10 NEET previous-year questions on Polymers, each with the correct answer and a step-by-step solution. Sourced directly from official NEET papers across every booklet code.
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( CH 2 – C = CH – CH 2 ) | Cl n
( CH 2 – CH ) | Cl n
( N – (CH 2 ) 6 – N – C – (CH 2 ) 4 – C ) || n O || O | H | H
| OH CH 2 | CH 2 n
Solution
Option (d) represents a phenol-formaldehyde resin, which is a thermosetting polymer. Thermosetting polymers, like Bakelite, are formed by the condensation of phenol and formaldehyde and do not melt on heating but decompose, as described in NCERT XII chapter Polymers.
Propylene and para HO – (C 6 H 4 ) – OH
Benzoic acid and ethanol
Terephthalic acid and ethylene glycol
Benzoic acid and para HO – (C 6 H 4 ) – OH
Solution
Dacron, a polyester, is formed by the polymerization of terephthalic acid and ethylene glycol. This reaction is a typical condensation polymerization, as described in NCERT XII chapter Polymers, making option (c) correct.
Nylon-6,6
Nylon-6
Teflon
Terylene
Solution
www.vedantu.com 63
All cis – configuration
All trans – configuration
Alternate cis – and trans – configuration www.vedantu.com 33
Random cis – and trans – configuration
Solution
Natural rubber consists of polymerized isoprene units with all cis-configuration, which gives it elasticity and flexibility. NCERT XII chapter Polymers describes natural rubber as a cis-1,4-polyisoprene, so option (a) is correct.
Examples are bakelite and melamine.
They are formed from bi- and tri-functional monomers.
They contain covalent bonds between various linear polymer chains.
They contain strong covalent bonds in their polymer chains.
Solution
Cross-linked or network polymers are formed from monomers with at least two functional groups, not bi- and tri-functional monomers. Examples include bakelite and melamine, which contain covalent bonds between polymer chains and within the chains. Therefore, option (b) is incorrect.
0.5 × 10−10
0.5 × 10−15 11 SPACE FOR ROUGH WORK
0.25 × 10−10
0.125 × 10−15
Solution
𝐶𝑎(𝑂𝐻)2=𝐶𝑎+2+2𝑂𝐻− 𝑝𝐻= 9, so pOH = 5, so [𝑂𝐻−]=10−5 M at equilibrium, [𝑂𝐻−]=10−5 M [𝐶𝑎+2]=0.5×10−5 M 𝐾𝑆𝑃=[𝐶𝑎+2][𝑂𝐻−]2= ( 1 2×10−5)×(10−5)2= 0.5×10−15
cis -1,4-polyisoprene
poly (Butadiene-styrene)
polybutadiene
poly (Butadiene-acrylonitrile)
Solution
cis-1,4-polyisoprene is the natural polymer found in rubber latex, derived from rubber trees. Other options are synthetic polymers, so option (a) is correct.
Teflon
Nylon-66
Novolac
Dacron
Solution
Teflon (polytetrafluoroethylene) is prepared by addition polymerisation of tetrafluoroethylene. Nylon-66, Novolac, and Dacron are formed by condensation polymerisation, so option (a) is correct.
Elastomers have polymer chains held together by weak intermolecular forces
Fibers possess high tensile strength
Thermoplastic polymers are capable of repeatedly softening and hardening on heating and cooling respectively
Thermosetting polymers are reusable
Solution
• Thermoplastic polymers are the linear or slightly long chain molecules capable of repeatedly softening and hardening on cooling. • Thermosetting polymers are cross-linked or heavily branched molecules, which on heating undergo extensive cross-linking in moulds and again become infusible. These cannot be reused. • Elastomers have polymer chains held together by weak intermolecular forces. • Fibres possess high tensile strength.
H₂C=C(CH₃)−CH=CH₂
H₂C=CH−CH=CH₂
H₂C=C(Cl)−CH=CH₂
H₂C=CH−C≡CH
Solution
Neoprene is produced by the polymerization of chloroprene, whose monomer structure is . NCERT XII chapter Polymers lists chloroprene as the monomer for neoprene, so option (c) is correct.
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