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Electrostatic Potential and Capacitance

Electrostatic Potential and CapacitanceNEET Physics · Class 12 · NCERT Chapter 2

32 NEET previous-year questions on Electrostatic Potential and Capacitance, each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.

PYQ frequency · topic × year

17
18
19
20
21
22
23
24
Potential
2
1
1
Potential energy
1
1
1
Equipotential
1
1
E and V relation
1
1
1
Capacitance
1
2
1
Parallel plate
1
1
1
1
Combinations
1
2
1
Dielectric
1
2
1
Energy stored
1
1
1
1

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All (32)
Potential (4)
Potential energy (3)
Equipotential (2)
E and V relation (3)
Capacitance (4)
Parallel plate (4)
Combinations (4)
Dielectric (4)
Energy stored (4)

A

B

C

D

Solution

. Falls as 1/r.

A

Volt

B

Coulomb

C

Farad

D

Henry

Solution

, so unit = C/V = farad (F).

A

B

C

D

Solution

Standard formula: .

A

2 µF

B

2.4 µF

C

5 µF

D

10 µF

Solution

Series: .

A

B

C

D

Solution

. Standard formula.

A

B

C

D

Solution

.

A

2.4 µF

B

5 µF

C

10 µF

D

24 µF

Solution

Parallel: .

A

B

C

D

Solution

. Same form as potential except multiplied by the second charge.

A

Always zero

B

Constant

C

Variable

D

Cannot be determined

Solution

is constant (uniform).

A

0.025 J

B

0.05 J

C

0.25 J

D

0.5 J

Solution

.

A

Concentric spheres

B

Parallel planes perpendicular to E

C

Cylinders

D

Spirals

Solution

Uniform E means V changes linearly along E. Surfaces of constant V are flat planes perpendicular to E.

A

No change

B

×2

C

×4

D

×8

Solution

. A → 2A, d → d/2: .

A

Zero

B

C

D

Solution

At the midpoint: . Equal and opposite cancel.

A

Stays the same

B

Becomes K times

C

Becomes 1/K times

D

Becomes K² times

Solution

Battery keeps V constant. C → KC, so Q = CV → KQ.

A

B

C

D

Solution

Three pairs, each . Total .

A

6/11 µF

B

11/6 µF

C

6 µF

D

0.5 µF

Solution

.

A

5 µF

B

50 µF

C

500 µF

D

0.5 µF

Solution

.

A

True

B

False, energy quadruples

C

False, energy halves

D

False, energy stays

Solution

. Doubling V quadruples U.

A

4 V/m

B

−4 V/m

C

8 V/m

D

−8 V/m

Solution

. At : .

A

B

C

D

Solution

. V → V/2: U → U/4.

A

Stays the same

B

Becomes K times

C

Becomes 1/K times

D

Becomes K² times

Solution

Disconnected: Q is fixed. C → KC. .

A

Zero

B

C

D

Solution

Distance from each corner to centre = . Each charge contributes . Four charges: .

A

50 pC

B

500 pC

C

5 nC

D

50 nC

Solution

.

A

B

C

D

Solution

Series: same Q. Q = C V_{C} = 2C V_{2C}, so V_{C} = 2 V_{2C}. Total V_{C} + V_{2C} = V 3 V_{2C} = V V_{C} = 2V/3.

A

Zero

B

Maximum

C

Equals qV

D

Negative

Solution

(no potential difference along an equipotential).

A

B

C

D

Zero

Solution

The metal slab acts like an extension of one plate. Effective gap is , so .

A

B

C

D

Zero

Solution

Three pairs: (), (), (). Sum = .

A

B

C

D

Solution

Two capacitors in parallel: half area with K = 4 () plus half area without (). Total = .

A

B

C

D

Zero

Solution

Outside the shell, the system looks like a point charge at the centre. .

A

20 V

B

25 V

C

30 V

D

50 V

Solution

Charge conserves: . After: .

A

B

C

D

Solution

, so .

A

B

C

D

Solution

. Wait, sign carefully: . Field points from high to low V; A is at higher V here.

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