32 NEET previous-year questions on Kinetic Theory, each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.
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Solution
From , .
Solution
Three translational degrees of freedom: each carries , so total .
Solution
At fixed T, . , . Ratio . So .
Solution
Standard kinetic theory result: .
times
times
times
unchanged
Solution
. Doubling multiplies by .
Solution
.
Solution
.
Solution
, , . So .
241 K
362 K
483 K
724 K
Solution
.
11.2 L
22.4 L
44.8 L
depends on the gas
Solution
At STP (273 K, 101325 Pa), . Same for any ideal gas.
Only the temperature
Only the density
Both density and v_rms
Only the volume
Solution
. So pressure depends on both density (rho = m/V) and v_rms (which depends on T).
Solution
Half per quadratic degree of freedom per molecule. This is the equipartition theorem.
Solution
Monoatomic: , so .
Solution
.
The same average speed
The same average translational kinetic energy
The same density
The same molar mass
Solution
Avg translational KE depends only on T, not on mass. So both have the same avg KE; the heavier gas just moves slower.
Number density only
Molecular diameter only
Both number density and molecular diameter
Temperature only
Solution
. Depends on both molecular size and number density .
0.5 atm
1 atm
2 atm
4 atm
Solution
At constant V, = const. . (Gay-Lussac's law)
Half
Twice
Four times
Same
Solution
Boyle's law at constant T: = const. Half V doubles P.
Is the same as v_rms
Is greater than v_rms
Is less than both v_avg and v_rms
Is the average of all molecular speeds
Solution
The order is for any Maxwell distribution. v_p is the speed at the peak of f(v), the smallest of the three.
Solution
Diatomic at room T: , .
150 K
300 K
450 K
600 K
Solution
. To double KE, double T: .
1.87 kJ
3.74 kJ
7.48 kJ
12.5 kJ
Solution
.
Halves
Doubles
Quadruples
Stays the same
Solution
. Halve P, double .
Doubles
Triples
Quadruples
Stays the same
Solution
at fixed density. Doubling v_rms quadruples P.
Solution
.
Solution
, so . Lighter gas, faster molecules.
Solution
, so .
Shifts the peak left, narrows the curve
Shifts the peak right, broadens the curve
Shifts the peak right, narrows the curve
Has no effect on the shape
Solution
Higher T means higher v_p (peak shifts right) and a flatter, broader distribution.
Solution
At STP, 22.4 L contains 1 mole, which is molecules. (Avogadro's number)
3
6
9
27
Solution
. Tripling v_rms multiplies P by .
Solution
Each vibrational mode = 2 quadratic dof (kinetic + potential). So energy = .
0.4 nm
40 nm
70 nm
700 nm
Solution
Standard textbook result: lambda for air at STP is about 70 nm, several hundred molecular diameters.
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