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Mechanical Properties of Fluids

Mechanical Properties of FluidsNEET Physics · Class 11 · NCERT Chapter 9

30 NEET previous-year questions on Mechanical Properties of Fluids, each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.

PYQ frequency · topic × year

15
16
17
18
19
20
21
22
23
24
Pressure
2
1
Pascal & hydraulics
1
1
1
Archimedes
2
1
2
1
Continuity
1
1
1
Bernoulli
1
1
2
1
Viscosity
1
1
1
1
Surface tension
1
1
1
2
1

Darker = more questions in our PYQ bank for that topic and year.

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All (30)
Pressure (3)
Pascal & hydraulics (3)
Archimedes (6)
Continuity (3)
Bernoulli (5)
Viscosity (4)
Surface tension (6)

A

B

C

D

Solution

Gauge pressure (above atmospheric) at depth is .

A

500 N

B

5000 N

C

50000 N

D

50 N

Solution

.

A

0.4

B

0.6

C

0.8

D

0.2

Solution

Fraction submerged = . Fraction above = 1 − 0.6 = 0.4.

A

10 N

B

40 N

C

50 N

D

90 N

Solution

Apparent loss in weight = buoyant force = .

A

0.2 m/s

B

2 m/s

C

5 m/s

D

10 m/s

Solution

.

A

B

C

D

Solution

.

A

Stays zero

B

Increases continuously

C

Increases until it reaches terminal velocity, then stays constant

D

Oscillates

Solution

Initially gravity dominates, so the ball accelerates downward. As speed grows, viscous drag (proportional to speed) grows. When drag + buoyancy = gravity, the net force is zero — the ball continues at constant terminal velocity.

A

B

C

D

Solution

.

A

B

C

D

Solution

A soap bubble has two surfaces (inner and outer), so the excess pressure is . (For a single droplet with one surface, it would be .)

A

B

C

D

Solution

. Doubling halves .

A

0.78

B

0.89

C

0.92

D

1.0

Solution

Fraction submerged = .

A

Higher pressure

B

Lower pressure

C

Same pressure

D

Zero pressure

Solution

is constant. Where is larger, must be smaller (at the same height).

A

Bernoulli's equation

B

Hydraulic press

C

Buoyancy

D

Capillary rise

Solution

Pascal's law (pressure transmitted equally in a confined fluid) is the principle behind hydraulic press and hydraulic lift.

A

Conservation of energy

B

Conservation of momentum

C

Conservation of mass

D

Bernoulli's principle

Solution

comes from the fact that the same mass of fluid that enters one section must exit another in steady, incompressible flow.

A

N/m²

B

N/m

C

N·m

D

J

Solution

Surface tension = force per unit length, units N/m. Equivalently J/m² (energy per unit area) — same numerical value.

A

~5 m

B

~10 m

C

~20 m

D

~50 m

Solution

Need .

.

A

B

C

D

Solution

. Memorise the factor of 6π.

A

B

C

D

Solution

Bernoulli: .

. Positive (so ) since in the constriction.

A

B

C

D

Solution

Soap bubble has 2 surfaces. Initial area . Final area .

.

.

A

B

C

D

Solution

Half submerged → buoyant force = weight of fluid displaced by half-volume = .

Reading = real weight − buoyant force = .

A

B

C

D

Solution

1 atm . Roughly Pa.

A

B

C

D

Solution

. Ratio .

A

B

C

D

Solution

Continuity: . Bernoulli (horizontal): .

A

Water is incompressible

B

Surface tension minimises surface area

C

Air pressure is uniform

D

Density is constant

Solution

Surface tension acts to minimise the surface area for a given volume. The geometric shape with minimum surface area for a fixed volume is a sphere.

A

0.4

B

0.5

C

0.6

D

0.7

Solution

Apparent loss in water = 30 − 20 = 10 N → buoyant force in water.

Apparent loss in liquid = 30 − 24 = 6 N → buoyant force in liquid.

Relative density = = ratio of buoyant forces = 6/10 = 0.6.

A

B

C

D

Solution

. So entry : exit = 1 : 4 (entry is narrower!).

Wait — re-checking. Higher speed means smaller area. at entry, so entry has smaller area. → entry area is 1/4 of exit area. So ratio is 1 : 4.

A

Decreasing with distance

B

Equally and undiminished

C

Only along the direction of the applied force

D

Increases with depth

Solution

Pascal's law: pressure transmitted equally in all directions, undiminished.

A

B

C

D

Solution

Fraction submerged = .

.

Closest option: 925 kg/m³.

A

B

C

D

Solution

Surface tension = force/length. Force is , so .

A

Pascal's law

B

Archimedes' principle

C

Bernoulli's principle

D

Stokes' law

Solution

Bernoulli's principle: faster air over the curved upper surface of the wing means lower pressure, slower air below means higher pressure → net upward lift.

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