCl3 + HCl.
  • With PCl3: 3 R-OH + PCl3 → 3 R-Cl + H3PO3.
  • With PBr3 or PI3 (in situ): for alkyl bromides and iodides, red P + Br2 or P + I2 generate PBr3 and PI3 in situ.

2. From Alkenes

  • Addition of HX: follows Markovnikov's rule (H adds to the C with more H). CH2=CH2 + HBr → CH3CH2Br.
  • Anti-Markovnikov addition (peroxide effect): in presence of peroxide (ROOR), HBr adds anti-Markovnikov via free radical mechanism. Only HBr shows this; HCl and HI do not.
  • Halogenation: alkene + Cl2/Br2 → vicinal dihalide. Cyclic halonium intermediate gives anti addition.

3. Halogen Exchange (Finkelstein and Swartz Reactions)

  • Finkelstein reaction: R-Cl + NaI (in dry acetone) → R-I + NaCl. NaCl precipitates out, driving equilibrium forward. Also: R-Br + NaI → R-I + NaBr.
  • Swartz reaction: R-Cl + AgF → R-F + AgCl. Uses silver fluoride to make fluoroalkanes. (Also: HgF2 or SbF3.)

4. From Hydrocarbons

  • Free radical halogenation of alkanes: CH4 + Cl2 (hv) → CH3Cl + HCl. Selectivity: F2 is too reactive; I2 is too unreactive; Cl2 and Br2 are practical.
  • Electrophilic aromatic substitution (for haloarenes): benzene + Cl2 (FeCl3/AlCl3) → chlorobenzene + HCl.

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SN1 and SN2 Mechanisms

Nucleophilic substitution reactions are the most important reactions of haloalkanes. A nucleophile (Nu:) attacks the electrophilic carbon bearing the halogen (the leaving group) and replaces it.

SN2 Mechanism (Substitution Nucleophilic Bimolecular)

SN2 is a one-step concerted mechanism. The nucleophile attacks the back side of the carbon bearing the leaving group (180° to the C-X bond) while the leaving group departs simultaneously. No intermediate is formed.

  • Rate: rate = k [RX][Nu]. Depends on both reactant concentrations (bimolecular, second order overall).
  • Stereochemistry: Walden inversion (complete inversion of configuration, like an umbrella turning inside-out). A pure R enantiomer gives a pure S product.
  • Substrate order: CH3X >>> 3°. Tertiary haloalkanes cannot undergo SN2 because the three bulky groups block back-side attack (steric hindrance).
  • Solvent: polar aprotic solvents (acetone, DMSO, DMF) favour SN2. These solvents solvate the cation but not the anion, leaving the nucleophile free and powerful.
  • Nucleophile: strong nucleophiles (CN-, I-, OH-, RS-) favour SN2.

SN1 Mechanism (Substitution Nucleophilic Unimolecular)

SN1 is a two-step stepwise mechanism. First, the C-X bond breaks heterolytically to form a carbocation intermediate. Then, the nucleophile attacks the planar carbocation from either face.

  • Rate: rate = k [RX]. Only depends on substrate concentration (unimolecular, first order). Rate-determining step is carbocation formation.
  • Stereochemistry: racemisation (mixture of R and S products) because the planar carbocation can be attacked from both faces equally.
  • Substrate order:>>> CH3X. Tertiary carbocations are most stable (hyperconjugation and inductive effect), so 3° undergoes SN1 fastest.
  • Solvent: polar protic solvents (water, alcohols, acetic acid) favour SN1. They stabilise the carbocation intermediate and the leaving group anion by solvation.
  • Rearrangements: carbocation intermediates in SN1 can rearrange via hydride shift or methyl shift to form a more stable carbocation before the nucleophile attacks.
FeatureSN1SN2
MechanismStepwise (2 steps)Concerted (1 step)
IntermediateCarbocationNone (transition state only)
Rate lawk[RX] — unimoleculark[RX][Nu] — bimolecular
StereochemistryRacemisationWalden inversion
Best substrate3° (most stable carbocation)1° or CH3 (least steric hindrance)
SolventPolar protic (water, ROH)Polar aprotic (DMSO, acetone)
Nucleophile strengthWeak is fine (water)Strong required (CN-, I-)
Rearrangements?Yes (carbocation can shift)No

Common Nucleophilic Substitution Reactions

Reagent (Nu:)ProductReaction name
NaOH (aqueous)R-OH (alcohol)Hydrolysis
KCNR-CN (nitrile, chain extends by 1C)Cyanide substitution
AgCNR-NC (isonitrile)Isocyanide formation
NH3 (excess)R-NH2 (primary amine)Ammonolysis
NaOR' (alkoxide)R-O-R' (ether)Williamson ether synthesis
AgNO2R-ONO (nitrite ester)Nitrite formation
NaNO2R-NO2 (nitroalkane)Nitroalkane synthesis
R'MgX (Grignard)R-R' (alkane, higher)Coupling

Grignard Reagent (RMgX)

Grignard reagent is formed by reacting a haloalkane with magnesium metal in dry diethyl ether: R-X + Mg (dry ether) → R-MgX. The carbon-magnesium bond is highly polar (C has partial negative charge), making it a powerful nucleophile and a strong base. It reacts with water, CO2, aldehydes, ketones, and esters. It must be kept absolutely dry because water destroys it: R-MgX + H2O → R-H + Mg(OH)X.

SN1 vs SN2 Reaction Pathway Simulator

Select substrate type, nucleophile strength, and solvent. The simulator predicts the reaction pathway, rate law, stereochemical outcome, and explains why.

Substrate Type
Example: (CH₃)₂CHBrSecondary carbocation — moderately stable
Nucleophile
OH⁻, CN⁻, I⁻, RS⁻, NH₃
Solvent
DMSO, Acetone, DMF, CH₃CN
SN2 (minor SN1)
Rate Law

rate ≈ k [RX][Nu] dominates

Stereochemistry

Predominantly Walden inversion with some racemisation

Intermediate

Mainly concerted; trace carbocation

Major Product

Predominantly inverted substitution product

Why this pathway?

Secondary substrate can go either way, but strong nucleophile + polar aprotic solvent tips the balance towards SN2. Back-side attack is possible though hindered. Some SN1 can occur but SN2 dominates under these conditions.

Quick Reference
SN1 favoured by:3° substrate
Polar protic solvent
Weak nucleophile
Stable carbocation
SN2 favoured by:1°/CH₃ substrate
Polar aprotic solvent
Strong nucleophile
Low steric hindrance

Elimination Reactions (E1 and E2)

When a haloalkane is treated with a strong base, elimination (loss of HX) can compete with substitution. The product is an alkene.

E2 Mechanism (Elimination Bimolecular)

E2 is a one-step concerted mechanism. The base abstracts a proton from the beta carbon at the same time the leaving group departs. The base and substrate both appear in the rate law: rate = k[RX][Base].

  • Stereochemistry: requires anti-periplanar arrangement (180°) of H and leaving group. This is the anti elimination rule.
  • Regioselectivity: Zaitsev's rule — the major product is the more substituted (more stable) alkene. E.g., 2-bromobutane + KOH/alc → mainly but-2-ene (more substituted), not but-1-ene.
  • Favoured by: 3° substrates, strong bulky base (KOtBu), high temperature, polar aprotic solvent.

E1 Mechanism (Elimination Unimolecular)

E1 is a two-step stepwise mechanism. A carbocation forms first (same first step as SN1), then a base removes a beta proton. Rate = k[RX] (unimolecular). Favoured by: 3° substrate, weak base, polar protic solvent, high temperature. Gives Zaitsev product.

Substitution vs Elimination: How to Choose

  • Strong, concentrated base + high temperature: elimination favoured
  • Weak base or neutral nucleophile + low temperature: substitution favoured
  • Bulky base (KOtBu): strongly favours E2 even for 1° substrates
  • KOH in aqueous ethanol: favours substitution (SN2)
  • KOH in alcoholic solution (alc. KOH): favours E2 elimination

Optical Isomerism in Haloalkanes

A haloalkane with a chiral centre (an sp3 carbon bearing four different groups) shows optical isomerism. The two non-superimposable mirror-image forms are called enantiomers.

  • Dextrorotatory (+): rotates plane-polarised light clockwise.
  • Laevorotatory (-): rotates plane-polarised light anticlockwise.
  • Racemic mixture (±): equal mixture of both enantiomers. Optically inactive (rotations cancel out).
  • R and S configuration: assigned by CIP (Cahn-Ingold-Prelog) rules. Arrange substituents in decreasing priority. If the arrangement (highest to lowest) is clockwise with the lowest priority group pointing away, the centre is R (rectus). If anticlockwise, it is S (sinister).

SN2 gives inversion: R substrate + Nu → S product (Walden inversion).

SN1 gives racemisation: chiral substrate → racemic product (planar carbocation attacked from both faces).

Example: 2-bromobutane (CH3CHBrC2H5) has a chiral centre. It exists as two enantiomers: (R)-2-bromobutane and (S)-2-bromobutane.

Polyhalogen Compounds and Their Uses

CompoundFormulaUse / Notes
Dichloromethane (DCM)CH2Cl2Paint remover, metal cleaning solvent, decaffeination of coffee
Trichloromethane (Chloroform)CHCl3Formerly used as anaesthetic; now solvent for gums, resins, etc. Slowly oxidised to phosgene (COCl2) in air — stored in dark bottles with ethanol as stabiliser
IodoformCHI3Yellow solid, antiseptic (due to slow release of I2). Iodoform test identifies CH3CO- group or CH3CHOH- group in compounds
Carbon tetrachlorideCCl4Formerly fire extinguisher, dry cleaning; now restricted (toxic, ozone depleting)
Freons (CFCs)CF2Cl2 (Freon-12)Refrigerants, aerosol propellants; now banned — cause ozone layer depletion in stratosphere
DDT(ClC6H4)2CHCCl3First organochlorine insecticide; banned in many countries due to non-biodegradability and biomagnification in food chains

Haloarenes: Structure and Reactivity

Why Haloarenes Are Less Reactive Than Haloalkanes

In haloarenes, the halogen atom is directly bonded to the aromatic ring. The lone pairs on the halogen interact with the pi electron system of the ring by resonance (mesomeric effect). This delocalisation gives the C-X bond partial double-bond character, making it shorter and stronger than a typical C-X single bond in haloalkanes.

As a result, nucleophilic substitution is much more difficult in haloarenes. The C-X bond energy is higher and the carbon is less electrophilic because of electron donation from the ring via resonance.

Resonance Structures of Chlorobenzene

Chlorobenzene shows five resonance structures. In two of them, negative charge appears on the ortho and para carbons of the ring, and there is a C=Cl double bond. This confirms the partial double-bond character of C-Cl and explains why the C-Cl bond in chlorobenzene (169 pm) is shorter than that in cyclohexyl chloride (179 pm).

Electrophilic Aromatic Substitution of Haloarenes

Even though halogens are electron-withdrawing by induction (sigma framework), they areortho-para directing by resonance in electrophilic aromatic substitution. The lone pair donation from halogen to the ring activates the ortho and para positions towards electrophilic attack, but deactivates the ring overall (reaction is slower than benzene itself).

  • Overall effect: halogen = deactivating (ring is less reactive than benzene) but ortho-para directing.
  • Chlorobenzene + Cl2 (FeCl3) → mixture of 1,2-dichlorobenzene and 1,4-dichlorobenzene (ortho and para products). Very little 1,3-dichlorobenzene (meta product).

Nucleophilic Aromatic Substitution (NAS)

Haloarenes can undergo nucleophilic substitution under extreme conditions or when strongly electron-withdrawing groups are present at ortho/para positions.

  • Dow process (industrial): chlorobenzene + NaOH (steam, 300°C, 200 atm) → sodium phenoxide → phenol + NaCl. Very harsh conditions needed.
  • Meisenheimer complex mechanism: nucleophile adds first (addition step) to form a negatively charged cyclohexadienyl anion (Meisenheimer complex), then the leaving group departs. The rate-determining step is the addition, not the departure of halide.
  • Activation by electron-withdrawing groups: NO2 groups at ortho/para positions stabilise the Meisenheimer complex by delocalising its negative charge. 2,4,6- trinitrochlorobenzene (picryl chloride) reacts even with weak nucleophiles.
  • Benzyne intermediate mechanism: at moderate temperatures, some haloarene reactions proceed via a benzyne (dehydrobenzene) intermediate, where HX is eliminated first and then the nucleophile adds across the triple bond.

Wurtz-Fittig Reaction

Aryl halide + alkyl halide + 2Na → aryl-alkyl compound + 2NaX. Example: C6H5Br + CH3Br + 2Na → C6H5CH3 (toluene) + 2NaBr.

Fittig Reaction

Two molecules of aryl halide + 2Na → diaryl compound + 2NaX. Example: 2 C6H5Br + 2Na → C6H5-C6H5 (biphenyl) + 2NaBr.

Haloarene Reactivity Explorer

Compare different halogen compounds — from simple haloalkanes to haloarenes to activated aryl halides. See how structure determines reactivity through resonance, bond strength, and mechanism differences.

Select Compound
Chlorobenzene

C₆H₅Cl

Haloarene
Nucleophilic Substitution Reactivity
Very Low

C-X Bond Length

169 pm (shorter than C-Cl in haloalkane: 177 pm)

C-X Bond Character

Partial double bond character due to resonance donation of lone pairs into ring pi system

EAS Directing Effect

Ortho-para directing; ring is overall deactivated vs benzene

NAS / SN Susceptibility

Very poor — requires extreme conditions (300°C, 200 atm NaOH, Dow process)


Resonance and Mechanism Insight

Cl lone pairs overlap with ring pi orbitals → 5 resonance structures. Negative charge delocalised to ortho/para positions. C-Cl bond strengthened.

Key Facts for NEET
  • C-Cl bond shorter and stronger than in cyclohexyl chloride

  • Electrophilic substitution gives mainly o- and p-dichlorobenzene

  • Used as solvent and intermediate for phenol (Dow process)

  • Benzene ring less reactive than benzene itself (Cl deactivates by -I effect)

Nucleophilic Substitution Reactivity Order (SN)

Benzyl Cl > Cyclohexyl Cl (CH₃)₃CCl > Fluorobenzene > Chlorobenzene

Benzyl chloride reacts fast via resonance-stabilised SN1. Haloalkanes react by SN1/SN2 depending on substitution. Haloarenes react poorly — their C-X bond has partial double bond character. Activated haloarenes (with NO₂) react by NAS.

Worked NEET Problems

1

NEET-style problem · SN1 mechanism

Question

Which of the following undergoes SN1 reaction most readily? (A) CH3Cl (B) (CH3)2CHCl (C) (CH3)3CCl (D) CH3CH2Cl

Solution

Answer: (C) (CH3)3CCl (tert-butyl chloride). SN1 rate depends on the stability of the carbocation formed. The order of carbocation stability is: 3° > 2° > 1° > methyl. (CH3)3CCl forms a tertiary carbocation stabilised by hyperconjugation from three methyl groups. The other options form less stable carbocations. Trick: SN1 = 3° is best; SN2 = 1°/CH3 is best.
2

NEET-style problem · SN2 stereochemistry

Question

The reaction of (R)-2-bromobutane with NaOH in aqueous ethanol gives: (A) (R)-butan-2-ol only (B) (S)-butan-2-ol only (C) racemic mixture (D) elimination product

Solution

Answer: (B) (S)-butan-2-ol only. OH- is a strong nucleophile and drives SN2. SN2 proceeds with complete Walden inversion: the nucleophile attacks from the back side at 180° to Br, inverting configuration from R to S. The product is optically pure — not racemic. Racemisation is characteristic of SN1, not SN2.
3

NEET-style problem · SN2 reactivity order

Question

Arrange in increasing order of reactivity towards SN2: (i) CH3Cl (ii) (CH3)3CCl (iii) CH3CH2Cl (iv) (CH3)2CHCl

Solution

Answer: (ii) < (iv) < (iii) < (i) — that is 3° < 2° < 1° < methyl. SN2 rate decreases with steric hindrance. The nucleophile must approach from the back side at 180° to C-X. Three methyl groups in (CH3)3CCl completely block approach (slowest). CH3Cl has zero alkyl groups — fastest SN2. This is the exact reverse of SN1 reactivity order.

Summary Cheat Sheet

Reactivity of Halogens

  • C-X bond strength: C-F > C-Cl > C-Br > C-I
  • C-X reactivity (ease of breaking): C-I > C-Br > C-Cl > C-F
  • Leaving group ability: I- > Br- > Cl- > F-

SN1 vs SN2 One-Line Rules

  • 3° + weak Nu + polar protic solvent = SN1 (racemisation)
  • 1°/CH3 + strong Nu + polar aprotic solvent = SN2 (inversion)
  • Benzyl and allyl substrates: both SN1 and SN2 fast (resonance-stabilised carbocation for SN1, good orbital overlap for SN2)

Key Name Reactions

  • Finkelstein: R-Cl/R-Br + NaI (dry acetone) → R-I (halogen exchange)
  • Swartz: R-Cl + AgF → R-F (fluoroalkane synthesis)
  • Grignard: R-X + Mg (dry ether) → R-MgX (powerful nucleophile/base)
  • Wurtz: 2 R-X + 2Na → R-R + 2NaX (coupling, symmetrical alkane)
  • Wurtz-Fittig: ArX + RX + 2Na → Ar-R + 2NaX
  • Fittig: 2 ArX + 2Na → Ar-Ar + 2NaX (biaryl synthesis)

Haloarenes vs Haloalkanes

  • Haloarenes: less reactive (C-X has partial double bond character due to resonance)
  • Haloarenes in EAS: ortho-para directing but ring-deactivating
  • Haloarenes in NAS: need electron-withdrawing groups (NO2) at ortho/para OR extreme conditions
  • Benzyl chloride (C6H5CH2Cl): behaves like haloalkane (allylic/benzylic resonance)

Frequently asked questions

What is the difference between SN1 and SN2 reactions? How do you predict which one will occur?

SN1 (unimolecular) is a two-step reaction: the C-X bond breaks first to form a carbocation, then the nucleophile attacks. SN2 (bimolecular) is a one-step concerted reaction: the nucleophile attacks the back side of the carbon as the leaving group leaves simultaneously. To predict which occurs, check three things: (1) Substrate: 3° always SN1 (carbocation stable), 1° and CH3 always SN2 (no steric block), 2° can be either. (2) Nucleophile: strong nucleophile (CN-, OH-, I-) drives SN2; weak nucleophile (water, alcohol) allows SN1. (3) Solvent: polar protic (water, alcohols) stabilises carbocation, favours SN1; polar aprotic (DMSO, acetone, DMF) leaves nucleophile free and reactive, favours SN2. The stereochemical outcome is key: SN1 gives racemisation; SN2 gives Walden inversion (complete inversion of configuration).

Why is the C-X bond in haloarenes stronger than in haloalkanes?

In haloarenes (like chlorobenzene), the halogen is directly attached to the aromatic ring. The lone pairs on the halogen can overlap with the pi system of the ring through resonance. This resonance delocalises electron density from the halogen into the ring, giving the C-X bond partial double-bond character. Because of this partial double bond, the C-X bond in chlorobenzene (bond length 169 pm) is shorter and stronger than in cyclohexyl chloride (179 pm). This extra strength means the C-X bond is harder to break, making haloarenes much less reactive than haloalkanes towards nucleophilic substitution.

What is the Finkelstein reaction and why does it work in dry acetone?

The Finkelstein reaction converts an alkyl chloride or bromide to an alkyl iodide using sodium iodide in dry acetone: R-Cl + NaI (dry acetone) → R-I + NaCl. The driving force is solubility. Sodium iodide is soluble in acetone, but the products NaCl and NaBr are practically insoluble in acetone and precipitate out of solution. By Le Chatelier's principle, this removes products from the equilibrium and drives the reaction forward to almost complete conversion. You can't use water as solvent because all sodium halides are soluble in water, so the equilibrium doesn't shift far.

What is optical isomerism and which haloalkane is the classic NEET example?

Optical isomers (enantiomers) are non-superimposable mirror images of each other. They arise when a carbon atom has four different groups attached (a chiral centre). The two enantiomers rotate plane-polarised light in opposite directions: one is dextrorotatory (+) and the other is laevorotatory (-). An equal mixture of both is a racemic mixture and shows no net optical activity. The classic NEET example is 2-bromobutane: CH3-CHBr-C2H5. The middle carbon carries four different groups (CH3, Br, H, and C2H5), making it a chiral centre. It exists as (R)-2-bromobutane and (S)-2-bromobutane. SN2 on (R)-2-bromobutane with OH- gives (S)-butan-2-ol (inversion). SN1 gives a racemic mixture of both.

Why are haloarenes ortho-para directing in EAS even though they deactivate the ring?

This seems contradictory but makes sense when you separate two effects. The halogen withdraws electrons from the ring through the sigma bond (inductive effect, -I), which deactivates the ring overall and makes it less reactive than benzene. But the halogen also donates lone pair electrons into the pi system by resonance (+M), and this donation specifically activates the ortho and para positions. The positive charge in the resonance structures appears at ortho and para positions on the ring, stabilising the electrophilic attack intermediate at those positions. The net result: ring is deactivated (slower than benzene) but the little reaction that does occur is directed to ortho and para positions. Electrophilic attack at meta would not be stabilised by resonance from the halogen.

What is the Grignard reagent and what are its common reactions?

A Grignard reagent (R-MgX) is made by reacting a haloalkane with magnesium metal in dry diethyl ether: R-X + Mg → R-MgX. The C-Mg bond is highly polar (carbon is nucleophilic), so Grignard reagents act as powerful nucleophiles and strong bases. Key reactions: (1) Water: R-MgX + H2O → R-H + Mg(OH)X (destroyed — must keep it dry). (2) Aldehyde: R-MgX + RCHO → R-CHOH-R (secondary alcohol after hydrolysis). (3) Ketone: R-MgX + R'COR' → tertiary alcohol. (4) Formaldehyde (HCHO): gives primary alcohol. (5) CO2: R-MgX + CO2 → RCOOH (carboxylic acid, chain extended by 1C). Grignard reagents are essential for making C-C bonds and are one of the most important synthetic tools in organic chemistry.

What is the iodoform test and which compounds give a positive result?

The iodoform test detects the presence of a CH3CO- (methyl ketone) or CH3CHOH- (secondary alcohol with methyl group) group. The reagent is NaOI (made in situ from I2 + NaOH). Positive test: a yellow precipitate of CHI3 (iodoform) with its characteristic antiseptic smell forms. Compounds that give a positive iodoform test: (1) Acetaldehyde (CH3CHO) — only aldehyde that gives positive. (2) All methyl ketones (CH3COR). (3) Ethanol (CH3CH2OH). (4) All secondary alcohols of the type CH3CHOHR. (5) Acetone. (6) Isopropanol (CH3CHOHCH3). Compounds that do NOT give iodoform test: benzaldehyde, formaldehyde, other aldehydes, 1° alcohols (except ethanol), ketones without CH3CO- group.

How does the Wurtz reaction differ from the Fittig and Wurtz-Fittig reactions?

All three reactions use sodium metal to join two organic halide molecules by eliminating NaX. The difference is in the starting halides: Wurtz reaction: two molecules of the same alkyl halide (2 R-X + 2Na → R-R + 2NaX). Used to make symmetric alkanes. Example: 2 CH3Br + 2Na → C2H6 + 2NaBr. Works only for haloalkanes. Fittig reaction: two molecules of aryl halide (2 Ar-X + 2Na → Ar-Ar + 2NaX). Used to make symmetric biaryls (diaryl compounds). Example: 2 C6H5Br + 2Na → biphenyl + 2NaBr. Wurtz-Fittig reaction: one aryl halide + one alkyl halide + 2Na → Ar-R + 2NaX. Used to attach an alkyl group to an arene. Example: C6H5Br + CH3Br + 2Na → toluene (C6H5CH3) + 2NaBr.

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