29 NEET previous-year questions on Mechanical Properties of Solids, each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.
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Solution
.
Solution
(same , ).
.
stress × strain
stress / strain
Solution
Within the elastic limit, .
Solution
.
Solution
. To double length, :
.
Solution
Force varies linearly from 0 to . Average force = . Work = average force × distance = .
Force
Energy
Pressure
Power
Solution
Stress = Force/Area, dimensions , same as pressure.
to
to
to
to
Solution
Theoretical thermodynamic bounds: . Most real materials have .
Solution
.
Stress to strain
Pressure change to volume strain
Force to area
Strain to stress
Solution
— bulk stress (pressure change) divided by volumetric strain.
Solution
Shear stress = (force per top-face area).
Shear strain = stress/G = .
Solution
Same force, same material → strain .
.
Solution
where .
.
Returns to original shape on removing the force
Shows permanent deformation
Develops cracks immediately
Has zero stress
Solution
Beyond the elastic limit, deformation becomes plastic — permanent. The body does not return fully to its original shape.
Material
Temperature
Length of the wire
Type of strain (within elastic limit)
Solution
Y is a property of the material itself. It does NOT depend on the dimensions (length, area) of the specimen — those determine the elongation under a given force, but Y stays the same.
Greater than its bulk modulus
Equal to its bulk modulus
Zero
Infinite
Solution
Fluids cannot sustain shear stress at rest — they flow under any shear. So the shear modulus is zero.
Solution
with :
.
Strain
Compressibility
Young's modulus
Modulus of rigidity
Solution
Compressibility . Higher compressibility means easier to squeeze.
Solution
In series, both have same , so .
.
Solution
Volume conservation requires .
So , giving .
Rubber has for this reason.
Smaller stress
Greater stress
Same stress
Cannot be determined
Solution
Stress = F/A. With the same force , the smaller area produces larger stress. So the thinner wire experiences greater stress (and greater strain since is the same).
Solution
. Same form as elastic PE in a stretched wire.
Same
Half
One quarter
Twice
Solution
. Twice diameter → 4× area → becomes 1/4 of original.
Twice
Three times
Four times
Same
Solution
. Doubling multiplies by 4.
Elastic limit
Young's modulus
Yield stress
Ultimate strength
Solution
In the linear region, , so the slope of stress vs strain is — Young's modulus.
Solution
.
.
Higher bulk modulus
Lower bulk modulus
Equal bulk modulus
Zero bulk modulus
Solution
Gases are highly compressible — small pressure produces large fractional volume change — so their bulk modulus is much smaller than liquids.
Solution
For most common solids, . Exact relation involves Poisson's ratio: .
Solution
Energy stored: .
Volume: .
Density: .
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