54 NEET previous-year questions on Cell: The Unit of Life, each with the correct answer and a step-by-step solution. Sourced directly from official NEET papers across every booklet code.
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Nucleoid
Ribosomes
Cell wall
Mesosomes
Solution
Mesosomes, which are invaginations of the plasma membrane in bacteria, perform functions similar to those of mitochondria, including respiration and energy production. NCERT XI chapter Cell: The Unit of Life describes mesosomes as the sites of respiratory enzymes in bacteria, so option (d) is correct.
Microtubules
Microfilaments
Intermediate filaments
Lamins Ans. [2] Sol . Microfilament are made up of 2 molecules of 6 nm actin protein. Microtubule are 25 nm hollow tube like structure while intermidiate filament are 10 nm and lamins are nuclear proteins.
Solution
Microfilaments are solid, linear cytoskeletal elements with a diameter of 6 nm, composed of actin monomers. NCERT XI chapter Cell: The Unit of Life describes microfilaments as such, so option (b) is correct.
Mitochondria
Vacuoles
Plastids
Ribosomes
Solution
Vacuoles regulate the osmotic expansion of a cell by controlling water uptake and maintaining turgor pressure. NCERT XI chapter Cell: The Unit of Life describes vacuoles as key organelles in osmoregulation, so option (b) is correct.
(iv) (ii) (i) (iii)
(i) (ii) (iv) (iii)
(i) (iii) (ii) (iv)
(iv) (iii) (i) (ii)
Solution
- Centriole - (iv) Basal body cilia or flagella
- Chlorophyll - (ii) Thylakoids
- Cristae - (i) Infoldings in mitochondria
- Ribozymes - (iii) Nucleic acids
Cyanobacteria
Sea-fan ( Gorgonia )
Saccharomyces
Blue-green algae
Solution
Sea-fan (Gorgonia) is an animal, and animal cells lack cell walls. Cyanobacteria, Saccharomyces (yeast), and blue-green algae (cyanobacteria) all have cell walls, so option (b) is correct.
Fimbriae
Flagella
Cilia
Pili
Solution
Motile bacteria move using flagella, which are long, whip-like structures that propel the cell. NCERT XI chapter Cell: The Unit of Life describes flagella as the primary organelles for bacterial motility, so option (b) is correct.
Substrate binds with enzyme at its active site
Addition of lot of succinate does not reverse the inhibition of succinic dehydrogenase by malonate
A non-competitive inhibitor binds the enzyme at a site distinct from that which binds the substrate
Malonate is a competitive inhibitor of succinic dehydrogenase
Solution
Option (b) is incorrect because the inhibition of succinic dehydrogenase by malonate is competitive, meaning that adding more succinate can reverse the inhibition by outcompeting malonate for the active site. NCERT XI chapter Cell The Unit of Life explains competitive inhibition in this context, so option (b) is the correct choice.
Maltose
Sucrose
Lactose
Ribose 5-phophate
Solution
Sucrose is a non-reducing sugar because it lacks a free aldehyde or ketone group due to the formation of a glycosidic bond between glucose and fructose. NCERT XI chapter Cell The Unit of Life classifies sucrose as a non-reducing carbohydrate, so option (b) is correct.
(iv) (iii) (i) (ii)
(iii) (iv) (i) (ii)
(iii) (i) (iv) (ii)
(iii) (iv) (ii) (i)
Solution
Thylakoids – Flat membranous sacs in stroma of chloroplast. Cristae – Infoldings in mitochondria Cisternae – Disc-shaped sacs in golgiapparatus Chromatin – Condensed structure of DNA.
Nuclear envelope
Ribosome
Mesosome
Plasma membrane
Solution
True nucleus is absent in prokaryotic cell.
Penicillium is multicellular and produces antibiotcs
Neurospora is used in the study of biochemical genetics
Morels and truffles are poisonous mushrooms
Yeast is unicellular and useful in fermentation
Solution
Morels and truffles are edible fungi belong to class ascomycetes.
Vacuoles
Ribosomes
Lysosomes
Mesosomes www.vedantu.com 12
Solution
Ribosomes are made up of r-RNA and proteins.
Nuclei, ribosomes and mitochondria
Chromosomes, ribosomes and endoplasmic reticulum
Endoplasmic reticulum, ribosomes and nuclei
Lysosomes, Golgi apparatus and mitochondria www.vedantu.com 23
Solution
Lysosomes, Golgi apparatus and mitochondria are membrane bound organelles.
Aspergillus
Funaria
Mycoplasma
Nostoc www.vedantu.com 7
Solution
Mycoplasma is wall-less smallest living organism
Without plasma membrane
Without nucleus
Undergoing division
Without cell wall
Solution
Plant cell — Cell wall = Protoplast
Performing cementing to keep neighbouring cell together
Facilitate communication between adjoining cells by connecting the cytoplasm for rapid transfer of ions, small molecules and some large molecules.
Separate two cells from each other
Stop substance from leaking across a tissue
Solution
Gap junctions are communicating junctions in animals which facilitates communication between two adjoining cells by protein bridges for rapid transfer of ions, small molecules and large molecules.
The viroids were discovered by D.J. Jvanowski
W.M. Stanley showed that viruses could be crystallized
The term ‘contagium vivum fluidum’ was coined by M.W. Beijerinek
Mosaic disease in tobacco and AIDS in human being are caused by viruses
Solution
The viroids were discovered by T.O. Diener.
Lipid synthesis
Nucleotide synthesis
Polysaccharide synthesis
RNA and protein synthesis
Solution
Balbiani rings are the large chromosome puff of polytene chromosomes. These are the sites of RNA and protein synthesis.
Both (i) and (ii) are correct
(ii) is true but (i) is false
(i) is true but (ii) is false
Both (i) and (ii) are false
Solution
Mitochondria and chloroplast are semi-autonomous organelles and they have their own ribosomes with help of which they can synthesize protein.
Cilia, Flagella and Peroxisomes
Spindle fibres, centrioles and cilia
Centrioles, spindle fibres and chromatin
Centrosome, Nucleosome and Centrioles
Solution
Peroxisomes is a microbody. Chromatin consists of DNA and proteins and it condenses to form chromosomes. Nucleosome is the basic unit of chromatin. Microtubules are structures present in cilia, flagella, centrioles and spindle fibres.
Polysome
Polymer
Polypeptide
Okazaki fragment
Solution
Many ribosomes are attached to a single strand of mRNA during protein synthesis. This is known as Polysome.
Mitochondria
Chloroplasts
Lysosomes
Nuclei
Solution
Except lysosomes, all three are bounded by double membrane.
Lysosome
Ri bosome
Chloroplast
Mitochondrion
Solution
Mitochondria are the site of aerobic oxidation of carbohydrates to generate ATP. 1 15. The process of separation and purification of expressed protein before marketing is called (1) Upstream processing (2) Downstream processing (3) Bioprocessing (4) Postproduction processing Answer (2) Sol. Biosynthetic stage for synthesis of product in recombinant DNA technology is called upstreaming process while after completion of biosynthetic stage, the product has to be subjected through a series of processes which include separation and purification are collectively referred to as downstreaming processing.
During S-phase
Within nucleolus
Prior to fission
Just before transcription
Solution
DNA replication in bacteria occurs prior to fission. Prokaryotes do not show well marked S-phase due to their primitive nature.
Respiration in bacteria
Formation of secretory vesicles
Fatty acid breakdown
Activation of amino acid
Solution
The Golgi complex is involved in the formation and modification of secretory vesicles, which transport substances out of the cell. NCERT XI chapter Cell: The Unit of Life describes the Golgi complex's role in packaging and secreting cellular products, so option (b) is correct.
It takes part in spindle formation.
It is a membrane-bound structure.
Larger nucleoli are present in dividing cells.
It is a site for active ribosomal RNA synthesis.
Solution
The nucleolus is the site for active ribosomal RNA synthesis and assembly of ribosomal subunits. NCERT XI chapter Cell: The Unit of Life describes the nucleolus as a non-membrane-bound structure involved in rRNA synthesis, so option (d) is correct.
Cleavage of signal peptide
Protein glycosylation
Protein folding
Phospholipid synthesis
Solution
Phospholipid synthesis occurs in the smooth endoplasmic reticulum, not the rough endoplasmic reticulum. The rough endoplasmic reticulum is primarily involved in protein synthesis, folding, and modification, so option (d) is correct.
Plastidome
Polyhedral bodies
Polysome
Nucleosome
Solution
Strings of ribosomes associated with a single mRNA to form multiple copies of a polypeptide simultaneously are termed as polysomes. NCERT XI chapter Cell: The Unit of Life describes this phenomenon, so option (c) is correct.
Free-central
Basal
Axile
Parietal
Solution
Ref. XI NCERT Chapter- 05, Page No. 75
Terminate the cell cycle
Exit the cells cycle
enter the cell cycle
Suspend the cell cycle
Solution
In 𝐺0 phase cell is inactive for division but may again become active based on body requirements.
Cell-mediated immune response
Humoral immune response
Humoral immune response
Inflammatory immune response
Solution
Factual- NCERT
They are not bound by any membrane.
These are involved in ingestion of food particles.
They lie free in the cytoplasm.
These represent reserve material in cytoplasm.
Solution
Inclusion bodies are non-membrane-bound structures that lie free in the cytoplasm and store reserve materials like glycogen, lipids, and proteins. They are not involved in the ingestion of food particles, which is a function of phagocytosis, so option (b) is incorrect.
Endoplasmic reticulum
Peroxisomes
Golgi bodies
Polysomes
Solution
Golgi bodies are the primary site for the formation of glycoproteins and glycolipids in eukaryotic cells. NCERT XI chapter Cell The Unit of Life describes the Golgi apparatus as the site where proteins and lipids are modified, sorted, and packaged for secretion or delivery to other organelles, so option (c) is correct.
(iv) (iii) (ii) (i)
(i) (iv) (iii) (ii)
(iii) (iv) (i) (ii)
(ii) (iii) (iv) (i)
Solution
- Cristae are infoldings in mitochondria.
- Thylakoids are flattened membranous sacs in the stroma of plastids.
- Centromere is the primary constriction in a chromosome.
- Cisternae are disc-shaped sacs in the Golgi apparatus.
(iv) (i) (ii) (iii)
(i) (iv) (iii) (ii)
(ii) (i) (iv) (iii)
(iv) (iii) (i) (ii)
Solution
- Protein: Peptide bonds link amino acids.
- Unsaturated fatty acid: C = C double bonds are characteristic.
- Nucleic acid: Phosphodiester bonds connect nucleotides.
- Polysaccharide: Glycosidic bonds link monosaccharides.
Endoplasmic reticulum, Mitochondria, Ribosomes and Lysosomes
Endoplasmic reticulum, Golgi complex, Lysosomes and Vacuoles
Golgi complex, Mitochondria, Ribosomes and Lysosomes
Golgi complex, Endoplasmic reticulum, Mitochondria and Lysosomes
Solution
The endomembrane system includes the endoplasmic reticulum, Golgi complex, lysosomes, and vacuoles. These organelles are interconnected and involved in the synthesis, processing, and transport of cellular materials, as described in NCERT XI chapter Cell: The Unit of Life, so option (b) is correct.
Histones are organized to form a unit of 8 molecules.
The pH of histones is slightly acidic.
Histones are rich in amino acids - Lysine and Arginine.
Histones carry positive charge in the side chain.
Solution
Histones are basic proteins with a pH above 7, not acidic. They are rich in positively charged amino acids like Lysine and Arginine, which help in DNA binding. NCERT XI chapter Cell The Unit of Life describes histones as basic proteins, so option (b) is incorrect.
(a) and (b) only
(c) and (d) only
(b) and (c) only
(b) and (e) only
Solution
Lecithin is indeed a phospholipid, and trihydroxy propane is the chemical name for glycerol. However, palmitic acid has 16 carbon atoms, not 20, and arachidonic acid has 20 carbon atoms, not 16. Therefore, the correct statements are (b) and (c), so option (c) is correct.
(b), (d), (e) Only
(a), (c), (d) Only
(b), (e) Only
(a), (c), (e) Only
Solution
Heterochromatin is transcriptionally inactive. A typical nucleosome contains 200 bp of DNA helix. Euchromatin is the loosely packed chromatin region. The negatively charged DNA is wrapped around the positively charged histone octamer to form a structure called nucleosome. Histones are rich in basic amino acid residues lysine and arginine. - 46 - NEET (UG)-2022 (Code-Q1)
(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
(a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
(a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
Solution
In metacentric chromosome, centromere is in the middle of the chromosomes. Acrocentric chromosome has centromere close to the end of the chromosome. In submetacentric chromosome, centromere is slightly away from the middle of the chromosome. Telocentric chromosome has terminal centromere. - 50 - NEET (UG)-2022 (Code-Q1)
(a), (b) and (c) only
(a), (d) and (e) only
(c), (d) and (e) only
(a), (b) and (d) only
Solution
Option (3) is the correct answer because statements (c), (d) and (e) are correct as oils have lower melting point and hence remain oil in winters. Lipids are generally insoluble in water but soluble in some organic solvents. Option (1), (2) and (4) are incorrect because statements (a) and (b) are incorrect. Lecithin is a type of phospholipid found in plasma membrane. Saturated fatty acids are without double bond . - 51 - NEET (UG)-2022 (Code-Q1)
RER has ribosomes attached to ER
SER is devoid of ribosomes
In prokaryotes only RER are present
SER are the sites for lipid synthesis
Solution
In prokaryotes, ER is absent be it RER or SER.
Active Transport
Osmosis
Facilitated Diffusion
Passive Transport
Solution
Movement and accumulation of ions against their concentration gradient requires energy and is an example of active transport. NCERT XI chapter Cell: The Unit of Life explains that active transport involves the use of ATP to move ions or molecules against their concentration gradient, so option (a) is correct.
It breakes down when iodine reacts with it.
It is a disaccharide.
It is a helical molecule.
It does not contain complex helices and hence cannot hold iodine molecules.
Solution
Cellulose does not form a blue colour with iodine because it lacks the complex helical structure found in starch, which is necessary to trap iodine molecules. NCERT XI chapter Cell: The Unit of Life explains that the helical structure of starch is responsible for the blue colour with iodine, so option (d) is correct.
A is false but R is true.
Both A and R are true and R is the correct explanation of A.
Both A and R are true but R is NOT the correct explanation of A.
A is true but R is false.
Solution
Both Assertion A and Reason R are true, and R correctly explains A. ATP is indeed used in glycolysis at the steps where glucose is converted to glucose-6-phosphate and fructose-6-phosphate to fructose-1-6-diphosphate, as described in NCERT XI chapter Cell: The Unit of Life. Therefore, option (b) is correct.
Prophase
Metaphase
Anaphase
Telophase
Solution
Spindle fibers attach to kinetochores of chromosome in metaphase stage.
Linear, double stranded
Circular, double stranded
Linear, single stranded
Circular, single stranded
Solution
The DNA present in chloroplast is circular double stranded. - 61 - NEET (UG)-2024 (Code-Q1)
A-IV, B-III, C-II, D-I
A-IV, B-II, C-III, D-I
A-II, B-IV, C-I, D-III
A-II, B-I, C-IV, D-III
Solution
• Axoneme is seen in cilia and flagella • Centriole shows cartwheel appearance • Crista is found in mitochondria • Satellite is present in chromosomes
Both Statement I and Statement II are correct.
Both Statement I and Statement II are incorrect.
Statement I is correct but Statement Il is incorrect.
Statement I is incorrect but Statement Il is correct.
Solution
Both mitochondria and chloroplasts are double membrane bound cell organelles. Transport of ions occurs across the inner membrane of mitochondria. The inner membrane of chloroplast is impermeable to ions and metabolites. Therefore, it is said that inner membrane of mitochondria is relatively more permeable to that of chloroplast.
A, B, C are true
A, B, D are true
A, B, E are true
B, D, E are true
Solution
The eukaryotic ribosomes are 80S and prokaryotic ribosomes are 70S type.
Each ribosome has two sub-units.
The two sub-units of 80S ribosome are 60S and 40S while that of 70S are 50S and 30S.
A-I, B-II, C-III, D-IV
A-II, B-I, C-IV, D-III
A-IV, B-II, C-III, D-I
A-II, B-III, C-I, D-IV
Solution
Centromere - Helps in cell division
Cilium - Helps in cell movement
Cristae - Finger like structures of mitochondria
Cell membrane - Is a phospholipid bilayer
Mesosome
Chromatophores
Cristae
Endoplasmic Reticulum
Solution
A mesosome is a specialized membranous structure in prokaryotic cells that helps in cell wall formation, DNA replication, and respiration. NCERT XI chapter Cell: The Unit of Life describes mesosomes as invaginations of the plasma membrane, so option (a) is correct.
Lysine & Arginine
Leucine & Lysine
Phenylalanine & Leucine
Phenylalanine & Arginine
Solution
Sol. In eukaryotes, packaging of DNA is much more complex. There is a set of positively charged, basic proteins called histones.
Histones are organised to form a unit of light molecules called histone octamer.
They are rich in the basic amino acid residues lysine and arginine.
Cofactor
Coenzyme
Apoenzyme
Prosthetic group
Solution
There are number of cases in which non-protein constituents called co-factors are bound to the enzyme to make the enzyme catalytically active.
In these instances, the protein portion of the enzymes is called the apoenzyme.
Three kinds of co-factors are identified prosthetic groups, co-enzymes and metal ions. Prosthetic groups are organic compounds and they are tightly bound with apoenzyme. Co-enzymes are also organic compounds but their association with apoenzyme is only transient.
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