OscillationsNEET Physics · Class 11 · NCERT Chapter 13

A particle executes SHM with $a=-{\omega }^{2}x$. The motion is:

The time period of a simple pendulum of length $L$ is given by:

The time period of a mass $m$ attached to a spring of constant $k$ is:

A particle in SHM with amplitude $A$ and angular frequency $\omega$ has speed at displacement $x$ given by:

The total energy of a particle in SHM with mass $m$, amplitude $A$ and angular frequency $\omega$ is:

The maximum acceleration of a particle in SHM with amplitude $A$ and angular frequency $\omega$ is:

A pendulum's length is doubled. Its time period:

Two springs of constants $k$ and $2k$ are connected in parallel. The effective constant is:

Two springs of constants $k$ and $2k$ are connected in series. The effective constant is:

In SHM, at what displacement is the KE equal to the PE?

If $x(t)=A\sin (\omega t+\pi /2)$, the motion is equivalent to:

The time period of a simple pendulum on Earth is 2 s. On a planet where $g$ is one-fourth of Earth's, the time period is:

A 1 kg mass on a spring oscillates with $T=\pi /5\text{s}$. The spring constant is:

In SHM, the speed of the particle is maximum at:

In a damped oscillation, the amplitude:

Resonance occurs in a forced oscillator when:

A particle in SHM has $A=4\text{cm}$ and $T=2\text{s}$. Its maximum speed is:

Two SHMs $x_1=A\sin (\omega t)$ and $x_2=A\sin (\omega t+\pi /2)$ have a phase difference of:

In SHM, the average kinetic energy over a full period is:

A vertical spring stretches by 0.05 m when a 0.5 kg mass is hung from it. The time period of vertical oscillation is ($g=10{\text{m/s}}^2$):

A simple pendulum has period 2 s. To make its period 1 s, its length should be:

A particle moves on the x-axis with $x(t)=5\cos (2\pi t)\text{cm}$. The amplitude and frequency are:

In SHM, when displacement is half of amplitude, the ratio of KE to PE is:

A particle in SHM has $v_{\max }=10\text{cm/s}$ and $a_{\max }=100{\text{cm/s}}^2$. Its angular frequency is:

Same problem as above: find the amplitude $A$.

Velocity in SHM leads displacement by:

In SHM, acceleration and displacement are:

A spring-mass system has time period $T$. If the mass is doubled and the spring constant is halved, the new time period is:

A motion is SHM if its acceleration is:

Two identical springs each of constant $k$ are joined in parallel. The time period of mass $m$ becomes:

A child swings on a swing without losing energy. This is closest to:

A pendulum is taken to a freely falling lift. Its time period: