30 NEET previous-year questions on Thermal Properties of Matter, each with the correct answer and a step-by-step solution. Filter by topic and expand any question to see how to solve it.
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233.15 K
273.15 K
313.15 K
0 K
Solution
.
Solution
.
Solution
, , so .
Solution
Equal masses, same specific heat: is the average .
4186 kJ
334 kJ
2260 kJ
420 kJ
Solution
.
W/m
W·m/K
W/(m·K)
W·K/m
Solution
From Fourier's law , units of : .
2
4
8
16
Solution
. Doubling multiplies the rate by .
5 min
7 min
8 min
10 min
Solution
Newton's cooling (using mean temperature approximation):
Stage 1: , rate . So .
Stage 2: . Rate . Time .
It heats up quickly
It needs a lot of heat to raise its temperature
It cools quickly
It is a poor heat conductor
Solution
High specific heat means a lot of heat is required for a given temperature change. Water's is the highest of common substances.
Solution
In series, total resistance is sum: .
.
.
Solution
Wien's displacement law: , so . Higher T → shorter peak wavelength.
40 °C
50 °C
60 °C
70 °C
Solution
Same specific heat: .
0.1%
0.2%
0.3%
0.6%
Solution
, so .
.
Solids
Liquids
Gases
Vacuum
Solution
Solids have the closest packing, so heat conducts fastest. Air (gas) has very low conductivity; vacuum has none.
180 °F
212 °F
273 °F
100 °F
Solution
. Boiling point of water.
113 kJ
167 kJ
420 kJ
210 kJ
Solution
.
The body's temperature
The square of the body's temperature
The temperature difference between body and surroundings
The thermal conductivity
Solution
— proportional to the temperature excess above surroundings.
Solution
. Ratio .
Solution
.
Solution
In series, .
— the harmonic mean.
50 °C
100 °C
200 °C
500 °C
Solution
.
250 nm
500 nm
1000 nm
2000 nm
Solution
Wien: const. Halving T doubles . So peak shifts to (infrared).
Raise the temperature of ice from −10 to 0 °C
Convert ice at 0 °C to water at 0 °C
Convert water at 0 °C to steam at 100 °C
Boil water at 100 °C
Solution
Latent heat of fusion = energy per unit mass to convert solid to liquid at the melting point, with no temperature change.
Solution
In parallel: areas add. Effective .
Solution
Set : .
.
Solution
Mayer's relation: .
Cool the jar
Cool the lid
Heat the lid (brass expands more)
Apply pressure
Solution
Brass has higher α than glass. Heating the lid causes it to expand more than the jar's neck, loosening the fit.
15 g
20 g
40 g
60 g
Solution
Heat absorbed by water = .
Heat released by steam (condensing + cooling): .
.
The temperature difference is very small
The body is in vacuum
The temperature difference is very large
There is no air
Solution
Newton's law (linear in temperature difference) holds for small temperature differences and for natural convection cooling. For large differences, radiation (T⁴ law) dominates.
420 J/(kg·K)
4186 J/(kg·K)
40 J/(kg·K)
420 cal/(g·K)
Solution
in SI units. Equivalent to .
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