31 NEET previous-year questions on Electric Charges and Fields, each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.
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Repulsive,
Attractive,
Zero
Repulsive,
Solution
Opposite charges attract. Magnitude is (the negative sign just means attraction).
Solution
Coulomb's law in field form: for a point charge.
Solution
Axial: . Equatorial: .
Solution
Total flux = . By symmetry, each of 6 faces gets .
Zero
Solution
Gauss's law: enclosed charge inside shell = 0, so flux = 0 and E = 0 everywhere inside.
Solution
From Gauss's law (cylindrical surface): .
Solution
, where is the angle between E and the area normal.
Zero
Solution
The two attractive forces on -q are equal in magnitude and opposite in direction. They cancel: net force = 0.
Solution
Infinite plane: . Note that this does NOT depend on distance.
Solution
, magnitude .
Halved
Doubled
Quadrupled
Same
Solution
Flux depends only on the enclosed charge, not on the surface size: , unchanged.
Zero
Solution
Each pulls toward itself with force . The angle between these two forces is , so by parallelogram rule, magnitude .
Solution
. Minimum at .
Maximum
Minimum
Zero
Cannot say
Solution
By Gauss's law, . No charge enclosed .
Zero
Solution
Inside solid sphere, enclosed Q . By Gauss, .
Same
Solution
. Charge , distance , so , i.e., 1/8 of original.
0.45 N
4.5 N
22.5 N
45 N
Solution
.
Solution
Equatorial field: . Half of axial.
Zero
Solution
By symmetry, the four field vectors at the centre cancel pairwise. Net field = 0.
Zero
Solution
Flux through the hemisphere = flux through its flat circular base (since the closed surface has zero net flux from the uniform field): .
Zero
Solution
Outside the shell behaves like a point charge at the centre: .
Only spherical surfaces
Only conductors
Any closed surface
Only static charges
Solution
Gauss's law is exact for ANY closed surface. Spherical or cubical or irregular, the relation holds.
Solution
In a medium, .
Zero
Solution
, with : . Maximum.
Zero
Solution
At small , the y-components add (approximately linearly), x-components cancel. .
Solution
Infinite line: . Doubling r halves E.
Zero
Solution
Inside the outer shell, the outer charge contributes 0 (shell theorem). Only matters. .
Zero
Solution
.
V
V/m
V·m
C/m²
Solution
has units of (V/m) m² = V·m. Equivalent to N·m²/C.
Zero
Solution
Symmetric: forces from the two charges are equal and opposite, so net = 0. (q₀ at the midpoint of two equal charges.)
C/(N·m)
C²/(N·m²)
N·m/C
N/(C·m)
Solution
From : has units , equivalent to F/m.
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