32 NEET previous-year questions on Current Electricity, each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.
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24 Ω
6 Ω
0.17 Ω
14 Ω
Solution
.
12 Ω
4 Ω
4/3 Ω
1 Ω
Solution
.
4.84 Ω
48.4 Ω
484 Ω
4840 Ω
Solution
.
Solution
Balance: . (Equivalently .)
0.5 A
1 A
1.2 A
6 A
Solution
.
R
2R
4R
R/2
Solution
Volume conserves: A halves when L doubles. becomes .
Charge conservation
Energy conservation
Mass conservation
Newton's third law
Solution
KVL: sum of voltage changes around a loop is zero. This is energy conservation per unit charge.
2.4 Ω
4 Ω
10 Ω
24 Ω
Solution
Series: 4 + 6 = 10 Ω.
60 W bulb
100 W bulb
Equally bright
Neither glows
Solution
Series: same current. Lower-watt bulb has higher resistance, so is bigger for higher R. The 60 W bulb (higher R) is brighter.
Solution
From : .
Less than EMF
Equal to EMF
Greater than EMF
Zero
Solution
During charging, current flows INTO the cell. .
0 A
4 A
6 A
8 A
Solution
KCL: .
Ω
Ω/m
Ω·m
V/m
Solution
From : has units of .
Zero
Maximum
Equal to battery current
Half the battery current
Solution
Balance condition: V_B = V_D, so no current flows through the galvanometer.
Solution
Two equal R in parallel = R/2.
4.5 A
9 A
11 A
20 A
Solution
.
Solution
Maximum power transfer: external R = internal r. Power , half lost inside.
Zero
Sum of all currents
Sum of IR drops
Sum of all resistances
Solution
KVL: around any closed loop.
2:3
3:2
1:2
2:1
Solution
.
0.08 V
2 V
12.5 V
20 V
Solution
.
Solution
Each piece has R/5. Five of these in parallel: R/(5 \cdot 5) = R/25.
Stays the same
Doubles
Quadruples
Halves
Solution
At fixed length, doubles, so doubles.
0.3 kWh
300 J
60 J
5 kWh
Solution
.
10 V
6 V
4 V
2 V
Solution
Opposite polarity: subtract. .
Positive
Negative
Zero
Depends on the metal
Solution
Metals: heating raises atomic vibrations, scattering more electrons. R rises with T. .
25 Ω
50 Ω
100 Ω
200 Ω
Solution
.
50 W
100 W
200 W
400 W
Solution
Each at full voltage: 100 W each. Parallel: powers add. Total = 200 W.
Solution
Two paths between any two corners: one of R, the other of 2R (going through the third corner). Parallel: .
Charge conservation
Energy conservation
Mass conservation
Newton's third law
Solution
KCL: sum of currents into a junction = sum out. Charge conservation.
V vs I curve
V vs t curve
I vs t curve
V vs V curve
Solution
. Plot V vs I: slope is . y-intercept is .
120 Ω
140 Ω
180 Ω
200 Ω
Solution
.
m/s
m/s
m/s
m/s
Solution
Drift speed is around 0.1 mm/s = m/s, despite the fact that signals propagate at near light speed.
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